Ta có:
\(37 - 5 \left(\right. x + 9 \left.\right) = \mid - 17 \mid\)

👉 Vì \(\mid - 17 \mid = 17\)

⇒ \(37 - 5 \left(\right. x + 9 \left.\right) = 17\)

\(37 - 5 x - 45 = 17\) \(- 5 x - 8 = 17\) \(- 5 x = 25 \Rightarrow x = - 5\)

✅ Đáp án: x = -5

b)

\(- 2 < \mid x + 2 \mid < 2\)

👉 Vì \(\mid x + 2 \mid \geq 0\) nên điều kiện \(- 2 < \mid x + 2 \mid\) luôn đúng

⇒ chỉ cần:

\(\mid x + 2 \mid < 2\) \(- 2 < x + 2 < 2\) \(- 4 < x < 0\)

✅ Đáp án: \(- 4 < x < 0\)

c)

\(- 7 \mid x - 2013 \mid + 20120 = \mid + 1 \mid\)

👉 \(\mid + 1 \mid = 1\)

⇒

\(- 7 \mid x - 2013 \mid + 20120 = 1\) \(- 7 \mid x - 2013 \mid = 1 - 20120 = - 20119\) \(\mid x - 2013 \mid = \frac{20119}{7} = 2874.142857...\)

⇒

\(x - 2013 = \pm \frac{20119}{7}\) \(x = 2013 \pm \frac{20119}{7}\)

👉 Có 2 nghiệm:

• \(x = 2013 + \frac{20119}{7}\)
• \(x = 2013 - \frac{20119}{7}\)

(= khoảng 4887.14 và -861.14)

d)

\(21 + \left(\right. x - 10 \left.\right) = - 19\)

\(21 + x - 10 = - 19\) \(x + 11 = - 19\) \(x = - 30\)

✅ Đáp án: x = -30

✅ Tóm lại:

• a) \(x = - 5\)
• b) \(- 4 < x < 0\)
• c) \(x = 2013 \pm \frac{20119}{7}\)
• d) \(x = - 30\)

e,

\(2^x-15=17\\ 2^x=17+15\\ 2^x=32\\ 2^x=2^5\\ x=5\)

Vậy \(x=5\)

d,

\(\left(x-1\right)^5-\left(x-1\right)^2=0\\ \left(x-1\right)^2\cdot\left[\left(x-1\right)^3-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(x-1\right)^2=0\\\left(x-1\right)^3-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^3=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\\left(x-1\right)^3=1^3\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=2\end{matrix}\right.\)

Vậy \(x=1\) hoặc \(x=2\)

mấy câu còn lại coi lại đề

Vay minh cam on ban nha!

x=20 nha bạn

\(\frac{-1}{2}\)\(-\left(\frac{3}{2}+x\right)=-22\)

\(\frac{-1}{2}\)\(-\frac{3}{2}\)\(-x=-22\)

\(-\left(\frac{1}{2}+\frac{3}{2}\right)-x=-22\)

\(-2-x=-22\)

\(x=-2-\left(-22\right)\)

\(x=20\)

không đúng thì thôi bạn đừng k sai nha!

a/ \(\left|5x+\frac{3}{4}\right|-\frac{5}{4}=2\)

\(\left|5x+\frac{3}{4}\right|=\frac{13}{4}\)

1. / \(5x+\frac{3}{4}=\frac{13}{4}\)
   \(5x=\frac{5}{2}\)
   \(x=\frac{1}{2}\)
2. / \(5x+\frac{3}{4}=-\frac{13}{4}\)
   \(5x=-4\)
   \(x=-\frac{4}{5}\)

\(\Rightarrow x=\left\{\frac{1}{2};-\frac{4}{5}\right\}\)

b/\(\frac{3}{2}-\left|\frac{1}{2}x+1\right|=\frac{1}{4}\)

\(\left|\frac{1}{2}x+1\right|=\frac{5}{4}\)

1/\(\frac{1}{2}x+1=\frac{5}{4}\)
\(\frac{1}{2}x=\frac{1}{4}\)
\(x=\frac{1}{2}\)

2/\(\frac{1}{2}x+1=-\frac{5}{4}\)

\(\frac{1}{2}x=-\frac{9}{4}\)

\(x=-\frac{9}{2}\)​

\(\Rightarrow x=\left\{\frac{1}{2};-\frac{9}{2}\right\}\)

nếu p=5 thì các số kia là snt
nếu p=5k+1 thì p+14=5k+15  ko là số nt
nếu p=5k+2 thì....                 ko là số nt
nếu p=5k+3 thì....                 ko là số nt
nếu p=5k+4 thì....                 ko là số nt
vậy p=5 thỏa mãn y/c đề bài

a) \(3x-\frac{3}{2}-5x+\frac{10}{3}=1\)

\(3x-5x=1+\frac{3}{2}-\frac{10}{3}\)

\(-2x=-\frac{5}{6}\)

\(x=\frac{5}{12}\)

b) \(\left|x-1\right|=5-x\)

Th1:

\(x-1=5-x\)

\(x+x=5+1\)

\(2x=6\)

\(x=3\)

Th2:

\(-\left(x-1\right)=5-x\)

\(x+1=5-x\)

\(x+x=5-1\)

\(2x=4\)

\(x=2\)

Vậy \(x=3\)và \(x=2\)

a) 3x - 5x = 1 + 3/2 - 10/3

-2x = -5/6

x = -5/6 : ( - 2 )

x = 5/12

b)  |x-1|= 5-x

Nếu x \(\ge\)1 \(\Rightarrow\)x - 1 \(\ge\)0 \(\Rightarrow\)x - 1 = 5 - x.

2x = 6

x = 3.

Nếu x < 1 \(\Rightarrow\)x - 1 < 0 \(\Rightarrow\)Ix-1I = 1 - x

\(\Rightarrow\)1 - x = 5 - x \(\Rightarrow\)vô lý.

Vậy x = 3

5² . x + 4³ . x - 2² . 3 . x = 10² - 5² 

25 . x + 64 . x - 12 . x = 100 - 25

x . ( 25 + 64 - 12 ) = 75

x . 77 = 75

x = \(\frac{75}{77}\)

\(5^2.x+4^3.x-2^2.3.x=10^2-5^2\)

\(\Leftrightarrow x\left(5^2+4^3-2^2.3\right)=10^2-5^2\)

\(\Leftrightarrow x.77=\left(10-5\right)\left(10+5\right)\)

\(\Leftrightarrow x.77=5.15\)

\(\Leftrightarrow x.77=75\)

\(\Rightarrow x=\frac{75}{77}\)

a)ab=3ab

=>3ab=1

=>ab=1

mà ab=1 thì a=1;b=1

do đó b chia hết cho a

b)theo phần a thì ab=1