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a) 2a−4b=2(a−2b)2a−4b=2(a−2b)
c) 2ax−2ay+2a=2a(x−y+1)2ax−2ay+2a=2a(x−y+1)
e) 3xy(x−4)−9x(4−x)=3x(x−4)(y+3)3xy(x−4)−9x(4−x)=3x(x−4)(y+3)
b,d xem lại đề
\(A,ĐKXĐ:x;y\ge0\)
\(A=\sqrt{xy}-2\sqrt{y}-5\sqrt{x}+10\)
\(=\sqrt{y}\left(\sqrt{x}-2\right)-5\left(\sqrt{x}-2\right)\)
\(=\left(\sqrt{x}-2\right)\left(\sqrt{y}-5\right)\)
\(ĐKXĐ:x;y\ge0\)
\(B=a\sqrt{x}+b\sqrt{y}-\sqrt{xy}-ab\)
\(=\left(a\sqrt{x}-\sqrt{xy}\right)+\left(b\sqrt{y}-ab\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)+b\left(\sqrt{y}-a\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)
\(=\sqrt{x}\left(a-\sqrt{y}\right)-b\left(a-\sqrt{y}\right)\)
\(=\left(a-\sqrt{y}\right)\left(\sqrt{x}-b\right)\)
\(\text{a)}x\sqrt{x}+\sqrt{x}-x-1\)
\(=\left(x\sqrt{x}+\sqrt{x}\right)-\left(x+1\right)\)
\(=\sqrt{x}\left(x+1\right)-\left(x+1\right)\)
\(=\left(x+1\right)\left(\sqrt{x}-1\right)\)
\(\text{b)}\sqrt{ab}+2\sqrt{a}+3\sqrt{b}+6\)
\(=\left(\sqrt{ab}+2\sqrt{a}\right)+\left(3\sqrt{b}+6\right)\)
\(=\sqrt{a}\left(\sqrt{b}+2\right)+3\left(\sqrt{b}+2\right)\)
\(=\left(\sqrt{b}+2\right)\left(\sqrt{a}+3\right)\)
\(\text{c)}\left(1+\sqrt{x}\right)^2-4\sqrt{x}\)
\(=\left(1+\sqrt{x}\right)^2-\left(2\sqrt{\sqrt{x}}\right)^2\)
\(=\left(1+\sqrt{x}+2\sqrt{\sqrt{x}}\right)\left(1+\sqrt{x}-2\sqrt{\sqrt{x}}\right)\)
\(\text{d)}\sqrt{ab}-\sqrt{a}-\sqrt{b}+1\)
\(=\left(\sqrt{ab}-\sqrt{a}\right)-\left(\sqrt{b}-1\right)\)
\(=\sqrt{a}\left(\sqrt{b}-1\right)-\left(\sqrt{b}-1\right)\)
\(=\left(\sqrt{b}-1\right)\left(\sqrt{a}-1\right)\)
\(\text{e)}a+\sqrt{a}+2\sqrt{ab}+2\sqrt{b}\)
\(=\left(a+\sqrt{a}\right)+\left(2\sqrt{ab}+2\sqrt{b}\right)\)
\(=\left[\left(\sqrt{a}\right)^2+\sqrt{a}\right]+\left(2\sqrt{ab}+2\sqrt{b}\right)\)
\(=\sqrt{a}\left(\sqrt{a}+1\right)+2\sqrt{b}\left(\sqrt{a}+1\right)\)
\(=\left(\sqrt{a}+1\right)\left(\sqrt{a}+2\sqrt{b}\right)\)
\(\text{f)}x-2\sqrt{x-1}-a^2\)
\(=\left(\sqrt{x-2}\right)^2\left(\sqrt{\sqrt{x-1}}\right)^2-a^2\)
\(=\left(\sqrt{x-2}\sqrt{\sqrt{x-1}}\right)^2-a^2\)
\(=\left(\sqrt{x-2\sqrt{x-1}}\right)^2-a^2\)
\(=\left(\sqrt{x-2\sqrt{x-1}}+a\right)\left(\sqrt{x-2\sqrt{x-1}}-a\right)\)
