\(a.97-7\left(x-8\right)=3\cdot2^4\)

\(97-7\left(x-8\right)=48\)

\(7\left(x-8\right)=97-48\)

\(7\left(x-8\right)=49\)

\(x-8=49:7=7\)

\(x=7+8=15\)

\(b.5x^2-74=51\)

\(5x^2=51+74=125\)

\(x^2=125:5=25\)

\(\Rightarrow x=\pm5\)

\(c.3x+2-3x=216\)

\(0x=214\)

⇒ \(x\in\) rỗng

\(5\left(3x-4\right)^3=40\)

\(\left(3x-4\right)^3=40:5=8\)

⇒ 3x - 4 = 2

⇒ 3x = 2 + 4 = 6

⇒ x = 6 : 3 = 2

a.97−7(x−8)=3⋅24

\(97 - 7 \left(\right. x - 8 \left.\right) = 48\)

\(7 \left(\right. x - 8 \left.\right) = 97 - 48\)

\(7 \left(\right. x - 8 \left.\right) = 49\)

\(x - 8 = 49 : 7 = 7\)

\(x = 7 + 8 = 15\)

\(b . 5 x^{2} - 74 = 51\)

\(5 x^{2} = 51 + 74 = 125\)

\(x^{2} = 125 : 5 = 25\)

\(\Rightarrow x = \pm 5\)

\(c . 3 x + 2 - 3 x = 216\)

\(0 x = 214\)

⇒ \(x \in\) rỗng

\(5 \left(\left(\right. 3 x - 4 \left.\right)\right)^{3} = 40\)

\(\left(\left(\right. 3 x - 4 \left.\right)\right)^{3} = 40 : 5 = 8\)

⇒ 3x - 4 = 2

⇒ 3x = 2 + 4 = 6

⇒ x = 6 : 3 = 2

A=7 B=1 OR =0 C=2 D=4.5.6

a: \(2^{x}\cdot4=128\)

=>\(2^{x}=\frac{128}{4}=32=2^5\)

=>x=5

b: \(x^{15}=x\)

=>\(x^{15}-x=0\)

=>\(x\left(x^{14}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{14}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{14}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

c: \(\left(2x+1\right)^3=125\)

=>\(\left(2x+1\right)^3=5^3\)

=>2x+1=5

=>2x=5-1=4

=>\(x=\frac42=2\)

d: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-5-1\right)\left(x-5+1\right)=0\)

=>\(\left(x-5\right)^4\cdot\left(x-6\right)\left(x-4\right)=0\)

=>\(\left[\begin{array}{l}x-5=0\\ x-6=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=6\\ x=4\end{array}\right.\)

\(a,70-5\times\left(x-3\right)=45\)

\(5\times\left(x-3\right)=70-45\)

\(5\times\left(x-3\right)=25\)

\(x-3=25:5\)

x - 3 = 5

x = 5 + 3 = 8

vậy x = 8

\(b,12+\left(5+x\right)=20\)

12 + 5 + x = 20

17 + x = 20

x = 20 - 17 = 3

vậy x = 3

c, 130 - (100 + x) = 25

130 - 100 - x = 25

30 - x = 25

x = 30 - 25 = 5

vậy x = 5

\(g,10+2\times x=4^5:4^3\)

\(10+2\times x=4^2\)

\(10+2\times x=16\)

\(2\times x=16-10\)

\(2\times x=6\)

x = 6 : 2 = 3

vậy x = 3

h, \(14\times x+54=82\)

\(14\times x=82-54\)

\(14\times x=28\)

\(x=28:14=2\)

vậy x = 2

\(k,15\times x-133=17\)

\(15\times x=17+133\)

\(15\times x=150\)

\(x=150:15=10\)

vậy x = 10

\(a,70-5\times\left(x-3\right)=45\)

\(5\times\left(x-3\right)=70-45\)

\(5\times\left(x-3\right)=25\)

\(x-3=25:5\)

x - 3 = 5

x = 5 + 3 = 8

vậy x = 8

\(b,12+\left(5+x\right)=20\)

12 + 5 + x = 20

17 + x = 20

x = 20 - 17 = 3

vậy x = 3

c, 130 - (100 + x) = 25

130 - 100 - x = 25

30 - x = 25

x = 30 - 25 = 5

vậy x = 5

\(g,10+2\times x=4^5:4^3\)

\(10+2\times x=4^2\)

\(10+2\times x=16\)

\(2\times x=16-10\)

\(2\times x=6\)

x = 6 : 2 = 3

vậy x = 3

h, \(14\times x+54=82\)

\(14\times x=82-54\)

\(14\times x=28\)

\(x=28:14=2\)

vậy x = 2

\(k,15\times x-133=17\)

\(15\times x=17+133\)

\(15\times x=150\)

\(x=150:15=10\)

vậy x = 10

các bạn làm ơn giúp mk với mk đang gấp lắm

đau có y

Ta có \(2^{x+2}-2^x=96\)

\(\Rightarrow2^x.\left(2^2-1\right)=96\)

\(\Rightarrow2^x.3=96\)

\(\Rightarrow2^x=32\)

\(\Rightarrow2^x=2^5\)

\(\Rightarrow x=5\)

b, Ta có \(5^x+5^{x+2}=650\)

\(\Rightarrow5^x.\left(1+5^2\right)=650\)

\(\Rightarrow5^x.26=650\)

\(\Rightarrow5^x=25\)

\(\Rightarrow5^x=5^2\)

\(\Rightarrow x=2\)

a:

2^x+2-2^x=96
=> 2^x.2²-2^x=99
=>2^x.4-2^x=96
=>2^x(4-1)=96
=>2^x.3=96
=>2^x=96:3=32=2^5
=>x=5

^a:

5^x+5^x+2=650
=>5^x+5^x.5²=650
=>5^x+5^x.25=650
=>5^x(1+25)=650
=>5^x=650:26=25
=>x=5
----HỌC TỐT NHA----

ai là được mình k nha 3 k một ngày luôn

a) không

b) nhỏ nhất \(\orbr{\begin{cases}x-5=160\Rightarrow x=165\\x-5=-160\Rightarrow x=-155\end{cases}}\)

c) Lớn nhất \(\orbr{\begin{cases}x-5=169\Rightarrow x=174\\x-5=-169\Rightarrow x=-164\end{cases}}\)