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Đặt A=3(22 +1)(24+1)(28+1)(216+1)

=(4-1)(2^2+1)(2^4+1)(28+1)(2^16+1)

=[(2^2-1)(2^2+1)](2^4+1)(2^8+1)(2^16+1)

=(2^4-1)(2^4+1)(2^8+1)(2^16+1)

=(2^8-1)(2^8+1)(2^16+1)

=(2^16-1)

Theo mình ý a bn làm đc

19 tháng 12 2019

a) \(\left(6x+1\right)^2+\left(6x-1\right)^2-2\left(1+6x\right)\left(6x-1\right)\)

\(=36x^2+12x+1+36x^2-12x+1-72x^2+2\)

\(=4\)

c) \(x\left(2x^2-3\right)-x^2\left(5x+1\right)+x^2\)

\(=2x^3-3x-5x^3-x^2+x^2\)

\(=-3x^3-3x\)

d) \(3x\left(x-2\right)-5x\left(1-x\right)-8\left(x^2-3\right)\)

\(=3x^2-6x-5x+5x^2-8x^2+24\)

\(=-11x+24\)

10 tháng 9
a)

$(6x+1)^2-(6x-1)-2(1+6x)(6x-1)$

$=36x^2+12x+1-6x+1-2(6x+1)(6x-1)$

$=36x^2+6x+2-2(36x^2-1)$

$=36x^2+6x+2-72x^2+2$

$=-36x^2+6x+4$

b)

$x(2x^2-3)-x^2(5x+1)+x^2$

$=2x^3-3x-5x^3-x^2+x^2$

$=2x^3-5x^3-3x$

$=-3x^3-3x$

$=-3x(x^2+1)$

10 tháng 9
c)

$3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$

$=3\cdot\dfrac{2^4-1}{2^2-1}\cdot\dfrac{2^8-1}{2^4-1}\cdot\dfrac{2^{16}-1}{2^8-1}\cdot\dfrac{2^{32}-1}{2^{16}-1}$

$=3\cdot\dfrac{2^{32}-1}{2^2-1}$

$=3\cdot\dfrac{2^{32}-1}{3}$

$=2^{32}-1$

d)

$3x(x-2)-5x(1-x)-8(x^2-3)$

$=3x^2-6x-5x+5x^2-8x^2+24$

$=3x^2+5x^2-8x^2-11x+24$

$=-11x+24$

$=24-11x$

9 tháng 6 2022

hellothanghoa

22 tháng 10 2023

1:

a: \(\left(2x-5\right)^2-4x\left(x+3\right)\)

\(=4x^2-20x+25-4x^2-12x\)

=-32x+25

b: \(\left(x-2\right)^3-6\left(x+4\right)\left(x-4\right)-\left(x-2\right)\left(x^2+2x+4\right)\)

\(=x^3-6x^2+12x-8-\left(x^3-8\right)-6\left(x^2-16\right)\)

\(=-6x^2+12x-6x^2+96=-12x^2+12x+96\)

c: \(\left(x-1\right)^2-2\left(x-1\right)\left(x+2\right)+\left(x+2\right)^2+5\left(2x-3\right)\)

\(=\left(x-1-x-2\right)^2+5\left(2x-3\right)\)

\(=\left(-3\right)^2+5\left(2x-3\right)\)

\(=9+10x-15=10x-6\)

2: 

a: \(\left(2-3x\right)^2-5x\left(x-4\right)+4\left(x-1\right)\)

\(=9x^2-12x+4-5x^2+20x+4x-4\)

\(=4x^2+12x\)

b: \(\left(3-x\right)\left(x^2+3x+9\right)+\left(x-3\right)^3\)

\(=27-x^3+x^3-9x^2+27x-27\)

\(=-9x^2+27x\)

c: \(\left(x-4\right)^2\left(x+4\right)-\left(x-4\right)\left(x+4\right)^2+3\left(x^2-16\right)\)

\(=\left(x-4\right)\left(x+4\right)\left(x-4-x-4\right)+3\left(x^2-16\right)\)

\(=\left(x^2-16\right)\left(-8\right)+3\left(x^2-16\right)\)

\(=-5\left(x^2-16\right)=-5x^2+80\)