2^x+2 = 16³

2^x+2 = 2¹²

=> x+2 = 12

x = 12 - 2

x = 10

3 + 2^x-1 = 24 - [4² - (2² - 1)]

3 + 2^x-1 = 24 - [16 - (4 - 1)]

3 + 2^x-1 = 24 - [16 - 3]

3 + 2^x-1 = 24 - 13

3 + 2^x-1 = 11

2^x-1 = 11 - 3

2^x-1 = 8

2^x-1 = 2³

=> x-1 = 3

x = 3 + 1

x = 4

2^x+2=16³

2^x+2=4096

\(\Rightarrow\) 2^x+2=2¹²

4.

\(x+\frac{7}{2}+x=\frac{97}{4}\)

\(2x=\frac{97}{4}-\frac{14}{4}\)

\(2x=\frac{83}{4}\)

\(x=\frac{83}{8}\)

Học tốt~

 \(2x+\frac{7}{2}=\frac{97}{4}\)

\(2x=\frac{83}{4}\)

=> x = \(\frac{83}{8}\)

                         \(x+3\frac{1}{2}+x=24\frac{1}{4}\)

                        \(x+\frac{7}{2}+x=\frac{97}{4}\)

                       \(2x=\frac{97}{4}-\frac{7}{2}\)

                      \(2x=\frac{97}{4}-\frac{14}{4}\)

                      \(2x=\frac{83}{4}\)

                       \(x=\frac{83}{4}:2=\frac{83}{8}\)

                 Vậy \(x=\frac{83}{8}\)

               Ủng hộ mk nha !!! ^_^

Ta có : 

\(x+3\frac{1}{2}+x=24\frac{1}{4}\)

\(\Leftrightarrow x+x+\frac{7}{2}=\frac{97}{4}\)

\(\Leftrightarrow2x+\frac{14}{4}=\frac{97}{4}\)

\(\Leftrightarrow2x=\frac{83}{4}\)

\(\Leftrightarrow x=\frac{83}{8}\)

Vậy  \(x=\frac{83}{8}\)

\(x+3\frac{1}{2}+x=24\frac{1}{4}\)

        \(2x+\frac{7}{2}=\frac{97}{4}\)

        2x         \(=\frac{97}{4}-\frac{7}{2}\)

        2x         \(=\frac{83}{4}\)

         x          = \(\frac{83}{8}\)

1)

\(\frac{3}{4}.x+\frac{x}{5}=\frac{1}{6}\)

\(x.\left(\frac{3}{4}+\frac{1}{5}\right)=\frac{1}{6}\)

\(x.\frac{19}{20}=\frac{1}{6}\)

\(x=\frac{1}{6}:\frac{19}{20}\)

\(x=\frac{10}{57}\)

2) 

\(x+3\frac{1}{2}+x=24\frac{1}{4}\)

\(2x+3\frac{1}{2}=24\frac{1}{4}\)

\(2x=24\frac{1}{4}-3\frac{1}{2}\)

\(2x=\frac{83}{4}\)

\(x=\frac{83}{4}:2\)

\(x=\frac{83}{8}\)

a , \(\left(\dfrac{-2}{3}+1\dfrac{1}{4}-\dfrac{1}{6}\right):\dfrac{-24}{10}\)

=\(\left(\dfrac{-2}{3}+\dfrac{5}{4}-\dfrac{1}{6}\right):\dfrac{-12}{5}\)

=\(\left(\dfrac{-8}{12}+\dfrac{15}{12}-\dfrac{2}{12}\right)\cdot\dfrac{-5}{12}\)

=\(\dfrac{5}{12}\cdot\dfrac{-5}{12}=\dfrac{-25}{144}\)

b , \(\dfrac{13}{15}\cdot0,25\cdot3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right)1\dfrac{23}{24}\)

=\(\dfrac{13}{15}\cdot\dfrac{1}{4}\cdot3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right)\cdot\dfrac{57}{24}\)

=\(\dfrac{13}{20}-\dfrac{47}{60}\cdot\dfrac{57}{24}\)

=\(\dfrac{13}{20}-\dfrac{893}{480}=\dfrac{312}{480}-\dfrac{893}{480}=\dfrac{-581}{480}\)

c , \(\left(\dfrac{12}{32}+\dfrac{5}{-20}-\dfrac{10}{24}\right):\dfrac{2}{3}\)

