= (9/5 + 6/5) + 4/9 + 8/7 + 3/2 = 3 + (100/63 + 3/2) = 389/126 + 3 = 767/126          

a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)

\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)

b)\(5+\dfrac{3}{5}=\dfrac{25}{5}+\dfrac{3}{5}=\dfrac{28}{5};10-\dfrac{9}{16}=\dfrac{160}{16}-\dfrac{9}{16}=\dfrac{151}{16}\)

\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\left(\dfrac{8}{48}+\dfrac{6}{48}\right)=\dfrac{2}{3}-\dfrac{14}{48}=\dfrac{32}{48}-\dfrac{14}{48}=\dfrac{3}{8}\)

\(3+\frac{2}{5}-\frac{3}{4}\times\frac{4}{5}\)

\(=3+\frac{2}{5}-\frac{3}{4}\)

\(=\frac{3\times20+2\times4-3\times5}{20}\)

\(=\frac{60+8-15}{20}\)

\(=\frac{68-15}{20}\)

\(=\frac{53}{20}\)

\(5-\frac{7}{9}+\frac{2}{3}-\frac{5}{6}:\frac{4}{9}\)

\(=5-\frac{7}{9}+\frac{2}{3}-\frac{45}{24}\)

\(=\frac{5\times72-7\times8+2\times24-45\times3}{72}\)

\(=\frac{360-56+48-135}{72}\)

\(=\frac{217}{72}\)

\(a,\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}\)

Cách 1: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=1\times\frac{3}{7}=\frac{10}{7}\)

Cách 2: \(\left(\frac{6}{11}+\frac{5}{11}\right)\times\frac{3}{7}=\frac{6}{11}\times\frac{3}{7}+\frac{5}{11}\times\frac{3}{7}=\frac{18}{77}+\frac{15}{77}=\frac{33}{77}=\frac{3}{7}\)

\(b,\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}\)

Cách 1: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{7}{15}+\frac{2}{15}=\frac{9}{15}\)

Cách 2: \(\frac{3}{5}\times\frac{7}{9}+\frac{3}{5}\times\frac{2}{9}=\frac{3}{5}\times1=\frac{3}{5}\)

P/s: Ý B có vấn đề thì phải

\(a,\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{3}{7}\)

\(=\frac{11}{11}=1x\frac{3}{7}\)

\(=\frac{3}{7}\)

cach 2 

\(\frac{6}{11}x\frac{3}{7}+\frac{5}{11}x\frac{3}{7}\)

\(=\frac{18}{77}+\frac{15}{77}\)

\(=\frac{33}{77}=\frac{3}{7}\)

\(b,\frac{3}{5}x\frac{7}{9}+\frac{3}{5}x\frac{2}{9}\)

\(=\frac{21}{45}+\frac{6}{45}\)

\(=\frac{27}{45}=\frac{3}{5}\)

cách 2 : 

\(\frac{3}{5}x\left(\frac{7}{9}+\frac{2}{9}\right)\)

\(=\frac{3}{5}x\frac{9}{9}\)

\(=\frac{27}{45}=\frac{3}{5}\)

bằng  4/5 nha bạn

\(\frac{4}{5}\div\frac{9}{15}\times\frac{3}{5}\)

\(=\frac{4}{5}\times\frac{15}{9}\times\frac{3}{5}\)

\(=\frac{4}{5}\)

k mk nha

a ) -33/56

b )-17/63

c ) 18/5

a ) - 33/56

b ) - 17/63

c ) 18/5

Ta có:\(\frac{5}{9}.\frac{3}{5}:\frac{2}{9}\)

\(\Rightarrow\frac{5}{9}.\frac{3}{5}.\frac{9}{2}\)

\(=\frac{3}{2}\)

Chúc bạn hok tốt

Câu hỏi:

Tính :  ( Dấu ( . ) là dấu nhân nhé ! )

\(\frac{5}{9}.\frac{3}{5}:\frac{2}{9}\)

Trả lời :

\(\frac{5}{9}.\frac{3}{5}:\frac{2}{9}=\frac{5}{9}.\frac{3}{5}.\frac{9}{2}\)

                 \(=\frac{5.3.9}{9.5.2}=\frac{3}{2}.\)

a)\(\frac{2}{3}:\frac{4}{9}+\frac{1}{3}:\frac{4}{9}\)

=\(\frac{4}{9}:\left(\frac{2}{3}+\frac{1}{3}\right)\)

=\(\frac{4}{9}:1=\frac{4}{9}\)

b

a 9/4

b 49/40

c 36/35

d 144/441

công thúc nè
tính số số hạng : (số cuối -số đầu) / khoảng cách +1
tính tổng :(số cuối + số đầu)* số số hạng / 2
cho mình hỏi chút lopw 4 đã hc có nì rồi ah

a) 1 + 5 + 9 + 13 + ... + 393 + 397

= (1 + 397) x (\(\frac{397-1}{4}\) + 1) : 2

= 398 x \(\frac{397-1+4}{4}\) : 2

= (398 : 2) x \(\frac{397+3}{4}\)

= 199 x \(\frac{200}{4}\)

= 199 x 50 = 9950

a \(\frac{7}{6}\)

b \(\frac{5}{3}\)

\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)

\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)

\(=1+\frac{1}{6}\)

\(=\frac{7}{6}\)

Hok tốt!~