(-5) mu 222 < 3 mu 333 

chúc bạn học giỏi

\(\Rightarrow\)

\(\text{Ta có : }\)

\(\left(-5\right)^{222}< 3^{333}\)

\(\text{Chúc bạn học tốt ! }\)

\(\frac{x-1}{27}=\frac{-3}{1-x}\)

\(\Rightarrow\frac{x-1}{27}=\frac{3}{x-1}\)

\(\Rightarrow\left(x-1\right)^2=81\)

\(\Rightarrow x-1=\pm9\)

Làm nốt nhassssso

1)Ta có:\(ac=b^2\Rightarrow\frac{a}{b}=\frac{b}{c},ab=c^2\Rightarrow\frac{c}{a}=\frac{b}{c}\)

\(\Rightarrow\frac{a}{b}=\frac{c}{a}=\frac{b}{c}=\frac{a+c+b}{b+a+c}=1\)(T/C...)

\(\Rightarrow a=b=c\)

\(\Rightarrow M=\frac{b^{333}}{a^{111}\cdot c^{222}}=\frac{b^{333}}{b^{111}\cdot b^{222}}=\frac{b^{333}}{b^{333}}=1\)

\(\left(-333\right)^{444}=3^{444}=\left(3^4\right)^{111}=81^{111}\)

\(4^{333}=\left(4^3\right)^{111}=64^{111}\)

\(81^{111}>64^{111}\Rightarrow\left(-3\right)^{444}>444^{333}\)

Ta có : \(A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)...\left(1-\frac{1}{19}\right)\left(1-\frac{1}{20}\right)\)

               \(=\frac{1}{2}.\frac{2}{3}....\frac{18}{19}.\frac{19}{20}\)

               \(=\frac{1.2....18.19}{2.3...19.20}\)

               \(=\frac{1}{20}>\frac{1}{21}\)

Vậy A > 1/21

ỦA SAO BẠN GIẢI RA LUÔN RỒI. HAY Zậy?

đúng là hay quá ha.

tại mình ấn nhầm

Từ ac = b² (1) => abc = b³

ab = c² => abc = c³

=> b³ = c³ => b = c thay vào (1)

=> ab = b² <=> (a - b).b = 0 <=>  \(\orbr{\begin{cases}a=b\\b=0\left(loại\right)\end{cases}}\)

=> a = b = c

Khi đó: P = \(\frac{a^{555}}{a^{222}.a^{333}}+\frac{b^{555}}{b^{222}.b^{333}}+\frac{c^{555}}{c^{222}.c^{333}}=1+1+1=3\)

\(\left[\frac{7}{11}+\frac{4}{11}\right]:\left[\frac{1}{3}.3+\frac{77}{333}:\frac{77}{333}\right]\)

= 1 : [ 1 + 1 ]

= 1 : 2

= \(\frac{1}{2}\)

\(\left[0,\left(63\right)+0,\left(36\right)\right]:\left[0,\left(3\right)+0,\left(231\right):\frac{77}{333}\right]\)

\(=\left[\frac{63}{99}+\frac{36}{99}\right]:\left[\frac{3}{9}.3+\frac{231}{999}\cdot\frac{333}{77}\right]\)

\(=1:\left[1+1\right]=\frac{1}{2}\)