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Question

Bài tập Toán giup mình với cảm ơn rất nhiều

Nguyễn Ngọc Thảo Vy · Accepted Answer

1.(đề đầu)

1. SO3

2.$P_2O_5+3H_2O\rightarrow2H_3PO_4$

3.$CaO+2HCl\rightarrow CaCl_2+H_2O$

2.

(1)$CaO+H_2O\rightarrow Ca\left(OH\right)_2$

(2)$Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O$

(3)CaCO₃ --nhiệt>CaO+H₂O

(4)$CaO+2HCl\rightarrow CaCl_2+H_2O$

(5)$3CaCl_2+2Na_3PO_4\rightarrow Ca_3\left(PO_4\right)_2+6NaCl$

3.

a,$SO_3+H_2O\rightarrow H_2SO_4$

b,$n_{SO_3}=\dfrac{8}{80}=0,1\left(mol\right)$

Theo PTHH: $n_{H2SO4}=n_{SO3}=0,1\left(mol\right)$

$\Rightarrow C_{M\left(SO3\right)}=\dfrac{0,1}{0,25}=0,4\left(M\right)$

Câu trả lời:

1.(đề đầu)

1. SO3

2.$P_2O_5+3H_2O\rightarrow2H_3PO_4$

3.$CaO+2HCl\rightarrow CaCl_2+H_2O$

2.

(1)$CaO+H_2O\rightarrow Ca\left(OH\right)_2$

(2)$Ca\left(OH\right)_2+CO_2\rightarrow CaCO_3+H_2O$

(3)CaCO₃ --nhiệt>CaO+H₂O

(4)$CaO+2HCl\rightarrow CaCl_2+H_2O$

(5)$3CaCl_2+2Na_3PO_4\rightarrow Ca_3\left(PO_4\right)_2+6NaCl$

3.

a,$SO_3+H_2O\rightarrow H_2SO_4$

b,$n_{SO_3}=\dfrac{8}{80}=0,1\left(mol\right)$

Theo PTHH: $n_{H2SO4}=n_{SO3}=0,1\left(mol\right)$

$\Rightarrow C_{M\left(SO3\right)}=\dfrac{0,1}{0,25}=0,4\left(M\right)$

Nguyễn Ngọc Thảo Vy · Answer

1(Đề 2)

1.H2SO4

2.BaO

3.CuO

2.

(1)CaCO3---nhiệt-->CaO+H2O

(2)CaO+H2O--->Ca(OH)2

(3)Ca(OH)2+CO2--->CaCO3+H2O

(4)CaO+2HCl--->CaCl2+H2O

(5)Ca(OH)2+Mg(NO3)2---->Ca(NO3)2+Mg(OH)2

3.

a, SO3+H2O--->H2SO4

b,$n_{SO3}=\dfrac{16}{80}=0,2\left(mol\right)$

Theo PTHH:$n_{H2SO4}=n_{SO3}=0,2\left(mol\right)$

$\Rightarrow C_{M\left(H2SO4\right)}=\dfrac{0,2}{0,5}=0,4\left(mol\right)$