a: \(B=\frac{1}{1\cdot2}+\frac{1}{3\cdot4}+\cdots+\frac{1}{99\cdot100}\)

\(=1-\frac12+\frac13-\frac14+\cdots+\frac{1}{99}-\frac{1}{100}\)

\(=1+\frac12+\cdots+\frac{1}{100}-2\left(\frac12+\frac14+\cdots+\frac{1}{100}\right)\)

\(=1+\frac12+\cdots+\frac{1}{100}-1-\frac12-\cdots-\frac{1}{50}\)

\(=\frac{1}{51}+\frac{1}{52}+\cdots+\frac{1}{100}\)

=A

=>\(\frac{A}{B}=1\)

b: \(A=\frac{34}{7\cdot13}+\frac{51}{13\cdot22}+\frac{85}{22\cdot37}+\frac{68}{37\cdot49}\)

\(=17\left(\frac{2}{7\cdot13}+\frac{3}{13\cdot22}+\frac{5}{22\cdot37}+\frac{4}{37\cdot49}\right)\)

\(=\frac{17}{3}\left(\frac{6}{7\cdot13}+\frac{9}{13\cdot22}+\frac{15}{22\cdot37}+\frac{12}{37\cdot49}\right)\)

\(=\frac{17}{3}\left(\frac17-\frac{1}{13}+\frac{1}{13}-\frac{1}{22}+\frac{1}{22}-\frac{1}{37}+\frac{1}{37}-\frac{1}{49}\right)\)

\(=\frac{17}{3}\left(\frac17-\frac{1}{49}\right)\)

Ta có: \(B=\frac{39}{7\cdot16}+\frac{65}{16\cdot31}+\frac{52}{31\cdot43}+\frac{26}{43\cdot49}\)

\(=13\left(\frac{3}{7\cdot16}+\frac{5}{16\cdot31}+\frac{4}{31\cdot43}+\frac{2}{43\cdot49}\right)\)

\(=\frac{13}{3}\left(\frac{9}{7\cdot16}+\frac{15}{16\cdot31}+\frac{12}{31\cdot43}+\frac{6}{43\cdot49}\right)\)

\(=\frac{13}{3}\left(\frac17-\frac{1}{16}+\frac{1}{16}-\frac{1}{31}+\frac{1}{31}-\frac{1}{43}+\frac{1}{43}-\frac{1}{49}\right)\)

\(=\frac{13}{3}\left(\frac17-\frac{1}{49}\right)\)

Do đó: \(\frac{A}{B}=\frac{17}{3}:\frac{13}{3}=\frac{17}{13}\)

d: \(\Leftrightarrow x+5=5\)

hay x=0

\(a.\dfrac{2}{3}-\dfrac{5}{7}.\dfrac{14}{25}=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10}{15}-\dfrac{6}{15}=\dfrac{14}{15}\)

\(b.\dfrac{-2}{5}.\dfrac{5}{8}+\dfrac{5}{8}.\dfrac{3}{5}=\dfrac{5}{8}.\left(\dfrac{-2}{5}+\dfrac{3}{5}\right)=\dfrac{5}{8}.\dfrac{1}{5}=\dfrac{1}{8}\)

\(c.25\%-1\dfrac{1}{2}+0,5.\dfrac{12}{5}=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{6}{5}=-\dfrac{1}{20}\)

úi,mình kẻm ơn nhìu ạ :333

KHO THE

\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)

\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)

\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)

Câu đăng như này thì khoảng 3 - 5 câu 1 lượt thôi nha :)) 

Bài 1.

\(a,\dfrac{1}{3}+\dfrac{1}{4}=\dfrac{4}{12}+\dfrac{3}{12}=\dfrac{7}{12}\)

\(b,\dfrac{-2}{5}+\dfrac{7}{21}=\dfrac{-42}{105}+\dfrac{35}{105}=\dfrac{-77}{105}=\dfrac{-11}{15}\)

\(c,\dfrac{3}{8}+\dfrac{-5}{6}=\dfrac{18}{48}+\dfrac{-40}{48}=\dfrac{-22}{48}=\dfrac{-11}{24}\)

\(d,\dfrac{-3}{4}+\dfrac{2}{5}=\dfrac{-15}{20}+\dfrac{8}{20}=\dfrac{-7}{20}\)

\(e,\dfrac{1}{6}+\dfrac{-3}{2}=\dfrac{2}{12}+\dfrac{-18}{12}=\dfrac{16}{12}=\dfrac{4}{3}\)

\(f,\dfrac{-2}{5}+\dfrac{-4}{3}=\dfrac{-6}{15}+\dfrac{-20}{15}=\dfrac{-26}{15}\)

