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\(x\times2+x\times0,5=10\)
\(\Rightarrow x\times\left(2+0,5\right)=10\)
\(\Rightarrow x\times2,5=10\)
\(\Rightarrow x=10\div2,5\)
\(\Rightarrow x=4\)
Vậy x = 4
\(\frac{4}{7}+\frac{3}{7}\div x=\frac{3}{2}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{3}{2}-\frac{4}{7}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{21}{14}-\frac{8}{14}\)
\(\Rightarrow\frac{3}{7}\div x=\frac{13}{14}\)
\(\Rightarrow x=\frac{3}{7}\div\frac{13}{14}\)
\(\Rightarrow x=\frac{3}{7}\cdot\frac{14}{13}=\frac{6}{13}\)
Vậy x = \(\frac{6}{13}\)
x.2+x.0,5=10
=> x= . (2+0,5)=10
=>x.2,5=10
=>x= 10:2,5
=>x=4
vậy x = 4
b)
\(\frac{4}{7}\)+\(\frac{3}{7}\):x=\(\frac{3}{2}\)
=> \(\frac{3}{7}\):x= \(\frac{3}{2}\):\(\frac{4}{7}\)
=> \(\frac{3}{7}\):x=\(\frac{13}{14}\)
=> \(\frac{3}{7}\):x=\(\frac{3}{7}\):\(\frac{14}{13}\)
=> x =\(\frac{6}{13}\)
vậy x =\(\frac{6}{13}\)
hok tốt
a, 7/5 : x + 3/2 = 16/3
7/5 : x = 16/3 - 3/2
7/5 : x = 23/6
x = 7/5 : 23/6
x = 42/115
b, x : 1/5 + 1/7 = 3/5 . 18/21
x : 1/5 + 1/7 = 18/35
x : 1/5 = 18/35 - 1/7
x : 1/5 = 13/35
x = 13/35 . 1/5
x = 13/175
c, x - 1 và 1/3 : 2 = 5/7
x - 4/3 : 2 = 5/7
x - 4/3 = 5/7 . 2
x - 4/3 = 10/7
x = 10/7 + 4/3
x = 58/21
d, x + 2 và 3/5 . 1/6 = 35/36
x + 13/5 . 1/6 = 35/36
x + 13/5 = 35/36 : 1/6
x + 13/5 = 35/6
x = 35/6 - 13/5
x = 97/30
e, ( x + 3/2 ) : 2 = 7/10 + 1/5
( x + 3/2 ) : 2 = 9/10
x + 3/2 = 9/10 . 2
x + 3/2 = 9/5
x = 9/5 - 3/2
x = 3/10
(x-1/2)*5/3=7/4-1/2
(x-1/2)*5/3=5/4
x-1/2=3/4
x = 5/4
(x+4/3)*7/4=5-7/6
(x+4/3)*7/4=23/6
x+4/3 = 46/21
x = 6/7
6/8=15/x
6*x=15*8
6*x=120
x = 20
\(\frac{6}{8}=\frac{15}{x}\)
\(\Rightarrow x=\left(15\cdot8\right):6\)
\(\Rightarrow x=20\)
\(x+\frac{15}{7}=\frac{9}{2}\)
\(x=\frac{9}{2}-\frac{15}{7}=\frac{33}{14}\)
\(x-\frac{3}{4}=\frac{7}{2}\)
\(x=\frac{7}{2}+\frac{3}{4}=\frac{17}{4}\)
\(x.\frac{7}{8}=\frac{12}{5}\)
\(x=\frac{12}{5}:\frac{7}{8}=\frac{96}{35}\)
\(\frac{5}{6}:x=\frac{4}{3}\)
\(x=\frac{5}{6}:\frac{4}{3}=\frac{5}{8}\)
- a) x=9/2-15/7=33/14
- b) x=7/2+3/4=17/4
- c) x=12/5:7/8=61/35
- d) x=5/6:4/3=5/8
- k nha
\(\frac{11}{9}-\frac67\)
\(=\frac{77}{63}-\frac{54}{63}=\frac{77-54}{63}=\frac{23}{63}\)
