Lời giải:
\(\frac{2022\times 2023-3}{2023\times 2021+2020}=\frac{2023\times (2021+1)-3}{2023\times 2021+2020} \\ =\frac{2023\times 2021+2023-3}{2023\times 2021+2020}=\frac{2023\times 2021+2020}{2023\times 2021+2020}=1\)

yynbjkgyg

x= 2002/3000

ko bt đúng ko mong bn nhắc nhở

4

4

Sửa đề: \(\frac{2022\times2023-3}{2023\times2021+2020}\)

\(=\frac{2023\times2021+2023-3}{2023\times2021+2020}\)

\(=\frac{2023\times2021+2020}{2023\times2021+2020}\)

=1

2021 x 2021 - 2019 x 2023 

= (2019 +2) x ( 2023 -2) - 2019 x 2023

= 2019 x 2023 - 2 x 2019 + 2 x 2023 - 4 - 2019 x 2023

= ( 2019 x 2023 - 2019 x 2023) + 2 x ( 2023 - 2019) - 4

= 0 + 2 x 4 - 4

= 8 - 4

 = 4

2021 x 2021 - 2019 x 2023 

= (2019 +2) x ( 2023 -2) - 2019 x 2023

= 2019 x 2023 - 2 x 2019 + 2 x 2023 - 4 - 2019 x 2023

= ( 2019 x 2023 - 2019 x 2023) + 2 x ( 2023 - 2019) - 4

= 0 + 2 x 4 - 4

= 8 - 4

 = 4

=2023phần2053345

\(\frac{2022\times2023-2020\times2023}{2022\times2023+2024\times7+2016}\)

\(=\frac{2023\times\left(2022-2020\right)}{2022\times2023+7\times\left(2023+1\right)+2016}\)

\(=\frac{2023\times2}{2023\times2022+7\times2023+7+2016}=\frac{2023\times2}{2023\times\left(2022+7+1\right)}=\frac{2}{2022+8}\)

\(=\frac{2}{2030}=\frac{1}{1015}\)

2030 × 4 +2023 × 2 + 3 × 2023

 =8120 + 4046 + 6069

=18235

= 4x2023+2023x2+2023 x1 + 3x2023
=2023x (4+2+3+1)
= 2023 x 10
= 20230
cảm ơn bạn đã đọc!

kết quả là 1022 nhé bạn

4,3 \(\times\) y + y + 4,7 \(\times\) y = 2023

4,3 \(\times\) y + y \(\times\) 1 +  4,7 \(\times\) y = 2023

y \(\times\) ( 4,3 + 1 + 4,7) = 2023

y \(\times\) 10 = 2023

y = 2023 : 10

y = 202,3

4,3 $\times$ y + y + 4,7 $\times$ y = 2023

4,3 $\times$ y + y $\times$ 1 +  4,7 $\times$ y = 2023

y $\times$ ( 4,3 + 1 + 4,7) = 2023

y $\times$ 10 = 2023

y = 2023 : 10

y = 202,3

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