úi sao bạn cũng là quản lý giống mình à, mình trả lời câu hỏi của bạn có được không nhỉ
a, \(x-\sqrt{x}\)= \(\sqrt{x}.\left(\sqrt{x}-1\right)\)
b, 3x+6\(\sqrt{x}\)= \(\sqrt{x}.\left(3\sqrt{x}+6\right)\)
c, x+2\(\sqrt{x}+1\)= \(\left(\sqrt{x}\right)^2+2\sqrt{x}+1=\left(\sqrt{x}+1\right)^2\)
d, \(3x-5\sqrt{x}+2=3x-3\sqrt{x}-2\sqrt{x}+2\)
=\(3\sqrt{x}.\left(\sqrt{x}-1\right)-2.\left(\sqrt{x}-1\right)\)
=\(\left(3\sqrt{x}-2\right).\left(\sqrt{x}-1\right)\)
a) \(x-2\sqrt{x-1}-4=\left(x-1\right)-2\sqrt{x-1}+1-4\)
\(=\left(\sqrt{x-1}-1\right)^2-4=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(x-2\sqrt{x-6}-5-y^2=\left(x-6\right)-2\sqrt{x-6}+1-y^2\)
\(=\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-1+y\right)\left(\sqrt{x-6}-1-y\right)\)
c) \(x-2\sqrt{x-8}-7-a^2=\left(x-8\right)-2\sqrt{x-8}+1-a^2\)
\(=\left(\sqrt{x-8}-1\right)^2-a^2=\left(\sqrt{x-8}+a-1\right)\left(\sqrt{x-8}-a-1\right)\)
a) \(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c) \(\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a/ \(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+2\right)\)
b/ \(\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c/\(\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a)\(\) (\(\sqrt{x-1}-3\))(\(\sqrt{x-1}\)+1)
b) (\(\sqrt{x-6}-1-y\))(\(\sqrt{x-6}-1+y\))
c) (\(\sqrt{x-8}-1-a\))(\(\sqrt{x-8}-1+a\))
a)\(\left(x-4\right)\left(x+2\right)\)
b)\(\left(x-7-y\right)\left(x+y-7\right)\)
c)\(\left(x-9-a\right)\left(x-9+a\right)\)
a) \(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b)\(\left(\sqrt{x-6}-1+y\right)\left(\sqrt{x-6}-1-y\right)\)
c) \(\left(\sqrt{x-8}+a-1\right)\left(\sqrt{x-8}-a-1\right)\)
a) x - 2\(\sqrt{x-1}\) -4 = (x-1) - 2\(\sqrt{x-1}\) +1 -4= (\(\sqrt{x-1}\) -1)2 - 4=( \(\sqrt{x-1}\) - 1 -2)(\(\sqrt{x-1}\) -1 +2)
=(\(\sqrt{x-1}\) - 3)(\(\sqrt{x-1}\) +1)
b) x - 2\(\sqrt{x-6}\) - 5 -y2= ( x -6) - 2\(\sqrt{x-6}\) +1 - y2= (\(\sqrt{x-6}\) - 1)2 -y2
a.\(x-2\sqrt{x-1}-4=\left(x-1\right)-2\sqrt{x-1}+1-2^2=\left(\sqrt{x-1}-1\right)^2-2^2=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b.\(x-2\sqrt{x-6}-5-y^2=\left(x-6\right)-2\sqrt{x-6}+1-y^2=\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-y-1\right)\left(\sqrt{x-6}+y-1\right)\)