\(\frac{7}{10}-\frac25=\frac{7}{10}-\frac{4}{10}=\frac{7-4}{10}=\frac{3}{10}\)
\(\frac72-2=\frac72-\frac42=\frac{7-4}{2}=\frac32\)
\(\frac65\times\frac38=\frac{6\times3}{5\times8}=\frac{18}{40}=\frac{9}{20}\)
\(\frac25:\frac32=\frac25\times\frac23=\frac{2\times2}{5\times3}=\frac{4}{15}\)
\(5:\frac57=5\times\frac75=7\)
\(\frac73:4=\frac{7}{3\times4}=\frac{7}{12}\)
911−76
\(= \frac{77}{63} - \frac{54}{63} = \frac{77 - 54}{63} = \frac{23}{63}\)
\(\frac{7}{10} - \frac{2}{5} = \frac{7}{10} - \frac{4}{10} = \frac{7 - 4}{10} = \frac{3}{10}\)
\(\frac{7}{2} - 2 = \frac{7}{2} - \frac{4}{2} = \frac{7 - 4}{2} = \frac{3}{2}\)
\(\frac{6}{5} \times \frac{3}{8} = \frac{6 \times 3}{5 \times 8} = \frac{18}{40} = \frac{9}{20}\)
\(\frac{2}{5} : \frac{3}{2} = \frac{2}{5} \times \frac{2}{3} = \frac{2 \times 2}{5 \times 3} = \frac{4}{15}\)
\(5 : \frac{5}{7} = 5 \times \frac{7}{5} = 7\)
\(\frac{7}{3} : 4 = \frac{7}{3 \times 4} = \frac{7}{12}\)
b) \(\frac{1}{1000}+\frac{13}{1000}+\frac{25}{1000}+...+\frac{87}{1000}+\frac{99}{1000}\)
\(=\frac{1+13+25+...+85+97}{1000}=\frac{\left(97+1\right).\left[\left(97-1\right):12+1\right]:2}{1000}\)
\(=\frac{49.9}{1000}=\frac{441}{1000}.\) ( Đề bài sai nhé bạn tử số : 1; 13; 25; 37; 49 ; 61; 73; 85 ; 97. )
Câu c:B = (1999x1998 + 1998x1997)x(1+1/2: 1 1/2 - 11/3)
B = (1999x1998 + 1998x1997)x(1+1/2:3/2-4/3)
B = (1999x1998 +1998 x1997) x (1+1/2x2/3 - 4/3)
B = (1999 x 1998 + 1998 x 1997) x(1+1/3 - 4/3)
B = (1999 x 1998 + 1998 x 1997) x (4/3 - 4/3)
B = (1999 x 1998 + 1998 x 1997) x 0
B = 0
#)Trả lời :
\(a,\frac{2}{3}:\frac{5}{7}.\frac{5}{7}:\frac{2}{3}+1934\)
\(=\left(\frac{2}{3}:\frac{2}{3}\right).\left(\frac{5}{7}:\frac{5}{7}\right)+1934\)
\(=1.1+1934\)
\(=1935\)
#~Will~be~Pens~#
a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)

|x| - 3 = 7
|x| = 7 + 3
|x| = 10
⇒ x ∈ {10; -10}
Vậy x ∈ {10; -10}
(x)-3 = 7
x = 7+3
x = 10
Vậy x= 10.
|x|-3=7
=>|x|=3+7=10
=>\(\left[\begin{array}{l}x=10\\ x=-10\end{array}\right.\)
|x| - 3 = 7 |x| = 7 + 3 |x| = 10 ⇒ x = 10 hoặc -10 Vậy x = 10 hoặc - 10
10
mình chưa học cái này nên mình không hiểu lắm!
|x| - 3 = 7
|x| = 7 + 3
|x| = 10
=> x = 10 hoặc x = -10
Vậy x = 10 hoặc x = -10
|x| - 3 = 7
|x| = 7 + 3
|x| = 10
=> x = 10 hoặc -10