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a)
\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)
Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)
Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).
b)
\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)
Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)
Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).
c)
\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)
Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)
Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).
d)
\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)
Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).
có phải ghi cách làm ra không bạn hay chỉ ghi dấu thôi
a: 3/4=27/36
4/9=16/36
=>3/4>4/9
b: 16/36=4/9=12/27<14/27
c: 8/12=2/3=4/6
25/30=5/6
=>8/12<25/30
d: 8/13>8/15
a) \(\frac{7}{8}=\frac{14}{16}>\frac{11}{16}\)
b) \(\frac{15}{35}=\frac{3}{7}=\frac{24}{56}\)
c) \(\frac{20}{31}>\frac{20}{33}>\frac{19}{33}\)
d) \(\frac{11}{12}<\frac{14}{12}=\frac{7}{6}\)
a:Cách 1: \(\frac{21}{35}=\frac{21:7}{35:7}=\frac35\)
\(\frac{12}{40}=\frac{12:4}{40:4}=\frac{3}{10}\)
mà \(\frac35>\frac{3}{10}\left(5<10\right)\)
nên \(\frac{21}{35}>\frac{12}{40}\)
Cách 2: \(\frac{21}{35}=\frac{21\times8}{35\times8}=\frac{168}{280}\)
\(\frac{12}{40}=\frac{12\times7}{40\times7}=\frac{84}{280}\)
mà 168>84
nên \(\frac{21}{35}>\frac{12}{40}\)
b: Cách 1: \(\frac{35}{49}=\frac{35:7}{49:7}=\frac57\)
\(\frac{40}{64}=\frac{40:8}{64:8}=\frac58\)
mà \(\frac57>\frac58\left(7<8\right)\)
nên \(\frac{35}{49}>\frac{40}{64}\)
Cách 2: \(\frac{35}{49}=\frac{35\times64}{49\times64}=\frac{2240}{3136}\)
\(\frac{40}{64}=\frac{40\times49}{64\times49}=\frac{1960}{3136}\)
mà 2240>1960
nên \(\frac{35}{49}>\frac{40}{64}\)
c: Cách 1: \(\frac{9}{11}=1-\frac{2}{11}\)
\(\frac{13}{15}=1-\frac{2}{15}\)
Ta có: 11<15
=>\(\frac{2}{11}>\frac{2}{15}\)
=>\(-\frac{2}{11}<-\frac{2}{15}\)
=>\(-\frac{2}{11}+1<-\frac{2}{15}+1\)
=>\(\frac{9}{11}<\frac{13}{15}\)
Cách 2: Ta có: \(\frac{9}{11}=\frac{9\times15}{11\times15}=\frac{135}{165}\)
\(\frac{13}{15}=\frac{13\times11}{15\times11}=\frac{143}{165}\)
mà 135<143
nên \(\frac{9}{11}<\frac{13}{15}\)
d: Cách 1: \(\frac{21}{7}=\frac{21\times5}{7\times5}=\frac{105}{35}\)
mà 105>24
nên \(\frac{21}{7}>\frac{24}{35}\)
cách 2: Ta có: \(\frac{21}{7}=3>1;1>\frac{24}{35}\)
Do đó: \(\frac{21}{7}>\frac{24}{35}\)
e: Cách 1: \(\frac12=\frac{1\times2424}{2\times2424}=\frac{2424}{4848}\)
Cách 2: \(\frac{2424}{4848}=\frac{2424:2424}{4848:2424}=\frac12\)
f: Vì 19>11
nên \(\frac{19}{15}>\frac{11}{15}\)


Có: 8/12 = 2/3 = 4/6
35/30 = 7/6
Do đó: 8/12 < 35/30
\(\dfrac{8}{12}=\dfrac{2}{3}=\dfrac{2\cdot10}{3\cdot10}=\dfrac{20}{30}< \dfrac{35}{30}\)