c.\(x-2\sqrt{x-8}-7-a^2=\left(x-8\right)-2\sqrt{x-8}+1-a^2=\left(\sqrt{x-8}-1\right)^2-a^2=\left(\sqrt{x-8}-a-1\right)\left(\sqrt{x-8}+a-1\right)\)
a) \(x-2\sqrt{x-1}-4=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(x-2\sqrt{x-6}-5-y^2=\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c) \(x-2\sqrt{x-8}-7-a^2=\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a) x-2\sqrt{x-1}-4=\left(x-1\right)-2\sqrt{x-1}+1-4\\ =\left(\sqrt{x-1}-1\right)^2-2^2=\left(\sqrt{x-1}-1-2\right)\left(\sqrt{x-1}-1+2\right)=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)x−2x−1−4=(x−1)−2x−1+1−4=(x−1−1)2−22=(x−1−1−2)(x−1−1+2)=(x−1−3)(x−1+1)
b)
x-2\sqrt{x-6}-5-y^2=\left(x-6\right)-2\sqrt{x-6}+1-y^2\\ =\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)x−2x−6−5−y2=(x−6)−2x−6+1−y2=(
a) \(\left(\sqrt{x-1}-1\right)\left(\sqrt{x-1}+3\right)\)
b) \(\left(\sqrt{x-6}+1-y\right)\left(\sqrt{x-6}+1+y\right)\)
c) \(\left(\sqrt{x-8}+1-a\right)\left(\sqrt{x-8}+1+a\right)\)
a) \(\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c) \(\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a) \(x-2\sqrt{x-1}-4=x-1-2\sqrt{x-1}+1-4=\left(\sqrt{x-1}\right)^2-2\sqrt{x-1}+1-4=\left(\sqrt{x-1}-1\right)^2-2^2=\left(\sqrt{x-1}-1-2\right)\left(\sqrt{x-1}-1+2\right)=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(x-2\sqrt{x-6}-5-y^2=x-6-2\sqrt{x-6}+1-y^2=\left(\sqrt{x-6}\right)^2-2\sqrt{x-6}+1-y^2=\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)
c) \(x-2\sqrt{x-8}-7-a^2=x-8-2\sqrt{x-8}+1-a^2=\left(\sqrt{x-8}\right)^2-2\sqrt{x-8}+1-a^2=\left(\sqrt{x-8}-1\right)^2-a^2=\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a)x-2√x-1-4
=(x-1)-2√x-1 +1-4
=(√x-1 -1)^2)-2^2
=(√x-1 -1-2).(√x-1 -1+2)
=(√x-1 -3).(√x+1 +1)
b)x-2√x-6 -5-y^2
=(x-6)-2√x-6+1-y^2
=(√x-6 -1)^2 -y^2
=(√x-6 -1-y).(√x-6 -1+y)
c)x-2√x-8 -7-a^2
=(x-8)-2√x-8 +1-a^2
=(√x-8 -1)^2 -a^2
=(√x-8-1-a).(√x -8-1+a)
a,
\(x-2\sqrt{x-1}-4=\left(x-1\right)-2\sqrt{x-1}+1-4=\left(\sqrt{x-1}-1\right)^2-2^2=\left(\sqrt{x-1}-1-2\right)\left(\sqrt{x-1}-1+2\right)=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)b,
\(x-2\sqrt{x-6}-5-y^2=\left(x-6\right)-2\sqrt{x-6}+1-y^2=\left(\sqrt{x-6}-1\right)^2-y^2=\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)c,
