Tính hợp lí:

a, 75. ( \(-2\frac{3}{25}+7\frac{2}{75}-5\frac{4}{15}\) )

b, \(45.\left(5\frac{4}{15}-4\frac{7}{9}-1\frac{8}{45}\right)\)

c, \(\frac{-5}{8}+\frac{14}{18}-\frac{3}{8}+\frac{2}{9}-\frac{1}{2006}\)

d, \(\frac{15}{29}-\frac{8}{7}+\frac{16}{14}+\frac{14}{29}-\frac{3}{8}\)

e, \(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{49.51}\)

Giải giùm mk zới mn~~~~tặng người đầu tiên làm 4 tick nha(đảm bảo lên 4 điểm 100%)

a)​​\(\frac{-4}{9}.\frac{7}{15}+\frac{4}{-9}.\frac{8}{15}\)

b)\(\frac{5}{-4}.\frac{16}{25}+\frac{-5}{4}.\frac{9}{25}.\)

c)\(4\frac{11}{23}-\frac{9}{14}+2\frac{12}{23}-\frac{5}{4}.\)

d)\(2\frac{13}{27}-\frac{7}{15}+3\frac{14}{27}-\frac{8}{15}\)

e)\(11\frac{1}{4}-\left\{2\frac{5}{7}+5\frac{1}{4}\right\}\)

g)\(\frac{7}{19}.\frac{8}{11}+\frac{7}{19}.\frac{3}{11}+\frac{12}{19}\)

Bài 12.Tính

a\(-\frac{4}{12}+\frac{6}{7}+\frac{8}{24}\)

b\(\frac{9}{18}+-\frac{7}{12}+\frac{13}{32}\)

c\(\frac{5}{-8}+\frac{14}{25}-\frac{6}{10}\)

d\(\frac{11}{26}+\frac{32}{39}--\frac{14}{52}\)

(câu a là âm\(\frac{4}{12}\); b là âm \(\frac{7}{12}\) ; d là âm\(\frac{14}{52}\))

bài 1:thực hiện phép tính : 

a)\(\frac{3}{7}+\frac{5}{13}+\frac{4}{13}\)

b)\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

c)\(\frac{2}{5}.\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}.\frac{1}{3}\)

d)\(\left(4-\frac{5}{12}\right):2+\frac{5}{24}\)

e)\(\frac{7}{19}.\frac{8}{11}+\frac{3}{11}.\frac{7}{19}+\frac{-1}{19}\)

f)\(\frac{9}{27}+\frac{8}{24}+\frac{18}{27}-\frac{-16}{24}+\frac{2}{3}\)

g)\(\frac{-5}{21}+\frac{-2}{21}+\frac{8}{24}\)

h)\(\frac{-5}{9}+\frac{8}{15}+\frac{-2}{11}+\frac{4}{-9}+\frac{7}{15}\)

i)\(\frac{7}{25}.\frac{39}{-14}.\frac{50}{78}\)

m.n làm nhanh cho mình nhé, chiều mình phải nộp rồi! cảm ơn m.n!

tính nhanh

1) A=\(\frac{-15}{19}\).\(\frac{23}{37}\)+\(\frac{14}{37}\).\(\frac{15}{19}\)

2)B=\(\frac{9}{11}\).\(\frac{-6}{13}\)-\(\frac{16}{13}\).\(\frac{9}{11}\)+\(\frac{9}{11}\).\(\frac{25}{13}\)

3)C=\(\frac{16}{111}\).\(\frac{-7}{12}\)-\(\frac{-14}{12}\).\(\frac{8}{111}\)

4)D=\(\frac{1}{10.11}\)+\(\frac{1}{11.12}\)+...+\(\frac{1}{101.102}\)+\(\frac{1}{102.103}\)

5)E=\(\frac{3}{4}\)+\(\frac{3}{28}\)+\(\frac{3}{70}\)+\(\frac{3}{130}\)