a) 2^x : 4 = 128

=> 2x  = 512

=> 2^x  = 2⁹

=> x = 9

b) x¹⁵ = x

=> x¹⁵  = x¹⁵

=> x = 1 hoặc 0

c) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 4

=> x = 2

a) 2^x : 4 = 128

=> 2^x = 128 . 4

=> 2^x = 512

=> 2^x = 2⁹

=> x = 9

b) x¹⁵ = x

=> x¹⁵ = x¹⁵

=> x = 1 hoặc 0

c) ( 2x + 1 )³ = 125

=> ( 2x + 1 )³ = 5³

=> 2x + 1 = 5

=> 2x = 5 - 1

=> 2x = 4

=> x = 4 : 2

=> x = 2

a)2^Xx4=128

   2^X    =128:4

   2^X    =32

   2^X    =2^5

=> X=5

b)X^15=X

=>X=1.Vì 1 mũ bao nhiêu vẫn = 1

c)16^x<128

X=1 vì 16^2= 256 mà lại lớn hơn 128,16^3 thì còn lớn hơn

=>X=1

đúng thì k nha :)

\(-x-15=-25\)

\(\Rightarrow\)\(-x=-25+15\)

\(\Rightarrow\)\(-x=-10\)

-x - 15 = -25

=> -x = -25 + 15

=> -x = -10

|x-5| - 6 = -6

=> |x-5| = -6 + 6

=> |x-5| = 0

=> x - 5 = 0

=> x = 5

|x+215| -(-4) = 219

|x+215| + 4 = 219

|x+215| = 219 - 4

|x+215| = 215

\(\hept{\begin{cases}x+215=215\\x+215=-215\end{cases}\Rightarrow}\hept{\begin{cases}x=0\\x=430\end{cases}}\)

Bài cuối tự làm

(2*x+1)³=125

 (2*x+1)=5^3

  2*x+1 =5

  2*x     =5-1

  2*x     =4

          x=4:2

          x=2

con may cau hoi kia lat lam tiep

chuc bn hoc gioi!

nha

a, x=2

b, x=5

x=1

2^x.4=128

=> 2^x=128:4

=> 2^x=32

=> 2^x=2⁵

=> x=5

(2^x+1)³=125

=>(2^x+1)³=5³

=>2^x+1=5

=>2^x=5-1

=>2^x=4

=>2^x=2²

=>x=2

2^x-15=17

=>2^x=17+15

=>2^x=32

=>2^x=2⁵

=>x=5

a) x=5

b) x=2

c) x=5

2^x . 4 = 128

2^x      = 128 : 4

2^x      = 32

2^x      = 2 . 2 . 2 . 2 . 2

2^x        = 2⁵

x       = 5

(2x + 1)³ = 125

(2x + 1)³ = 5 . 5 . 5

(2x + 1)³ = 5³

2x + 1    = 5

2x         = 5 - 1 

2x         = 4

x          = 4 : 2

x          = 2

x¹⁵ = x

x = 1

(x - 5)⁴ = (x - 5)⁶

x = 6

a,x=5

b,x=2

c,x=6

tk mk nhé

a) 2^x.4 = 128

    2^x    = 128 : 4

    2^x    = 32

    2^x    = 2⁵

=>  x = 5

b) x¹⁵ = x

=> x có hai trường hợp : x = 1 hoặc x = 0

Vì 1¹⁵ = 1 ; 0¹⁵ = 0

Nên x = 1 hoặc 0

c) 16^x < 128

=> \(x\in\left\{0;1\right\}\)

A=7 B=1 OR =0 C=2 D=4.5.6

a: \(2^{x}\cdot4=128\)

=>\(2^{x}=\frac{128}{4}=32=2^5\)

=>x=5

b: \(x^{15}=x\)

=>\(x^{15}-x=0\)

=>\(x\left(x^{14}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{14}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{14}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\end{array}\right.\)

c: \(\left(2x+1\right)^3=125\)

=>\(\left(2x+1\right)^3=5^3\)

=>2x+1=5

=>2x=5-1=4

=>\(x=\frac42=2\)

d: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-5-1\right)\left(x-5+1\right)=0\)

=>\(\left(x-5\right)^4\cdot\left(x-6\right)\left(x-4\right)=0\)

=>\(\left[\begin{array}{l}x-5=0\\ x-6=0\\ x-4=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=5\\ x=6\\ x=4\end{array}\right.\)