a) -76

b) 37

c) 156

d) -9

e) 74

g) 52

i) -98

h) -33

k) 78

m) -150

bạn giải cụ thể cái cho mình rồi mình k cho

giải đi

a) (-48):2+26x(-2)

= (-24) + (-52)

= -76                             

b) (-96):(-2)+11x(-)?????

SAI ĐỀ

c) (-58)x(-2)+(-5)x(-8)

=116+40

=156

d) 3x(-7)-4x(-3)

=( -21) - (-12)

= (-21)+12

= -9

e) (-8)x(-4)+21x2

=32+42

=74

g) (-16)+32+(-18)x(-2)

= (-16) + 32 + 36

= 16 + 18

= 34

i) (-48)+(-2)x7+(-56):2+4x(-2)

= (-48)+(-14)+(-28)+(-8)

=(-62)+(-28)+(-8)

=(-90)+(-8)

=-98

h) (-16)-18+(-11)x(-2)+(-21)

=(-16)-18+22+(-21)

=(-34)+22-21

=(-34)+1

=-33

k) -18-(-3)x2+32-(-58)

=(-18)+3 x 2 + 32 + 58

=(-18) +6 +32 +58

=(-12)+32+58

= 20+58

=78

m) -2x8-72+31x(-2)

=(-16)-72+(-62)

=(-88)+(-62)

=-150

16-2x=40-3x

40-16=3x-2x

24=x

x=24

2x-16=40+x

  2x-x=40+16

      x=56

tick nhé cảm ơn

Bài 1 Tìm x biết:

a)65-(29-x)=32

65 -29+x=31

x=31-65+29

x=-5

b)(x+5)-(x+23)=x-34

x+5 -x +23 = x-34

(x-x)+ (23+5)=x-34

0+28=x-34

28=x-34

28+34=x

62=x

=>x=62

c)(16-x)+(x-38)=x+44

16-x+x-38=x+44

-x+x-x=44-16+38

-x=36

=>x=-36

d)-12+3(-x+7)=-18

3(-x+7)=-18+12

3(-x+7)=-6

-x+7=-6:3

-x+7=-2

-x=-2-7

-x=-9

=>x=9

Baif 2

d)|7-x|=10

=> \(\left[{}\begin{matrix}7-x=10\\7-x=-10\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=7-10\\x=-10-7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=-3\\x=-17\end{matrix}\right.\)

e)(x-6).(7-2x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}x-6=0\\7-2x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+6\\2x=7\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=7:2\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=6\\x=3,5\end{matrix}\right.\)

f)(9-x).(2x+8)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}9-x=0\\2x+8=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0+9\\2x=-8\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=9\\x=-4\end{matrix}\right.\)

g)x(-x+8).(-3x-18)=0

\(\Rightarrow\) \(\left[{}\begin{matrix}x=0\\-x+8=0\\-3x-18=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=0+8\\-3x=0+18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\-x=8\\-3x=18\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=18:\left(-3\right)\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=0\\x=-8\\x=-6\end{matrix}\right.\)

h)(-x+8).(x-54).(-24-x)=0

\(\Rightarrow\)\(\left[{}\begin{matrix}-x+8=0\\x-54=0\\-24-x=0\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}-x=8\\x=0+54\\-x=0+24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\-x=24\end{matrix}\right.\)

\(\Rightarrow\)\(\left[{}\begin{matrix}x=8\\x=54\\x=-24\end{matrix}\right.\)

2x-16=40+x=>x=56

16-2x=40-3x=>x=24

2(4x-2x)-7x=16=>x=-5,(3)

-2(-3-4x)-3(3x+7)=31=>x=-46

9(x+4)-4(2x+15)=3=>x=27

-2[x+(-7)]+(x-3)=12=>x=-1

(x-7)(x+2005)=0 =>x=7;-2005

bạn câu đầu tiền là 0,2 hay 02 vậy ạ

bạn ơi câu đầu tiên là 0 nhé ! mình viết liền quá ! Xin lỗi bạn 

a)\(\text{ 4x - 15 = -75 - x}\)

\(4x-15+75+x=0\)

\(5x+60=0\)

\(5x=-60\)

\(x=-14\)

Vậy....

Thêm dấu suy ra trc mỗi dòng nha

Học tốt

b)\(|2x-7|+2=13\)

\(|2x-7|=11\)

\(\Leftrightarrow\hept{\begin{cases}2x-7=11\\2x-7=-11\end{cases}\Leftrightarrow\hept{\begin{cases}2x=18\\2x=4\end{cases}\Leftrightarrow}\hept{\begin{cases}x=9\\x=2\end{cases}}}\)

vậy x=9 hoặc x=2