\(x-2\sqrt{x-8}-7-a^2=\left(x-8\right)-2\sqrt{x-8}+1-a^2=\left(\sqrt{x-8}-1\right)^2-a^2=\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)
a) x - \(2\sqrt{x-1}\) - 4
= (x - 1) - \(2\sqrt{x-1}\) + 1 - 4
= (\(\sqrt{x-1}\) - 1)2 - 22
= (\(\sqrt{x-1}\) - 3) (\(\sqrt{x-1}\) +1)
b) x - \(2\sqrt{x-6}\) - 5 - y2
= (\(\sqrt{x-6}\) - 1)2 - y2
= ( \(\sqrt{x-6}-1-y\))(\(\sqrt{x-6}-1+y\))
c) x - \(2\sqrt{x-8}-7-a^2\)
= (\(\sqrt{x-8}\) - 1)2 - a2
= ( \(\sqrt{x-8}-1-a\))(\(\sqrt{x-8}-1+a\))
a)x-2\(\sqrt{x-1}\)-4=((\(\sqrt{x-1}\)-2\(\sqrt{x-1}\)+1))-4=(\(\sqrt{x-1}\)-1)2-22=(\(\sqrt{x-1}\)+2)(\(\sqrt{x-1}\)-2)=(\(\sqrt{x-1}\)+1)(\(\sqrt{x-1}\)+3
b)x-2\(\sqrt{x-6}\)-5-y2=((x-6)-2\(\sqrt{x-6}\)+1)2=(\(\sqrt{x-6}\)-1)2-y2=(\(\sqrt{x-6}\)-1-y)(\(\sqrt{x-6}\)-1+y)
c)x-2\(\sqrt{x-8}\)-7-a2=((x-8)-2\(\sqrt{x-8}\)+1)-a2=(\(\sqrt{x-8}\)-1)2-a2=(\(\sqrt{x-8}\)-1-a)(\(\sqrt{x-8}\)-1+a)
A= (x-1)-2\(\sqrt{ }\)x-1+1-4=(\(\sqrt{ }\)x-1-1)2-22=(\(\sqrt{ }\)x-1-1-2)(\(\sqrt{ }\)x-1-1+2)=(\(\sqrt{ }\)x-1-3)(\(\sqrt{ }\)x-1+1)
a) x-2√x-1-4=(√x-1-3)(√x-1+1)
b)x-2√x-6-5-y^2=(√x-6-1-y)(√x-6-1+y)
c)x-2√x-8-7-a^2=(√x-8-1-a)(√x-8-1+a)
a) x-2√x-1-4=(√x-1-3)(√x-1+1)
b)x-2√x-6-5-y^2=(√x-6-1-y)(√x-6-1+y)
c)x-2√x-8-7-a^2=(√x-8-1-a)(√x-8-1+a)
a)x-2\(\sqrt{x-1}\)-4=(x-1)-2\(\sqrt{x-1}\)+1-4=(\(\sqrt{x-1}\)-1)2-4=(\(\sqrt{x-1}\)-1-2).(\(\sqrt{x-1}\)-1+2)=(\(\sqrt{x-1}\)-3).(\(\sqrt{x-1}\)+1)
b)x-2\(\sqrt{x-6}\)-5-y2=(x-6)-2\(\sqrt{x-6}\)+1-y2=(\(\sqrt{x-6}\)-1)2-y2=(\(\sqrt{x-6}\)-1-y).(\(\sqrt{x-6}\)-1+y)
c)x-2\(\sqrt{x-8}\)-7-a2=(x-8)-2\(\sqrt{x-8}\)+1-a2=(\(\sqrt{x-8}\)-1)2-a2=(\(\sqrt{x-8}\)-1-a).(\(\sqrt{x-8}\)-1+a)
a) \(x-2\sqrt{x-1}-4\)\(=\left(x-1-2\sqrt{x-1}.1+1\right)-4\)\(=\left[\left(\sqrt{x-1}\right)-1\right]^2-2^2\)\(=\left(\sqrt{x-1}-1-2\right)\left(\sqrt{x-1}-1+2\right)\)\(=\left(\sqrt{x-1}-3\right)\left(\sqrt{x-1}+1\right)\)
b) \(x-2\sqrt{x-6}-5-y^2\)\(=\left(x-6-2\sqrt{x-6}.1+1\right)-y^2\)\(=\left(\sqrt{x-6}-1-y\right)\left(\sqrt{x-6}-1+y\right)\)\(=\left(\sqrt{x-6}-1\right)^2-y^2\)
c) \(x-2\sqrt{x-8}-7-a^2\)\(=\left(x-8-2\sqrt{x-8}.1+1\right)-a^2\)\(=\left(\sqrt{x-8}-1\right)^2-a^2\)\(=\left(\sqrt{x-8}-1-a\right)\left(\sqrt{x-8}-1+a\right)\)