A = ( - 5)^32 . 20^43 / ( -8 )^29 . 125^25

   = 5^32 . 20^43 / ( -8 )^29 . 125^25

   = 5^32 . 20^43 / ( -8 )^29 . ( 5^3 )^25

   = 5^32 . 20^43 / ( -8 )^29 . 5^75

   = 20^43 / ( -8 )^29 . 5^43

   = ( 4 . 5 )^43 / ( -8 )^29 . 5^43

   = 4^43 . 5^43 / ( -8 )^29 . 5^43

   = 4^43 / ( -8 )^29

   = ( 2^2 )^43 / ( -2^3 )^29

   = 2^86 / -2^87

AI GIÚP MÒNH VỚI !

a: \(\frac{4^{30}\cdot3^{43}}{2^{53}\cdot27^{15}}\)

\(=\frac{\left(2^2\right)^{30}\cdot3^{43}}{2^{53}\cdot\left(3^3\right)^{15}}\)

\(=\frac{2^{60}}{2^{53}}\cdot\frac{3^{43}}{3^{45}}=\frac{2^7}{3^2}=\frac{128}{9}\)

b: \(\left(-27\right)^{10}\cdot16^{25}\)

\(=-3^{30}\cdot\left(2^4\right)^{25}=-3^{30}\cdot2^{100}\)

\(6^{30}\cdot\left(-32\right)^{15}\)

\(=2^{30}\cdot3^{30}\cdot\left(-1\right)\cdot\left(2^5\right)^{15}=-2^{105}\cdot3^{30}\)

\(\frac{\left(-27\right)^{10}\cdot16^{25}}{6^{30}\cdot\left(-32\right)^{15}}\)

\(=\frac{-2^{100}\cdot3^{30}}{-2^{105}\cdot3^{30}}=\frac{1}{2^5}=\frac{1}{32}\)

c: \(\left(-\frac{2}{17}\right)^3\cdot\left(-\frac{17}{35}\right)^3\cdot\left(\frac{35}{3}\right)^3\)

\(=\left(-\frac{2}{17}\cdot\frac{-17}{35}\cdot\frac{35}{3}\right)^3\)

\(=\left(\frac23\right)^3=\frac{8}{27}\)

e: \(2^2+4^2+\cdots+24^2\)

\(=2^2\left(1^2+2^2+\cdots+12^2\right)\)

\(=4\cdot650=2600\)

bạn ơi ! đề bài

\(A=\frac{49^{24}.125^{10}.2^8-5^{30}.7^{49}.4^5}{5^{29}.16^2.7^{43}}\)

\(A=\frac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{43}}\)

\(A=\frac{5^{30}.7^{48}.2^8.\left(1-7.2^2\right)}{5^{29}.2^8.7^{43}}=5.7^3.\left(1-7.2^2\right)=1715.\left(-27\right)=-46305\)

\(A=\frac{\left(7^2\right)^{24}.\left(5^3\right)^{10}.2^8-5^{30}.7^{49}.\left(2^2\right)^5}{5^{29}\left(2^4\right)^2.7^{43}}=\frac{7^{48}.5^{30}.2^8-5^{30}.7^{49}.2^{10}}{5^{29}.2^8.7^{43}}=\frac{7^{48}.5^{30}.2^8\left(1-7.2^2\right)}{5^{29}.2^8.7^{43}}\)

=\(7^5.5.\left(-27\right)=-2268945\)

đề bài là gì vậy bạn

a) -90/189 + 45/84 - 78/126

= -10/21 + 15/28 - 13/21

= (-10/21 - 13/21) + 15/28

= -24/21 + 15/28

= -17/28