Tính nhanh:
6+25+17+49+67+59+1+356+\frac25+\frac17+\frac49+\frac67+\frac59+1+\frac356+52+71+94+76+95+1+53
Đáp số:
Tính nhanh.
Tính bằng cách thuận tiện.
27:59×59:27+2025\frac27:\frac59\times\frac59:\frac27+202572:95×95:72+2025
Đáp số: .
A = 13+19+127+181+1243+1729\frac13+\frac19+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}+\frac{1}{729}31+91+271+811+2431+7291
B=1+54+58+516+532+564B=1+\frac54+\frac58+\frac{5}{16}+\frac{5}{32}+\frac{5}{64}B=1+45+85+165+325+645
21×3+23×5+25×7+…+299×101\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+\ldots+\frac{2}{99\times101}1×32+3×52+5×72+…+99×1012
12+16+112+120+130+⋯+1110\frac12+\frac16+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\cdots+\frac{1}{110}21+61+121+201+301+⋯+1101
Cho tổng: A=43×7+47×11+411×15+…=140429A=\frac{4}{3\times7}+\frac{4}{7\times11}+\frac{4}{11\times15}+\ldots=\frac{140}{429}A=3×74+7×114+11×154+…=429140
Tìm số hạng cuối cùng của A?
Tổng A có bao nhiêu số hạng?
56+1112+1920+2930+4142+5556+7172+8990\frac56+\frac{11}{12}+\frac{19}{20}+\frac{29}{30}+\frac{41}{42}+\frac{55}{56}+\frac{71}{72}+\frac{89}{90}65+1211+2019+3029+4241+5655+7271+9089
(1−34)×(1−37)×(1−310)×(1−313)×(1−316)×(1−319)\left(1-\frac34\right)\times\left(1-\frac37\right)\times\left(1-\frac{3}{10}\right)\times\left(1-\frac{3}{13}\right)\times\left(1-\frac{3}{16}\right)\times\left(1-\frac{3}{19}\right)(1−43)×(1−73)×(1−103)×(1−133)×(1−163)×(1−193)
(1−12)×(1−13)×(1−14)×(1−15)×(1−16)×(1−17)\left(1-\frac12\right)\times\left(1-\frac13\right)\times\left(1-\frac14\right)\times\left(1-\frac15\right)\times\left(1-\frac16\right)\times\left(1-\frac17\right)(1−21)×(1−31)×(1−41)×(1−51)×(1−61)×(1−71)
13131515×165165143143×424242151515\frac{1313}{1515}\times\frac{165165}{143143}\times\frac{424242}{151515}15151313×143143165165×151515424242
1996×1995−9961000+1996×1994\frac{1996\times1995-996}{1000+1996\times1994}1000+1996×19941996×1995−996 =
M=3500+8500+13500+18500+…+198500M=\frac{3}{500}+\frac{8}{500}+\frac{13}{500}+\frac{18}{500}+\ldots+\frac{198}{500}M=5003+5008+50013+50018+…+500198
A=29+219+212959+519+5129+311+331+3131511+531+5131A=\frac{\frac29+\frac{2}{19}+\frac{2}{129}}{\frac59+\frac{5}{19}+\frac{5}{129}}+\frac{\frac{3}{11}+\frac{3}{31}+\frac{3}{131}}{\frac{5}{11}+\frac{5}{31}+\frac{5}{131}}A=95+195+129592+192+1292+115+315+1315113+313+1313
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