a, (x-1)³ - x(x-1)² = 5(2-x) - 11(x+2)

b, (x-2)³ + (3x-1)(3x+1) = (x+1)³

c, $\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{5}$

d, $\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}=\frac{13x+4}{21}$

e, $\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}$

_Giúp mình với!_

a, (x-1)³ - x(x-1)² = 5(2-x) - 11(x+2)

b, (x-2)³ + (3x-1)(3x+1) = (x+1)³

c, $\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{5}$

d, $\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}=\frac{13x+4}{21}$

e, $\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}$

a, (x-1)³ - x(x-1)² = 5(2-x) - 11(x+2)

b, (x-2)³ + (3x-1)(3x+1) = (x+1)³

c, $\frac{2x-1}{5}-\frac{x-2}{3}=\frac{x+7}{5}$$\frac{\mathrm{<strong>2</strong>}\mathrm{<strong>x</strong>}<strong>-</strong>\mathrm{<strong>1</strong>}}{\mathrm{<strong>5</strong>}}<strong>-</strong>\frac{\mathrm{<strong>x</strong>}<strong>-</strong>\mathrm{<strong>2</strong>}}{\mathrm{<strong>3</strong>}}<strong>=</strong>\frac{\mathrm{<strong>x</strong>}<strong>+</strong>\mathrm{<strong>7</strong>}}{\mathrm{<strong>5</strong>}}$

d, $\frac{2\left(x-3\right)}{7}+\frac{x-5}{3}=\frac{13x+4}{21}$$\frac{\mathrm{<strong>2</strong>}<strong>(</strong>\mathrm{<strong>x</strong>}<strong>-</strong>\mathrm{<strong>3</strong>}<strong>)</strong>}{\mathrm{<strong>7</strong>}}<strong>+</strong>\frac{\mathrm{<strong>x</strong>}<strong>-</strong>\mathrm{<strong>5</strong>}}{\mathrm{<strong>3</strong>}}<strong>=</strong>\frac{\mathrm{<strong>13</strong>}\mathrm{<strong>x</strong>}<strong>+</strong>\mathrm{<strong>4</strong>}}{\mathrm{<strong>21</strong>}}$

e, $\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}$

16" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-table; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; overflow-wrap:normal; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal" class="MathJax_CHTML mjx-chtml">1 1−x+11+x+11+x2+11+x4+11+x8+11+x16

Xác định a để đa thức $x^3+x^2+a-x$ chia hết cho ${\left(x+1\right)}^2$

Cho các phân thức:

A= $\frac{2x+6}{\left(x+3\right)\left(x+2\right)}$ D= $\frac{x^2+4x+4}{2x+4}$

B= $\frac{x^2-9}{x^2-6x+9}$ E= $\frac{2x-x^2}{x^2-4}$

C= $\frac{9x^2-16}{3x^2-4x}$ F= $\frac{3x^2+6x+12}{x^3-8}$

a) Với điều kiện nào của x thì phân thức trên được xác định

b) Tìm x để giá trị của các phân thức trên =0

c) Rút gọn phân thức trên

- x4&#x2212;(x+1)x3+(x+1)x2&#x2212;(x+1)x+4(x&gt;=0)" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-table; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">x4−(x+1)x3+(x+1)x2−(x+1)x+4(x>=0)

- $x^2-3x^2-4x+12$

$x^4-4-4x^2-x^2$

Cho M=2x+2" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">2x+2${\displaystyle \frac{2}{x+2}}$+1x&#x2212;2" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">1x−2${\displaystyle \frac{1}{x-2}}$$-$x2x4&#x2212;4" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">x2x4−4${\displaystyle \frac{x^2}{x^4-4}}$

a) Rút gọn M

b) Tính giá trị của M khi x thỏa mãn $\left|2x-3\right|$=7 để M>0

c) Tìm x để M >0

d) Tìm x ∈ Z để M đạt giá trị nguyên.

giải phương trình sau

3(x&#x2212;11)4=3(x+1)5=2(2x&#x2212;5)10" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-table; float:none; font-size:20.34px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">3 (x−11)4=3(x+1)5=2(2x−5)10

cho các số nguyên a,b,c,d khác 0 thỏa mãn ab=cd

cm: 2014+b2014+c2014+d2014" role="presentation" style="border:0px; box-sizing:border-box; direction:ltr; display:inline-block; float:none; font-size:22.5px; font-style:normal; font-weight:normal; letter-spacing:normal; line-height:0; margin:0px; max-height:none; max-width:none; min-height:0px; min-width:0px; padding:1px 0px; position:relative; text-align:left; text-indent:0px; text-transform:none; white-space:nowrap; word-spacing:normal; word-wrap:normal" class="MathJax_CHTML mjx-chtml">a2014+b2014+c2014+d2014$a^{2014}+b^{2014}+c^{2014}+d^{2014}$ là hợp số