\(g,\dfrac{1}{8}+\dfrac{-3}{4}=\dfrac{4}{32}+\dfrac{-24}{32}=\dfrac{20}{32}=\dfrac{5}{8}\)

\(h,\dfrac{-3}{4}+\dfrac{3}{7}=\dfrac{-21}{28}+\dfrac{12}{28}=\dfrac{-9}{28}\)

\(i,\dfrac{-3}{4}+\dfrac{-4}{5}=\dfrac{-15}{20}+\dfrac{-16}{20}=\dfrac{-31}{20}\)

\(k,\dfrac{-5}{25}+\dfrac{-7}{14}=\dfrac{-70}{350}+\dfrac{-175}{350}=\dfrac{-245}{350}=\dfrac{-7}{10}\)

\(l,\dfrac{6}{21}+\dfrac{-3}{15}=\dfrac{90}{315}+\dfrac{-63}{315}=\dfrac{27}{315}=\dfrac{3}{35}\)

\(m,\dfrac{3}{4}-\dfrac{5}{8}+\dfrac{1}{2}=\dfrac{24}{32}-\dfrac{20}{32}+\dfrac{1}{2}=\dfrac{4}{32}+\dfrac{1}{2}=\dfrac{1}{8}+\dfrac{1}{2}=\dfrac{2}{16}+\dfrac{8}{16}=\dfrac{10}{16}=\dfrac{5}{8}\)

\(n,\dfrac{-3}{12}-\dfrac{1}{-4}+\dfrac{-2}{6}=\dfrac{-1}{4}-\dfrac{1}{-4}+\dfrac{-1}{3}=0+\dfrac{-1}{3}=\dfrac{-1}{3}\)

\(p,\dfrac{1}{3}+\dfrac{-3}{4}-\dfrac{5}{12}=\dfrac{4}{12}+\dfrac{-9}{12}-\dfrac{5}{12}=\dfrac{-5}{12}-\dfrac{5}{12}=\dfrac{-10}{12}=\dfrac{-5}{6}\)

Bài 2:

\(a,\dfrac{3}{5}+x=\dfrac{5}{6}\)

\(x=\dfrac{5}{6}-\dfrac{3}{5}\)

\(x=\dfrac{7}{30}\)

\(b,x-\dfrac{1}{4}=\dfrac{-5}{8}\)

\(x=\dfrac{-5}{8}+\dfrac{1}{4}\)

\(x=\dfrac{-3}{8}\)

\(c,x-\dfrac{2}{3}=\dfrac{7}{12}\)

\(x=\dfrac{7}{12}+\dfrac{2}{3}\)

\(x=\dfrac{5}{4}\)

\(d,x+\dfrac{-7}{15}=-1\dfrac{1}{20}\)

\(x=-1\dfrac{1}{20}-\dfrac{-7}{15}\)

\(x=\dfrac{-7}{12}\)

\(e,x-\dfrac{1}{2}=\dfrac{-3}{4}\)

\(x=\dfrac{-3}{4}+\dfrac{1}{2}\)

\(x=\dfrac{-1}{4}\)

\(f,x-\dfrac{3}{4}=\dfrac{1}{2}\)

\(x=\dfrac{1}{2}+\dfrac{3}{4}\)

\(x=\dfrac{5}{4}\)

\(g,x-\dfrac{1}{4}=\dfrac{5}{8}\cdot\dfrac{2}{3}\)

\(x-\dfrac{1}{4}=\dfrac{5}{12}\)

\(x=\dfrac{5}{12}+\dfrac{1}{4}\)

\(x=\dfrac{2}{3}\)

\(h,\dfrac{4}{5}-x=\dfrac{-8}{35}\)

\(x=\dfrac{4}{5}-\dfrac{-8}{35}\)

\(x=\dfrac{36}{35}\)

#YVA

x=(-59,-58,.......,60,61)

       cho mình đúng nha

Trả lời chi tiết cho mình đk

10 - [(8² - 48) x 5 + (2³ x 10 + 8)] : 28

= 10 - [( 64 - 48) x 5 + (8 x 10 + 8)] : 28

= 10 - (16 x 5 + 88) : 28

= 10 - (80 + 88) : 28

= 10 - 168 : 28

= 10 - 6 ( Nhân chia trước cộng trừ sau bạn nhá)

= 4

Bạn nên thử lại bằng máy tính vì mình tính nhẩm nên chưa chắc đúng đâu bạn ạ! Nhưng dù đúng hay sai thì cách làm là vậy.

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