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bài 1b)
\(8\frac{1}{14}-6\frac37\)
C1:\(\frac{113}{14}-\frac{45}{7}\) =\(\frac{113}{14}-\frac{90}{14}=\frac{23}{14}\)
C2:\(8\frac{1}{14}-6\frac37=\left(8-6\right)+\left(\frac{1}{14}-\frac37\right)=2+\left(\frac{1}{14}-\frac{6}{14}\right)\)
\(=2+\frac{-5}{14}=\frac{28}{14}-\frac{5}{14}=\frac{23}{14}\)
bài 1 c)\(7-3\frac67\)
C1:\(\) \(7-3\frac67=7-\frac{27}{7}=\frac{49}{7}-\frac{27}{7}=\frac{22}{7}\)
C2:\(7-3\frac67=\left(7-3\right)-\frac67=4-\frac67=\frac{28}{7}-\frac67=\frac{22}{7}\)
a) \(\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
= \(\left(-\frac{3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
= \(0:\frac{3}{7}\)
= \(0\)
b) \(\frac{2}{8}:\left(\frac{2}{9}-\frac{1}{18}\right)+\frac{7}{8}:\left(\frac{1}{36}-\frac{5}{12}\right)\)
= \(\frac{1}{4}:\frac{1}{6}+\frac{7}{8}:\frac{-7}{18}\)
=\(\frac{1}{4}.6+\frac{7}{8}.\frac{-18}{7}\)
= \(\frac{3}{2}-\frac{3}{4}\)
= \(\frac{3}{4}\)
a) \(\dfrac{1}{3}+\dfrac{3}{8}-\dfrac{7}{12}\)
\(=\dfrac{17}{24}-\dfrac{7}{12}\)
\(=\dfrac{1}{8}\)
b) \(\dfrac{-3}{14}+\dfrac{5}{8}-\dfrac{1}{2}\)
\(=\dfrac{23}{56}-\dfrac{1}{2}\)
\(=\dfrac{-5}{56}\)
c) \(\dfrac{1}{4}-\dfrac{2}{3}-\dfrac{11}{18}\)
\(=\dfrac{-5}{12}-\dfrac{11}{18}\)
\(=\dfrac{-37}{36}\)
d) \(\dfrac{1}{4}+\dfrac{5}{12}-\dfrac{1}{13}-\dfrac{7}{8}\)
\(=\dfrac{2}{3}-\dfrac{1}{13}-\dfrac{7}{8}\)
\(=\dfrac{23}{39}-\dfrac{7}{8}\)
\(=\dfrac{-89}{312}\)
a) = (3.23)3.3-(2.3)4.25
= 33.(23)3.3-24.34.25
= 34.29-29.34
=0
S = (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + (9 - 10 - 11 + 12) + (13 - 14 - 15 + 16) + (17 - 18)
= 0 + 0 + 0 + 0 + (-1)
= -1
A = (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + ... + (2013 - 2014 - 2015 + 2016) + 2017
= 0 + 0 + ... + 0 + 2017
= 2017
S = (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) +...... + (13 - 14 - 15 + 16)+ 17 - 18
S = 17 - 18 = -2
A = (1 - 2 - 3 + 4) + (5 - 6 -7 + 8) + ..... + (2013 - 2014 - 2015 + 2016) + 2017
A = 2017
1 - 2 - 3 + 4 + 5- 6 - 7 + .... + 601 - 602 - 603 + 604
= (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + ... + (601 -602 - 603 + 604)
= 0 + 0 + ... + 0
= 0
a) \(3^{7} \cdot 27^{5} \cdot 81^{3}\)
\(3^{7} \cdot \left(\right. 3^{3} \left.\right)^{5} \cdot \left(\right. 3^{4} \left.\right)^{3} = 3^{7} \cdot 3^{15} \cdot 3^{12} = 3^{7 + 15 + 12} = 3^{34} .\)
b) \(100^{6} \cdot 1000^{5} \cdot 10 \textrm{ } 000^{3}\)
\(\left(\right. 10^{2} \left.\right)^{6} \cdot \left(\right. 10^{3} \left.\right)^{5} \cdot \left(\right. 10^{4} \left.\right)^{3} = 10^{12} \cdot 10^{15} \cdot 10^{12} = 10^{39} .\)
c) \(\frac{36^{5}}{18^{5}}\)
\(\left(\left(\right. \frac{36}{18} \left.\right)\right)^{5} = 2^{5} = 32.\)
d) \(24 \cdot 5^{2} + 5^{2} \cdot 5^{3}\)
\(= 24 \cdot 25 + 25 \cdot 125 = 600 + 3125 = 3725.\)
e) \(\frac{125^{4}}{5^{8}}\)
\(\left(\right. 5^{3} \left.\right)^{4} : 5^{8} = 5^{12} : 5^{8} = 5^{12 - 8} = 5^{4} = 625.\)
TÓM lại là a) \(3^{34}\)
b) \(10^{39}\)
c) \(32\)
d) \(3725\)
e) \(625\)
bạn muốn chép đáp án hay sem cách làm///??
a: \(3^7\cdot27^5\cdot81^3\)
\(=3^7\cdot\left(3^3\right)^5\cdot\left(3^4\right)^3\)
\(=3^7\cdot3^{15}\cdot3^{12}=3^{7+15+12}=3^{34}\)
b: \(100^6\cdot1000^5\cdot10000^3\)
\(=\left(10^2\right)^6\cdot\left(10^3\right)^5\cdot\left(10^4\right)^3\)
\(=10^{12}\cdot10^{15}\cdot10^{12}=10^{15+12+12}=10^{39}\)
c: \(36^5:18^5=\left(\frac{36}{18}\right)^5=2^5=32\)
d: \(24\cdot5^2+5^2\cdot5^3\)
\(=5^2\left(24+5^3\right)\)
\(=25\cdot\left(24+125\right)=25\cdot149=3725\)
e: \(125^4:5^8=\left(5^3\right)^4:5^8=5^{12}:5^8=5^{12-8}=5^4\)
