Ở câu a) số mũ lúc nào cug dương mà bạn ( 45^-10 = 45¹⁰). Nếu số mũ là dương thì:

            a)\(\frac{45^{10}.5^{20}}{75^{15}}\)

        = \(\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(3.5^2\right)^{15}}\)

        = \(\frac{3^{20}.5^{10}.5^{20}}{3^{15}.5^{30}}\)

         = \(\frac{3^{20}.5^{30}}{3^{15}.5^{30}}\)

         = \(\frac{3^5.1}{1.1}\)

         = \(\frac{243}{1}\)

         = 243

      b)\(\frac{2^{15}.9^4}{6^6.8^2}\)

          = \(\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^2}\)

          = \(\frac{2^{15}.3^8}{2^6.3^6.2^6}\)

          = \(\frac{2^{15}.3^8}{2^{12}.3^6}\)

          = \(\frac{2^3.3^2}{1.1}\)

          = \(\frac{8.9}{1}\)

          = \(\frac{72}{1}\)

          = 72

cảm ơn bn

a)

\(\frac{16^5.21^6.45^3.30^2}{18^5.24^6.48^3.36^2}=\frac{2^{20}.3^6.7^6.5^3.3^6.3^2.2^2.5^2}{2^5.3^{10}.3^6.2^{18}.3^3.2^{12}.2^4.3^4}=\frac{2^{22}.3^{14}.7^6.5^5}{2^{39}.3^{23}}=\frac{7^6.5^5}{2^{17}.3^{11}}\)

b)

\(\frac{6^9.30^6.8^7.14^8}{9^7.24^6.10^7.7^9}=\frac{3^9.2^9.3^6.10^6.2^{21}.7^8.2^8}{3^{14}.3^6.2^{18}.10^7.7^9.}=\frac{3^{15}.2^{38}}{3^{20}.2^{18}.10.7}=\frac{2^{20}}{3^5.2.5.7}=\frac{2^{19}}{3^5.35}\)

\(\frac{2^{15}.3^4.3^4}{2^6.3^6.2^3.4^3}\)

=\(\frac{2^6.3^2}{4^3}\)

=9

a) \(\frac{7.12^3+2.12^3}{4^6.3^{11}}=\frac{12^3.\left(7+2\right)}{\left(2^2\right)^6.3^{11}}=\frac{\left(2^2.3\right)^3.3^2}{2^{12}.3^{11}}=\frac{2^6.3^5}{2^{12}.3^{11}}=\frac{1}{2^6.3^6}=\frac{1}{6^6}\)

\(\frac{-17.10+17.6}{18.11+18.6}=\frac{17.\left(-10+6\right)}{18.\left(11+6\right)}=\frac{17.\left(-4\right)}{18.17}=\frac{-2}{9}\)

\(\frac{6.7.8.10}{9.12.14.15}=\frac{2.3.7.2^3.2.5}{3^2.3.2^2.2.7.3.5}=\frac{2^5.3.5.7}{2^3.3^4.5.7}=\frac{2^2}{3^3}=\frac{4}{27}\)

phần b viết khó hiểu, phải viết phân số như a đàng hoàng

Câu 1:

A = (4/9 + 5/6) : (7/8 - 7/12)

A = (8/18 + 15/18) :(21/24 - 14/24)

A = 23/18 : 7/24

A = 23/18 x 24/7

A = 92/21

Câu B = 3/4.8/9.15/16...9999/10000

B = \(\frac{1.3}{2.2}\).\(\frac{2.4}{3.3}\)....\(\frac{99.101}{100.100}\)

B = \(\frac{1.2.3\ldots99}{2.3\ldots100}\). \(\frac{3.4.\ldots101}{2.3\ldots100}\)

B = \(\frac{1}{100}\) x \(\frac{101}{2}\)

B = \(\frac{101}{200}\)

a) \(2^3+3.\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right]\)

\(=8+3.1+4:\frac{1}{2}\)

\(=8+3+8=19\)

b)\(\frac{2^{15}.9^4}{6^6.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^6.3^6.2^9}\)\(=\frac{2^{15}.3^8}{2^{15}.3^6}=3^2=9\)

c) \(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\)

\(=\frac{17}{12}.\frac{1}{400}=\frac{17}{4800}\)

d) \(\left(-\frac{10}{3}\right)^3.\left(\frac{-6}{5}\right)^4=-\frac{100}{27}.\frac{1296}{625}\)\(=\frac{-4.48}{1.25}=-\frac{192}{25}\)