a/ 1818 : (6x - 37) = 18

6x- 37 = 101

6x = 138

x= 23

b/ (x : 23 + 45) . 67 = 8911

x : 23 + 45 = 133

x: 23 = 88

x = 2024

a/  1818 : ( 6x - 37 ) = 18

                  6x - 37   = 1818 : 18

                  6x - 37   = 101

                  6x          = 101 + 37

                  6x          = 138

                   x           = 138 : 6

                   x           = 23

b/  ( x : 23 + 45 ) . 67  = 8911

                 x : 23 + 45 = 8911 : 67

                 x : 23 + 45 = 133

                         x : 23 = 133 - 45

                         x : 23 = 88

                                x = 88 . 23

                                x = 2024

a) ( x + 216 ) : 61 + 1 = 202

( x + 216 ) : 61 = 201

( x + 216 ) = 12261

x = 12045

b) 1818 : ( 6x - 37 ) + 1 = 19

1818 : ( 6x - 37 ) = 18

( 6x - 37 ) = 101

6x = 138

x = 23

c) ( x : 23 + 45 ) x 67 + 3 = 8914

( x : 23 + 45 ) x 67 = 8911

x : 23 + 45 = 133

x : 23 = 88

x = 2024

(x + 216) : 61 + 1 = 202

=> (x + 216) : 61 = 201

=> x + 216 = 12261

=> x = 12045

vậy_

1818 : (6x - 37) + 1 = 19

=> 1818 : (6x - 37) = 18

=> 6x - 37 = 101

=> 6x = 138

=> x = 23

vậy_

(x : 23 + 45) x 67 + 3 = 8914

=> (x : 23 + 45) x 67 = 8911

=> x : 23 + 45 = 133

=>x : 23 = 88

=> x = 2024

vậy_

a: \(280-\left(x-140\right):35=270\)

=>(x-140):35=280-270=10

=>x-140=350

=>x=350+140

=>x=490

b: \(\left(190-2x\right):35-32=16\)

=>\(\left(190-2x\right):35=32+16=48\)

=>\(190-2x=35\cdot48=1680\)

=>2x=190-1680=-1490

=>x=-745

c: \(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=2^3\cdot5\)

=>\(720:\left\lbrack41-\left(2x-5\right)\right\rbrack=8\cdot5=40\)

=>41-(2x-5)=720:40=18

=>2x-5=41-18=23

=>2x=28

=>x=14

d: \(\left(x:23+45\right)\cdot37-22=2^4\cdot105\)

=>\(\left(\frac{x}{23}+45\right)\cdot37=16\cdot105+22=1702\)

=>\(\frac{x}{23}+45=46\)

=>\(\frac{x}{23}=1\)

=>x=23

e: \(\left(3x-4\right)\left(x-1\right)^3=0\)

=>\(\left[\begin{array}{l}3x-4=0\\ x-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac43\\ x=1\end{array}\right.\)

f: \(2^{2x-1}:4=8^3\)

=>\(2^{2x-1-2}=2^9\)

=>2x-3=9

=>2x=12

=>x=6

g: \(x^{17}=x\)

=>\(x^{17}-x=0\)

=>\(x\left(x^{16}-1\right)=0\)

=>\(\left[\begin{array}{l}x=0\\ x^{16}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x^{16}=1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=1\\ x=-1\end{array}\right.\)

h: \(\left(x-5\right)^4=\left(x-5\right)^6\)

=>\(\left(x-5\right)^6-\left(x-5\right)^4=0\)

=>\(\left(x-5\right)^4\cdot\left\lbrack\left(x-5\right)^2-1\right\rbrack=0\)

=>\(\left(x-5\right)^4\cdot\left(x-4\right)\left(x-6\right)=0\)

=>x∈{4;5;6}

i: \(\left(x+2\right)^5=2^{10}\)

=>\(\left(x+2\right)^5=\left(2^2\right)^5=4^5\)

=>x+2=4

=>x=2

k: 1+2+3+...+x=78

=>\(\frac{x\left(x+1\right)}{2}=78\)

