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A . 89 - ( 73 - x ) = 20
73 - x = 89 - 20
73 - x = 69
\(\Rightarrow\)x = 4
B .
a,\(5^3.2-100:4+2^3.5\)
= 125 . 2 - 25 + 8 . 5
= 250 - 25 + 40
= 265
b, \(6^2:9+50.2-3^3.3\)
= 36 : 9 + 100 - 27 . 3
= 4 + 100 - 81
= 23
b) \(5^3\cdot2-100:4+2^3\cdot5\)
\(=125\cdot2-25+8\cdot5\)
\(=250-25+40\)
\(=225+40=265\)
c) \(6^2:9+50\cdot2+3^3-3\)
\(=36:9+100+27-3\)
\(=4+100+27-3\)
\(=104+27-3=131-3=128\)
d) \(3^2\cdot5+2^3\cdot10-81:3\)
\(=9\cdot5+8\cdot10-27\)
\(=45+80-27\)
\(=125-27=98\)
e) \(5^{13}:5^{10}-25\cdot2^2\)
\(=5^{13-10}-5^2\cdot2^2\)
\(=5^3-\left(5\cdot2\right)^2\)
\(=125-10^2\)
\(=125-100=25\)
f) \(20:2^2+5^9:5^8\)
\(=20:4+5^{9-8}\)
\(=5+5^1=5+5=10\)
g) \(100:5^2+7\cdot3^2\)
\(=10^2:5^2+7\cdot9\)
\(=\left(10:5\right)^2+63\)
\(=2^2+63=4+63=67\)
h) \(84:4+3^9:3^7+5^0\)
\(=21+3^{9-7}+1\)
\(=21+3^2+1\)
\(=21+9+1=30+1=31\)
i) \(29-\left[16+3\cdot\left(51-49\right)\right]\)
\(=29-\left[16+3\cdot2\right]\)
\(=29-\left[16+6\right]\)
\(=29-22=7\)
j) \(\left(15^{19}:5^{17}+3\right)\cdot0:7\)
\(=\left[\left(3\cdot5\right)^{19}:5^{17}+3\right]\cdot0\)
Vì số nào nhân cho 0 cũng bằng 0 nên giá trị biểu thức trên bằng 0
k) \(7^9:7^7-3^2+2^3\cdot5\)
\(=7^{9-7}-9+8\cdot5\)
\(=7^2-9+40\)
\(=49-9+40=40+40=80\)
l) \(1200:2+6^2\cdot2^1+18\)
\(=600+36\cdot2+18\)
\(=600+72+18\)
\(=600+\left(72+18\right)=600+90=690\)
m) \(5^9:5^7+70:14-20\)
\(=5^{9-7}+5-20\)
\(=5^2+5-20\)
\(25+5-20=30-20=10\)
Những câu sau mình làm sau nhé bạn!!!!!!!
\(\dfrac{1}{2}+\dfrac{3}{4}-\left(\dfrac{3}{4}-\dfrac{4}{5}\right)\)
=\(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}\)
=\(\left(\dfrac{1}{2}+\dfrac{4}{5}\right)+\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
=\(\left(\dfrac{5}{10}+\dfrac{8}{10}\right)+0\)
=\(\dfrac{13}{10}\)
\(-\dfrac{7}{25}.\dfrac{11}{13}+\left(-\dfrac{7}{25}\right).\dfrac{2}{13}-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.\cdot\left(\dfrac{11}{13}+\dfrac{2}{13}\right)-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}.1-\dfrac{18}{25}\)
=\(-\dfrac{7}{25}-\dfrac{18}{25}\)
=\(-\dfrac{25}{25}\) = \(-1\)
- 22.32.5:22.3-32=3.5-32=15-9=6
- 2.52-22.32:32=2.(52-2)=2.(25-2)=46
3. 33.19-33.12=33.(19-12)=33.7=189
4. 3.52-16:22=3.52-24:22=3.25-4=75-4=71
Câu a:
7/10.4/9 + 3/10.4/9 - 1 7/9
= 4/9.(7/10 + 3/10) - 16/9
= 4/9 - 16/9
= - 12/9
= - 4/3
Câu b:
- 5/6 + 4/9.(5/4 - 2/3).(-3)^2 + 5/9.30%
= - 5/6 + [5/9 - 8/27].9 + 5/9.3/10
= - 5/6 + 5 - 8/3 + 1/6
= (-5/6 + 1/6) - 8/3 + 5
= - 4/6 - 8/3 + 15/3
= - 2/3 - 8/3 + 15/3
= - 10/3 + 15/3
= 5/3
