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$\textbf{A}$
$A=\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{(2^2\cdot3)^6+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{(125\cdot7)^3+5^9\cdot14^3}$
$=\dfrac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{12}\cdot3^6+2^{12}\cdot3^5}-\dfrac{5^{10}\cdot7^3-5^{10}\cdot7^4}{5^9\cdot7^3+2^3\cdot5^9\cdot7^3}$
$=\dfrac{2^{12}\cdot3^4(3-1)}{2^{12}\cdot3^5(3+1)}-\dfrac{5^{10}\cdot7^3(1-7)}{5^9\cdot7^3(1+8)}$
$=\dfrac{2}{12}-\dfrac{-30}{9}$
$=\dfrac16+\dfrac{10}{3}$
$=\boxed{\dfrac72}.$
$\textbf{B}$
$B=\dfrac{\left(-\dfrac12\right)^3-\left(\dfrac34\right)^3\cdot(-2)^2}{2\cdot(-1)^5+\left(\dfrac34\right)^2-\dfrac38}$
$=\dfrac{-\dfrac18-\dfrac{27}{64}\cdot4}{-2+\dfrac9{16}-\dfrac38}$
$=\dfrac{-\dfrac18-\dfrac{27}{16}}{-2+\dfrac3{16}}$
$=\dfrac{-\dfrac{29}{16}}{-\dfrac{29}{16}}$
$=\boxed{1}.$
a) \(\left(-\frac{5}{2}\right)^2:\left(-15\right)-\left(-0,45+\frac{3}{4}\right).\left(-1\frac{5}{9}\right)\)
= \(-\frac{25}{4}:\left(-15\right)-\left(\frac{9}{20}+\frac{15}{20}\right).\left(-\frac{14}{9}\right)\)
=\(-\frac{25}{4}.\frac{1}{-15}-\frac{6}{5}.\left(-\frac{14}{9}\right)\)
= \(\frac{-5}{12}-\frac{8}{5}\)
= \(\frac{\left(-25\right)-96}{60}\)
= \(\frac{\left(-25\right)+\left(-96\right)}{60}\)
=\(\frac{121}{60}\)
b) \(\left(\frac{-1}{3}\right)-\left(\frac{-3}{5}\right)^0+\left(1-\frac{1}{2}\right)^2:2\)
= \(\left(\frac{-1}{3}\right)-1+\left(\frac{1}{2}\right)^2.\frac{1}{2}\)
=\(\left(\frac{-1}{3}\right)-\frac{3}{3}+\frac{1}{4}.\frac{1}{2}\)
= \(\frac{-4}{3}+\frac{1}{8}\)=\(\frac{-32+3}{24}\)
=\(\frac{-29}{24}\)
c) E=\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
=\(\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.6^9}{2^{10}.3^8+6^8.20}\)
=\(\frac{2^{10}.3^8-2.6^9}{2^{10}.3^8+6^8.20}\)
=\(\frac{3}{5}\)
d)\(\frac{5^4.20^4}{25^5.4^5}\)
=\(\frac{\left(5.20\right)^4}{\left(25.4\right)^5}\)
=\(\frac{100^4}{100^5}\)
=\(\frac{1}{100}\)
Biểu thức 1
$3\dfrac12\cdot\dfrac4{49}-\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{8}\right)$
$=\dfrac72\cdot\dfrac4{49}-\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27-6\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27+\dfrac87$
$=\dfrac{10}{7}.$
Biểu thức 2
$\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot3\dfrac13\right):\dfrac43$
$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac{10}{3}\right):\dfrac43$
$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac43\cdot\dfrac34$
$=\dfrac{10}{81}\cdot\dfrac{99}{250}-1$
$=\dfrac{11}{225}-1$
$=-\dfrac{214}{225}.$
\(25^{10}.\left(\frac{1}{5}\right)^{20}+\left(\frac{3}{4}\right)^8.\left(\frac{-4}{3}\right)^8-2011^0\)
\(=5.5^{10}.\left(\left(\frac{1}{5}\right)^2\right)^{10}+\left(\frac{3}{4}\right)^8.\left(\frac{-4}{3}\right)^8-1\)
\(=\left(5.\left(\frac{1}{5}\right)^2\right)\left(\frac{5}{5}\right)^{10}+\left(-1\right)^8-1\)
\(=\frac{1}{5}.1+1-1\)
\(=\frac{1}{5}\)