=\(\left(\dfrac{180}{480}-\dfrac{120}{480}-\dfrac{200}{480}\right)\cdot\dfrac{3}{2}\)

= \(\dfrac{-7}{24}\cdot\dfrac{3}{2}=\dfrac{-7}{16}\)

d , \(4\dfrac{1}{2}:\left(2,5-3\dfrac{3}{4}\right)+\left(-\dfrac{1}{2}\right)\)

=\(\dfrac{9}{2}:\left(\dfrac{5}{2}-\dfrac{15}{4}\right)-\dfrac{1}{2}\)

=\(\dfrac{9}{2}:\dfrac{-5}{4}-\dfrac{1}{2}=\dfrac{9}{2}\cdot\dfrac{-4}{5}-\dfrac{1}{2}=\dfrac{-18}{5}-\dfrac{1}{2}=\dfrac{-41}{10}\)

e , \(\dfrac{-5}{2}:\left(\dfrac{3}{4}-\dfrac{1}{2}\right)=\dfrac{-5}{2}\left(\dfrac{3}{4}-\dfrac{2}{4}\right)\)

=\(\dfrac{-5}{2}:\dfrac{1}{4}=\dfrac{-5}{2}\cdot4=-10\)

\(a,\frac{4-x}{-2}=\frac{8}{x-4}\left(x\ne4\right)\)

\(\Leftrightarrow\frac{x-4}{2}=\frac{8}{x-4}\)

\(\Leftrightarrow\left(x-4\right)^2=16\)

\(\Leftrightarrow\orbr{\begin{cases}x-4=16\\x-4=-16\end{cases}\Leftrightarrow\orbr{\begin{cases}x=20\\x=-12\end{cases}}}\)(tmđk)

b) \(\frac{3}{x-1}=\frac{x}{24}\left(x\ne1\right)\)

<=> x(x-1)=72

Vì x và x-1 là 2 số liên tiếp  => x(x-1)=8.9

=> x=8 (tmđk)

a, ĐKXĐ \(x-4\ne0\Leftrightarrow x\ne4\)

 \(\frac{4-x}{-2}=\frac{8}{x-4}\Leftrightarrow-\frac{4-x}{2}=\frac{8}{x-4}\Leftrightarrow x-4=\frac{16}{x-4}\Leftrightarrow\left(x-4\right)^2=16\)

\(\Leftrightarrow\orbr{\begin{cases}x-4=\sqrt{16}=4\\x-4=\sqrt{16}=-4\end{cases}}\)Theo ĐKXĐ => x = -4

b, ĐKXĐ \(x-1\ne0\Leftrightarrow x\ne1\)

 \(\frac{3}{x-1}=\frac{x}{24}\Leftrightarrow72=x\left(x-1\right)\Leftrightarrow72=x^2-x\Leftrightarrow x^2-x-72=0\Leftrightarrow\left(x-9\right)\left(x+8\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)Theo ĐKXĐ : x (tm) 

lớp 6 học căn đâu

dễ mà bạn đây là bài cơ bản lớp 6 dấy

 câu a nhé bạn bạn nếu ko làm kiểu khó thì đổi về phaan số bình thường nà sau đó tính trong ngoặc trước rồi tính xoong bỏ dấu ngoặc nhưng ko đổi dấu né thế lad đc tương tự như các câu dưới
 

a)\(8\frac{2}{3}:2\frac{1}{6}-2\frac{27}{51}=\frac{26}{3}.\frac{6}{13}-\frac{43}{17}=4-\frac{43}{17}=\frac{25}{17}\)

b)\(\frac{27}{20}.\frac{15}{4}+\frac{19}{8}=\frac{119}{16}\)

c)\(\left(\frac{1}{12}+\frac{5}{6}\right)+\left(\frac{13}{35}+\frac{23}{35}\right)=\frac{11}{12}+\frac{36}{35}=\frac{817}{420}\)

d)\(\frac{24}{37}.\left(\frac{13}{18}+\frac{2}{9}+\frac{1}{18}\right)=\frac{24}{37}.1=\frac{24}{37}\)