A. T = 1

B. T = 5

C. T = 2

D. T = 10

A.  $\left\{\begin{array}{l}x=\frac{12}{5}+7t\\ y=\frac{6}{5}-t\\ z=2+5t\end{array}\right.$

B. $\left\{\begin{array}{l}x=\frac{12}{5}+7t\\ y=\frac{6}{5}+t\\ z=2+5t\end{array}\right.$

C. $\left\{\begin{array}{l}x=\frac{12}{5}-7t\\ y=\frac{6}{5}-t\\ z=-2+5t\end{array}\right.$

D. $\left\{\begin{array}{l}x=-\frac{12}{5}+7t\\ y=\frac{6}{5}+t\\ z=2+t\end{array}\right.$

A.  $\frac{x-1}{1}=\frac{y-2}{-4}=\frac{z-3}{-5}$

B. $\left\{\begin{array}{l}x=1+t\\ y=2-4t\\ z=3-5t\end{array}\right.$ 

C.  $\left\{\begin{array}{l}x=1+t\\ y=-4+2t\\ z=-5+3t\end{array}\right.$

D. $\frac{x-1}{1}=\frac{y+4}{2}=\frac{z+5}{3}$

A. $2x-3y-6z+15=0$ 

B. $2x-3y-6z-15=0$

C. $2x-3y-5z-10=0$

D. $2x-3y-5z+10=0$

A.  $\stackrel{\to }{u}=\left(2;1;-1\right)$

B.  $\stackrel{\to }{u}=\left(1;1;0\right)$

C.  $\stackrel{\to }{u}=\left(1;-1;0\right)$

D.  $\stackrel{\to }{u}=\left(1;2;1\right)$

A.  $\stackrel{\to }{u_3}\left(2;1;-2\right)$

B.  $\stackrel{\to }{u_2}\left(1;-1;0\right)$

C.  $\stackrel{\to }{u_4}\left(0;1;-1\right)$

D.  $\stackrel{\to }{u_1}\left(1;2;1\right)$

A. $\stackrel{\to }{u}=\left(2;1;-1\right)$.

B. $\stackrel{\to }{u}=\left(1;1;0\right)$.

C. $\stackrel{\to }{u}=\left(1;-1;0\right)$.

D. $\stackrel{\to }{u}=\left(1;2;1\right)$.

A.  $\stackrel{\rightharpoonup }{{\text{u}}_{\text{d}}}=(1;-2;0)$

B.  $\stackrel{\rightharpoonup }{{\text{u}}_{\text{d}}}=(2;3;-1)$

C.  $\stackrel{\rightharpoonup }{{\text{u}}_{\text{d}}}=(-3;1;-2)$

D.  $\stackrel{\rightharpoonup }{{\text{u}}_{\text{d}}}=(3;1;2)$

A. (1; -2; 0)

B. (2; 3; -1)

C. (-3; 1; -2)

D. (3; 1; 2)