a)\(\left(\frac{-1}{3}\right)^3\cdot x=\frac{1}{81}\) \(< =>\frac{-1}{27}x=\frac{1}{81}\)\(< =>x=\frac{-1}{3}\)

phân tích kết quả ra bạn nhé

ĐK:  \(x\ne\left\{0;-1;-2;-3\right\}\)

\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2017}\)

\(\Leftrightarrow\)\(\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}-\frac{1}{x}=\frac{1}{2017}\)

\(\Leftrightarrow\)\(-\frac{1}{x+3}=\frac{1}{2017}\)

\(\Rightarrow\)\(x+3=-2017\)

\(\Leftrightarrow\)\(x=-2020\)

Vậy...

\(\frac{1}{x\left(x+1\right)}+\frac{1}{\left(x+1\right)\left(x+2\right)}+\frac{1}{\left(x+2\right)\left(x+3\right)}-\frac{1}{x}=\frac{1}{2017}\)

\(\frac{1}{x}-\frac{1}{x+1}+\frac{1}{x+1}-\frac{1}{x+2}+\frac{1}{x+2}-\frac{1}{x+3}-\frac{1}{x}=\frac{1}{2017}\)

\(\frac{1}{x}-\frac{1}{x+3}-\frac{1}{x}=\frac{1}{2017}\)

\(-\frac{1}{x+3}=\frac{1}{2017}\)

\(-2017=x+3\)

\(x=-2020\)

1.

a)\(\left(x-\frac{1}{2}\right)^2=0\)

\(\Leftrightarrow x-\frac{1}{2}=0\Leftrightarrow x=\frac{1}{2}\)

b)\(\left(x-2\right)^2=1\Leftrightarrow\orbr{\begin{cases}x-2=\sqrt{1}\\x-2=-\sqrt{1}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\sqrt{1}+2\\x=-\sqrt{1}+2\end{cases}}\)

Mấy câu kia tương tự,bạn tự làm nha :)) 

\(a,5x^3-3x^2+x-x^3-4x^2-x\)

\(=4x^3-7x^2\)

\(b,y^2+2y-2y^2-3y+3\)

\(=-y^2-y+3\)

\(c,\frac{1}{2}x^3-2x^2-4x-\frac{1}{2}x^3-x+1\)

\(=\frac{1}{6}x^3-2x^2-5x+1\)

\(d,\frac{3}{4}xy^2-\frac{1}{2}y^2-\left(-\frac{1}{4}xy^2\right)+\frac{2}{3}y^2\)

\(=xy^2+\frac{1}{6}y^2\)

\(e,2xy-2yz.z+xy+\frac{1}{2}z^2y+2zy\cdot y\)

\(=3xy-\frac{3}{2}z^2y+2zy^2\)

\(g,3^n+3^{n+2}\)

\(=3^n+3^n.3^2\)

\(=3^n\cdot10\)

\(h,1,5\cdot2^n-2^{n-1}\)

\(=1,5\cdot2^n-2^n\cdot\frac{1}{2}\)

\(=2^n\cdot1\)

\(=2^n\)

\(i,2^n-2^n-2\)

\(=-2\)

\(k,\frac{2}{3}\cdot3^n-3^{n-1}\)

\(=\frac{2}{3}\cdot3^n-3^n\cdot\frac{1}{3}\)

\(=3^n\cdot\frac{1}{3}\)

\(=\frac{3^n}{3}\)

sẵn bán nick luôn :)

Cái này hơi lâu thật,nhưng kiên trì 1 chút là đc ngay thôi bn !

a, \(5x^3-3x+x-x^3-4x^2-x=4x^3-3x-4x^2\)

b, \(y^2+2y-2y^2-3y+3=-y^2-y+3\)

c, \(\frac{1}{2}x^3-2x^2-4x-\frac{1}{2}x^3-x+1=-2x^2-5x+1\)

d, \(\frac{3}{4}xy^2-\frac{1}{2}y^2-\left(-\frac{1}{4}xy^2\right)+\frac{2}{3}y^2=\frac{3}{4}xy^2-\frac{1}{2}y^2+\frac{1}{4}xy^2+\frac{2}{3}y^2=xy^2+\frac{1}{6}y^2\)

e, \(2xy-2yz.z+xy+\frac{1}{2}z^2y+2zy.y=2xy-2yz^2+xy+\frac{1}{2}z^2y+2zy^2=3xy-\frac{3}{2}z^2y+2zy^2\)

g, \(3^n+3^{n+2}\)( chắc tối giản rồi,ko phân tích đc nữa. )

h, \(1,5.2^n-2^{n-1}\)( chắc tối giản rồi,ko phân tích đc nữa. )

i, \(2^n-2^n-2=-2\)

k, \(\frac{2}{3}.3^n-3^{n-1}\)( chắc tối giản rồi,ko phân tích đc nữa. )

Có j sai,mong mọi người góp ý,thông cảm ạ.

Bạn tham khảo ở đây nhé, mình làm rồi đấy: https://olm.vn/hoi-dap/detail/211418926066.html

a/ \(\left(\frac{-2}{3}\right)^4:24=\frac{16}{81}:24=\frac{2}{243}\)

b/ \(\left(\frac{3}{4}\right)^3.4^4=\frac{27}{64}.256=108\)

c/ \(\frac{3.0,8^5}{2,4^4}=\frac{3.0,32768}{33,1776}=\frac{0,98304}{33,1776}=\frac{4}{135}\)

d/ \(\frac{3^3-0,9^5}{2,7^4}=\frac{27-0,59049}{53,1441}=\frac{26,40951}{53,1441}=0,4969415231\)

e/\(\left(\frac{-7}{2}\right)^2+\left(\frac{-3}{4}\right)^3.64-\left(\frac{-61}{5}\right)\)

\(=\frac{49}{4}+\frac{-27}{64}.64+\frac{61}{5}\)

\(=12,25-27+12,2\)

\(=-2,55\)

f/ \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}=\frac{2^{10}}{2^{10}}-\frac{2^5.5^3.3^3}{2^3.3^3.5^2.2^2}\)

                                      \(=1-\frac{2^5.5^3.3^3}{2^5.3^3.5^2}=1-\frac{5}{1}=-4\)

                                       \(\)

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