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2)a)
(-125)+100-80+125-20
=(-125+125)+(-80+-20)+100
=0+-100+100=0
b)
-30-(95+(-40)+5+(-30)
=-30-((95+5)+(-40+-30)
=-30-(100+(-70))
=-30-30=-60
Nếu bài dễ thì cố gắng tự làm bạn nhé.
Bài 1:
a) \(2x+3=5\)
\(\Leftrightarrow2x=5-3=2\)
\(\Leftrightarrow x=2:2=1\)
Vậy: x=1
b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)
\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)
Vậy: \(x\in\left\{3;0\right\}\)
c) \(3x+4=2x-7\)
\(\Leftrightarrow2x-3x=7+4\)
\(\Leftrightarrow-1x=11\)
\(\Leftrightarrow x=-11\)
Vậy: x=-11
d) \(\left(4x-1\right)^3=27\)\(=3^3\)
\(\Rightarrow4x-1=3\)
\(\Leftrightarrow4x=3+1=4\)
\(\Leftrightarrow x=4:4=1\)
Vậy: x=1
e) \(\left(x-7\right).2=3.\left(2x+4\right)\)
\(\Leftrightarrow2x-14=6x+12\)
\(\Leftrightarrow2x-6x=12+14\)
\(\Leftrightarrow-4x=26\)
\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)
Vậy: \(x=\frac{13}{-2}\)
a)7(x-1)+10=80 b)14-3(x+5)=2 c)65-5(3x-1)=15 d)4(12-3x)-9=3
7(x-1)=80-10 3(x+5)=14-2 5(3x-1)=65-15 4(12-3x)=3+9
7(x-1)=70 3(x+5)=12 5(3x-1)=50 4(12-3x)=12
(x-1)=70:7 (x+5)=12:3 (3x-1)=50:5 (12-3x)=12:4
x-1=10 x+5=4 3x-1=10 12-3x=3
x=10+1 x=4-5 3x=10+1 3x=12-3
x=11 x=(-1) 3x=11 3x=9
x=11:3 x=9:3
x=3,6...7 x=3
a) 60 - 4(x + 5) = 12
4(x + 5) = 60 - 12
4(x + 5) = 48
x + 5 = 48 : 4
x + 5 = 12
x = 7
Bài 1:
a: \(\Leftrightarrow\dfrac{6}{7}\left(\dfrac{7}{12}x-\dfrac{14}{3}\right)=\dfrac{5}{9}-\dfrac{9}{8}=\dfrac{-41}{72}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}-\dfrac{14}{3}=-\dfrac{287}{432}\)
\(\Leftrightarrow x\cdot\dfrac{7}{12}=\dfrac{1729}{432}\)
hay \(x=\dfrac{247}{36}\)
b: \(\Leftrightarrow\dfrac{1}{5}:x=\dfrac{1}{5}+\dfrac{3}{14}-\dfrac{8}{7}=\dfrac{-51}{70}\)
hay \(x=-\dfrac{14}{51}\)
c: đề sai rồi bạn
Cho mình câu chả lời sớm nhất vào 4h30 chiều ngày 28/9/2021
a: \(x+40\%\cdot x=5\)
=>\(x\left(1+0,4\right)=5\)
=>1,4x=5
=>\(x=\dfrac{5}{1,4}=\dfrac{50}{14}=\dfrac{25}{7}\)
b: \(1,2x-80\%x=\dfrac{1}{4}\)
=>1,2x-0,8x=0,25
=>0,4x=0,25
=>\(x=\dfrac{0.25}{0.4}=\dfrac{25}{40}=\dfrac{5}{8}\)
d: \(x\cdot x-\dfrac{1}{9}=\dfrac{1}{3}\)
=>\(x^2=\dfrac{1}{9}+\dfrac{1}{3}=\dfrac{4}{9}\)
=>\(\left[{}\begin{matrix}x=\dfrac{2}{3}\\x=-\dfrac{2}{3}\end{matrix}\right.\)