| x - 6 | = 89

ta có 2 trường hợp

th1

x -6  = 89

x  =  89 + 6

x = 95

th2

x -6 = -89

x     = (-89) + 6

x     = -82

=> x = 95;-82

giáng sinh vv

thank bạn nha

x^3=125

x=5

x⁶:x³=125

x^6-3=125

x³=125

x³=5³

x=5

vậy x=5

a) \(x\cdot25=5^3\)

\(x\cdot25=125\)

\(x=\frac{125}{25}\)

\(x=5\)

b) \(6^x:6^2=6^4\)

\(6^x=6^4\cdot6^2\)

\(6^x=6^6\)

\(x=6\)

c) \(3x=27\)

\(x=27:3\)

\(x=9\)

d) \(5^x+1=125\)

\(5^x=124\)

...

e) \(x\cdot36=6^8\)

\(x=6^8:6^2\)

\(x=6^6\)

\(x=46656\)

g) \(7^x+1:7^2=7^9\)

\(7^x=7^9-\frac{1}{7^2}\)

......

a, x =  125: 25 =5

b , 6 ^x =6^4 . 6^2

6^x =6^6

=> x =6

c, 3x = 27 

=> 3x = 3 .9

=> x = 9 ( vì 3 =3 )

d, 5^x +1 =125

5 ^ x+1 =5^3

=>x +1 =3

=>x=2

e, x. 36 =6 ^8

x . 6^2 = 6^8

x = 6^8 : 6^2

x= 6^6

g , 7^x+1 : 7^2 = 7^9

7^x+1 = 7^2+9

7^x +1=7^ 11

=>x +1 =11

=> x =10

a)\(3^x=9\Leftrightarrow x^x=3^2\Leftrightarrow x=2\)

b)\(6^{x-1}=36\Leftrightarrow6^{x-1}=6^2\Leftrightarrow x-1=2\Leftrightarrow x=3\)

c)\(5^x=125\Leftrightarrow5^x=5^3\Leftrightarrow x=3\)

d)\(3^{2x+1}=27\Leftrightarrow3^{2x+1}=3^3\Leftrightarrow2x+1=3\Leftrightarrow2x=2\Leftrightarrow x=1\)

e) \(3^{x+1}=9\Leftrightarrow3^{x+1}=3^2\Leftrightarrow x+1=2\Leftrightarrow x=1\)

f) \(x^{50}=x\Leftrightarrow\hept{\begin{cases}x=1\\x=0\end{cases}}\)

\(3^x=9\)

\(\Rightarrow3^x=3^2\)

\(\Rightarrow x=2\)

a: \(3636:\left(12\cdot x-91\right)=36\)

=>\(12x-91=\frac{3636}{36}=101\)

=>12x=91+101=192

=>\(x=\frac{192}{12}=16\)

b: \(446+2\cdot\left(125-x\right)=546\)

=>\(2\left(125-x\right)=546-446=100\)

=>125-x=50

=>x=125-50=75

c: \(\left(x-36\right):18=10+2\)

=>\(\left(x-36\right):18=12\)

=>\(x-36=18\cdot12=216\)

=>x=216+36=252

a: x^3=7^3

=>x^3=343

=>\(x=\sqrt[3]{343}=7\)

b: x^3=27

=>x^3=3^3

=>x=3

c: x^3=125

=>x^3=5^3

=>x=5

d: (x+1)^3=125

=>x+1=5

=>x=4

e: (x-2)^3=2^3

=>x-2=2

=>x=4

f: (x-2)^3=8

=>x-2=2

=>x=4

h: (x+2)^2=64

=>x+2=8 hoặc x+2=-8

=>x=6 hoặc x=-10

j: =>x-3=2 hoặc x-3=-2

=>x=1 hoặc x=5

k:

9x^2=36

=>x^2=36/9

=>x^2=4

=>x=2 hoặc x=-2

l:

(x-1)^4=16

=>(x-1)^2=4(nhận) hoặc (x-1)^2=-4(loại)

=>x-1=2 hoặc x-1=-2

=>x=3 hoặc x=-1

\(a,5x-16=40-1\)

<=>\(5x=40-1+16\)

<=>\(5x=55\)

<=>\(x=11\)

\(b,x-10=-25\)

<=>\(x=\left(-25\right)-10\)

<=>\(x=-35\)

\(c,-12+x=-30\)

<=>\(x=\left(-30\right)+12\)

<=>\(x=-18\)

a) 5x-16=40-1

5x-16=39

5x=39+16

5x=55

x=55:5

x=11

b)x-10=(-25)

x=(-25)+10

x=(-15)

c) -12+x= -30

           x= -30-(-12)

           x= -30+12

           x= -18

d) 2x +12 = -40+ 6

2x+12=(-34)

2x=(-34)-12

2x=(-46)

x=(-46):2

x=(-23)

e)125:(3x-13)=25

3x-13=125:25

3x-13=5

3x=5+13

3x=18

x=18:3

x=6

f)541+(218-x)=735

218-x=735-541

218-x=194

x=218-194

x=  24

g) 3(2x+1)-19=14

3(2x+1)=14+19

3(2x+1)=33

2x+1=33:3

2x+1=11

2x=11-1

2x=10

x=10:2

x=5

h)175-5(x+3)=85

5(x+3)=175-85

5(x+3)=90

x+3=90:5

x+3=18

x=18-3

x=15

i)8x+(-3)=39

8x=39-(-3)

8x=42

x=42:8

x=42/8

L)2x+4x=36+(-6)

6x=30

x=30:6

x=5

Ta có: 3636:(12x−91)=36

12x–91=3636:36

12x–91=101

12x=101+91

12x=192

x=192:12

x=16

Vậy x=16

440 + 2. (125 – x) = 546

2. (125 - x)=546 - 440

2. (125 - x)=106

125 - x=106 : 2

125 - x=53

x=125-53

x=72