1.53x201=10653

2.

a)4 xX-15x4=6x15+X

<=>4x-60=90+x

<=>4x-x=60+90

<=>3x=150

<=>x=50

b(102+28-2x):20-5=1

<=>(130-2x):20=6

<=>130-2x=120

<=>2x=10

<=>x=5

c)1999x-x=1999+1997+1999

<=>1998x=5995

<=>\(x\approx3\)

d)105-5x=150:15

<=>105-5x=10

<=>5x=95

<=>x=19

e)(x+1)+(x+2)+(x+3)+...+(x+6)=78

<=>6x+21=78

<=>6x=57

<=>x=9,5

1) 53x201=53x200+53=10600+53=10653

2a)

4x-15x4=6x15+x

4x-60=90+x

4x-x=90+60

3x=150

x=50

b) x=5

c) x=3

d)x=19

e) x=9,5

(1-2+3-4+5-6+7-8+...+101-102+103) * x-120=2012

[ -1 + ( -1 ) ... ( -1 ) + 103] * x -120 = 2012

( -1 x 51 + 103 ) * x - 120 = 2012

( -51 +103) * x = 2012 + 120

52 * x =2132

x= 2132 : 52

x= 41

a) y x 4,9 : 10 = 12

    y x 49         = 12

    y                 = 12 : 49

    y                 =    tự tính

\(y\times4,9+y\div10=1,2\)

\(y\times4,9+y\times\dfrac{1}{10}=1,2\)

\(y\times4,9+y\times0,1=1,2\)

\(y\times\left(4,9+0,1\right)=1,2\)

\(y\times5=1,2\)

\(y=1,2\div5\)

\(y=0,24\)

a) \(85\times16+16\times15\)

\(=16\times\left(85+15\right)\)

\(=16\times100=1600\)

b) \(\left(\dfrac{3}{7}\times\dfrac{11}{15}+\dfrac{3}{7}\times\dfrac{4}{15}\right):\left(4+2\dfrac{6}{11}-\dfrac{6}{11}\right)\)

\(=\left[\dfrac{3}{7}\times\left(\dfrac{11}{15}+\dfrac{4}{15}\right)\right]:\left(4+\dfrac{28}{11}-\dfrac{6}{11}\right)\)

\(=\dfrac{3}{7}\times1:\left(4+2\right)\)

\(=\dfrac{3}{7}:6\)

\(=\dfrac{3}{7}\times\dfrac{1}{6}=\dfrac{3}{42}=\dfrac{1}{14}\)

c) \(x+\left(x+3\right)+\left(x+6\right)+...+\left(x+102\right)=1855\)

\(\Rightarrow35x+\left(3+6+...+102\right)=1855\)

\(\Rightarrow35x+\left(102+3\right)\times34:2=1855\)

\(\Rightarrow35x+1785=1855\)

\(\Rightarrow35x=1855-1785\)

\(\Rightarrow35x=70\)

\(\Rightarrow x=70:35\)

\(\Rightarrow x=2\)

Vậy...

\(#Tmiamm\)

a) 85 x 16 + 16 x 15

= 16 x (85 + 15)

= 16 x 100

= 1600.

a: \(\frac{52}{17}>\frac{51}{17}=3\)

\(3=\frac{121}{41}>\frac{120}{41}\)

Do đó: \(\frac{52}{17}>\frac{120}{41}\)

b: \(\frac34+\frac14:\left(\frac{7}{12}-\frac16\right)\)

\(=\frac34+\frac14:\left(\frac{7}{12}-\frac{2}{12}\right)\)

\(=\frac34+\frac14:\frac{5}{12}\)

\(=\frac34+\frac14\times\frac{12}{5}=\frac34+\frac35=\frac{15}{20}+\frac{12}{20}=\frac{27}{20}\)

c: \(372,463\cdot998+744,926\)

\(=372,463\cdot998+372,463\cdot2\)

\(=372,463\times\left(998+2\right)=372,463\times1000=372463\)

d: Số số hạng trong dãy số 2;4;6;...;100 là:

\(\left(100-2\right):2+1=98:2+1=49+1=50\) (số)

\(2-4+6-8+10-12+\cdots+98-100+102\)

\(=\left(2-4\right)+\left(6-8\right)+\cdots+\left(98-100\right)+102\)

=(-2)+(-2)+...+(-2)+102

\(=-2\cdot\frac{50}{2}+102=-50+102=52\)

e: (y+112)-113=79

=>y+112-113=79

=>y-1=79

=>y=79+1=80

f: \(\frac34-y=\frac12\)

=>\(y=\frac34-\frac12=\frac14\)

g: \(\left(\frac45-2\times y\right)+\frac16=\frac56\)

=>\(\frac45-2\times y=\frac56-\frac16=\frac46=\frac23\)

=>\(2\times y=\frac45-\frac23=\frac{12}{15}-\frac{10}{15}=\frac{2}{15}\)

=>\(y=\frac{2}{15}:2=\frac{1}{15}\)

h: (y+1)+(y+2)+...+(y+50)=1750

=>50y+(1+2+...+50)=1750

=>\(50y+50\times\frac{51}{2}=1750\)

=>50y+1275=1750

=>50y=1750-1275=475

=>\(y=\frac{475}{50}=9,5\)

a. \(x+\frac{x}{3}\cdot15=\frac{424}{4}+\frac{102}{6}\)

\(x+5x=106+17\)

\(x\left(1+5\right)=123\)

\(6x=123\)

\(x=\frac{123}{6}=\frac{41}{2}\)

b. \(100-x+\frac{5\cdot2}{2}-0=0\)

\(100-x+5=0\)

\(105-x=0\)

\(x=105-0=105\)