a,\(\frac{7}{10}\cdot\frac{4}{9}+\frac{3}{10}\cdot\frac{4}{9}-1\frac{7}{9}\)
\(=\frac{14}{45}+\frac{2}{15}-\frac{16}{9}\)
\(=\frac{14}{45}+\frac{6}{45}-\frac{80}{45}\)
\(=\frac{-60}{45}=\frac{-4}{3}\)
b,\(\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{5}{4}-\frac{2}{3}\right)\cdot\left(-3\right)^2+\frac{5}{9}\cdot30\%\)
\(=\frac{-5}{6}+\frac{4}{9}\cdot\left(\frac{7}{12}\right)\cdot9+\frac{5}{9}\cdot\frac{3}{10}\)
\(=\frac{-5}{6}+\frac{7}{3}+\frac{1}{6}\)
\(=\frac{-5}{6}+\frac{14}{6}+\frac{1}{6}\)
=\(=\frac{10}{6}=\frac{5}{3}\)
Câu c:
1/2017.(1/3 - 7/12 + 1/4) - (6 2/3 - 1,5.2^2) :5/6
= 1/2017.(4/12 - 7/12 + 3/12) - (20/3 - 1,5x 4) : 5/6
= 1/2017.0 - (20/3 - 6) x 6/5
= 0 - (20/3 - 18/3) x 6/5
= - 2/3 x 6/5
= - 4/5
1. 53 = 5.5.5 = 125
2. 27 = 2.2.2.2.2.2.2 = 128
3. 44 = 4.4.4.4 = 256
4. 73 = 7.7.7 = 343
6. 35 = 243
7. 26 = 64
8. 34 = 81
9. 83 = 512
11. 132 = 169
12. 112 = 121
13. 142 = 196
14. 152 = 225
16. 172 = 289
17. 182 = 324
18. 192 = 361
19. 202 = 400
21. 104 = 10000
22. 105 = 100000
23. 106 = 1000000
24. 107 = 10000000
Câu a:
2.(x + 2/5) + 1 1 /4 = 11/20
2x + 4/5 + 5/4 = 11/20
2x = 11/20 - 5/4 - 4/5
2x = 11/20 - 25/20 - 16/20
2x = -30/20
2x = -3/2
x = -3/2 : 2
x = - 3/4
Vậy x = - 3/4
Câu b:
x - 1 1/8 - 2/3x - 5/6x = 75%
(x - 2/3x - 5/6x) = 75% + 1 1/8
x (1 - 2/3 - 5/6) = 3/4 + 9/8
x (6/6 - 4/6 - 5/6) = 6/8 + 9/8
x.(-1/2) = 15/8
x = 15/8 : (-1/2)
x = 15/8 x (-2)
= -15/4
a) \(2.\left(x+\frac{2}{5}\right)+1\frac{1}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)+\frac{5}{4}=\frac{11}{20}\)
\(2.\left(x+\frac{2}{5}\right)=\frac{-7}{10}\)
\(x+\frac{2}{5}=\frac{-7}{20}\)
\(x=\frac{-13}{20}\)
Vậy \(x=\frac{-13}{20}\)
b)\(x-1\frac{1}{8}-\frac{2}{3}x-\frac{5}{6}x=75\%\)
\(\left(x-\frac{2}{3}x-\frac{5}{6}x\right)-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x-\frac{9}{8}=\frac{3}{4}\)
\(\frac{-1}{2}x=\frac{15}{8}\)
\(x=\frac{-15}{4}\)
Vậy \(x=\frac{-15}{4}\)
\(\left(\dfrac{-9}{24}-\dfrac{6}{24}+\dfrac{10}{24}\right)\times\dfrac{3}{2}\)
\(=\left(\dfrac{-5}{24}\right)\times\dfrac{3}{2}\)
\(=\dfrac{-5}{16}\)
\(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{3}{4}+\dfrac{4}{5}\)
\(=\dfrac{5}{10}+\dfrac{8}{10}\)
\(=\dfrac{13}{10}\)
\(\dfrac{1}{\dfrac{13}{15}}\times\dfrac{3}{4}-\left(\dfrac{11}{20}-\dfrac{5}{20}\right)\times\dfrac{7}{5}\)
\(=\dfrac{15}{13}\times\dfrac{3}{4}-\dfrac{3}{10}\times\dfrac{7}{5}\)
\(=\dfrac{45}{52}-\dfrac{21}{50}\)
\(=\dfrac{1125}{1300}-\dfrac{546}{1300}\)
\(=\dfrac{579}{1300}\)
\(5E=5^2+5^3+...+5^{501}\)
\(5E-E=5^{501}-5\)
\(4E=5^{501}-5\)
\(E=\dfrac{5^{501}-5}{4}\)