=>x(x+1)=156

=>\(x^2+x-156=0\)

=>(x+13)(x-12)=0

=>x=-13(loại) hoặc x=12(nhận)

l: \(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)

=>\(3x-16=2\cdot\frac{7^4}{7^3}=2\cdot7=14\)

=>3x=16+14=30

=>\(x=\frac{30}{3}=10\)

n: \(5^{x}:5^2=125\)

=>\(5^{x-2}=5^3\)

=>x-2=3

=>x=5

m: \(\left(x+1\right)^2=\left(x+1\right)^0\)

=>\(\left(x+1\right)^2=1\)

=>\(\left[\begin{array}{l}x+1=1\\ x+1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-2\end{array}\right.\)

o: Số số hạng của dãy số 2;4;..;52 là:

(52-2):2+1=50:2+1=25+1=26(số)

Tổng của dãy số 2;4;...;52 là:

\(\left(52+2\right)\cdot\frac{26}{2}=54\cdot13=702\)

(2+x)+(4+x)+...+(52+x)=780

=>26x+702=780

=>26x=78

=>x=3

p: \(70=2\cdot5\cdot7;80=2^4\cdot5\)

=>ƯCLN(70;80)=\(2\cdot5=10\)

70⋮x; 80⋮x

=>x∈ƯC(70;80)

=>x∈Ư(10)

mà x>8

nên x=10

q: \(12=2^2\cdot3;25=5^2;30=2\cdot3\cdot5\)

=>BCNN(12;25;30)=\(2^2\cdot3\cdot5^2=300\)

x⋮12; x⋮25; x⋮30

=>x∈BC(12;25;30)

=>x∈B(300)

mà 0<x<500

nên x=300

1)\(x-105:21=15\)

\(x-5=15\)

\(x=15+5\)

\(x=20\)

Vậy \(x=20.\)

2)\(\left(x-105\right):21=15\)

\(\left(x-105\right)=15.21\)

\(x-105=315\)

\(x=315+105\)

\(x=420\)

Vậy \(x=412.\)

4)\(1818:\left(6x-37\right)=18\)

\(6x-37=1818:18\)

\(6x-37=101\)

\(6x=101+37\)

\(6x=138\)

\(x=138:6\)

\(x=23\)

Vậy \(x=23.\)

mk quên,còn phần 3) nữa:

3)\(\left(32+x\right):17=x\)

\(32+x=x.17\)

\(\Leftrightarrow x=2\)

Vậy \(x=2.\)

a) x(17+33)=100

50x=100

x=2

a, x = 2

b, x = 0

mình đầu tiên k mình nha bạn

:))))

a/ -x + 8 = -17-30

-x + 8 = -47

-x  = -47 - 8

-x = -55

x = 55

Vậy x = 55

b/ 35 – x = 37

 x = 35 - 37

x = -2

Vậy x = -2

c/ (-19 – x) + 23 = -20

-19 – x  = -20 -  23

-19 – x = -43

x = -19 - (-43)

x = 24

Vậy x = 24

d/ (x – 45) : 2 = -17

x – 45 = -17 * 2

x – 45 = -34

x = -34 + 45

x =  11

Vậy x = 11

a/ -x + 8 = -17-30

-x + 8 = -47

-x =-47 - 8

-x = -55

x = 55

Vậy x = 55

Phần a mình bị lỗi nên sửa lại nha

(1900 - 2x) : 35 - 32 = 16

=> (1900 - 2x)  : 35 = 48

=> 1900 - 2x = 1680

=> 2x = 220

=> x = 110

vậy_

111 + 1818 : (6x - 37) = 129

=> 1818 : (6x - 37) = 18

=> 6x - 37 = 101

=> 6x = 138

=> x = 23

vậy_

(x : 3 + 45) x 67 - 31 = 8880

=> (x : 3 + 45) x 67 = 8911

=> x : 3 + 45 = 133

=> x : 3 + = 88

=>x = 264

vậy_

a ) x = 2 45 − 1 9 = − 1 15 ; b ) x = − 3 7 − 4 5 − − 2 3 = − 59 105