\(\frac{x-2}{27}\)+\(\frac{x-3}{26}\)+\(\frac{x-4}{25}\)+\(\frac{x-44}{5}\)=1

<=> \(\frac{x-2}{27}-1\)+\(\frac{x-3}{26}-1\)+\(\frac{x-4}{25}-1\)+\(\frac{x-44}{5}+3\)=1

<=> \(\frac{x-29}{27}\)+\(\frac{x-29}{26}\)+\(\frac{x-29}{25}\)+\(\frac{x-29}{5}\)=1

<=> ( x- 29 ) \(\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{5}\right)\)=1

phần sau tự làm tp nhé!

\(\frac{x+2}{x}=\frac{1}{2}\)

\(\Rightarrow2.\left(x+2\right)=x\)

\(\Rightarrow2x+4=x\)

\(\Rightarrow2x-x=-4\)

\(\Rightarrow x=-4\)

\(b,\frac{x+3}{x+4}=\frac{3}{5}\)

\(\Rightarrow5.\left(x+3\right)=3.\left(x+4\right)\)

\(\Rightarrow5x+15=3x+12\)

\(\Rightarrow5x-3x=12-15\)

\(\Rightarrow2x=-3\)

\(\Rightarrow x=-\frac{3}{2}\)

\(\frac{x+5}{6}=\frac{6}{x+5}\)

\(\Rightarrow\left(x+5\right).\left(x+5\right)=6.6\)

\(\Rightarrow\left(x+5\right)^2=6^2\)

\(\Rightarrow\orbr{\begin{cases}x+5=6\\x+5=-6\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-11\end{cases}}\)

Vậy x = 1 hoặc x= - 11 

\(\frac{x+1}{3}=\frac{12}{x+1}\)

\(\Rightarrow\left(x+1\right).\left(x+1\right)=3.12\)

\(\Rightarrow\left(x+1\right)^2=36\)

\(\Rightarrow\left(x+1\right)^2=6^2\)

\(\Rightarrow\orbr{\begin{cases}x+1=6\\x+1=-6\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}\)

mn giúp em mình với

\(-\frac{5}{28}\)

\(\frac{-3}{7}.\frac{5}{12}+\frac{3}{7}.\frac{7}{12}+\frac{-3}{12}\)

\(=\frac{3}{7}.\frac{-5}{12}+\frac{3}{7}.\frac{7}{12}+\frac{-1}{4}\)

\(=\frac{3}{7}.\left(\frac{-5}{12}+\frac{7}{12}\right)+\frac{-1}{4}\)

\(=\frac{3}{7}.\frac{2}{12}+\frac{-1}{4}\)

\(=\frac{3}{7}.\frac{1}{6}+\frac{-1}{4}\)

\(=\frac{3}{42}+\frac{-1}{4}\)

\(=\frac{1}{14}-\frac{1}{4}\)

\(=\frac{4}{56}-\frac{14}{56}\)

\(=\frac{-10}{56}=\frac{-5}{28}\)

a) x - 2/3 = -5/12

=> x = -5/12 + 2/3

=> x = 1/4

b) \(\frac{x+5}{3}=\frac{5}{9}\)

=> \(\frac{3\left(x+5\right)}{9}=\frac{5}{9}\)

=> 3(x + 5) = 5

=> x + 5 = 5 : 3

=> x + 5 = 5/3

=> x = 5/3 - 5

=> x = 20/3

c) \(\frac{x-2}{27}=\frac{3}{x-2}\)

=> (x - 2)(x - 2) = 27 . 3

=> (x - 2)² = 81

=> (x - 2)² = 9²

=> \(\orbr{\begin{cases}x-2=9\\x-2=-9\end{cases}}\)

=> \(\orbr{\begin{cases}x=11\\x=-7\end{cases}}\)

Vậy ...

câu a sai đề nha

a, \(\frac{x}{5}=\frac{2}{3}\Leftrightarrow x=\frac{10}{3}\)

b, \(\frac{x}{-24}=\frac{20}{42}\Leftrightarrow x=-\frac{80}{7}\)

c, \(\frac{x+3}{15}=\frac{1}{3}\Leftrightarrow3x+9=15\Leftrightarrow x=2\)

d, \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\Leftrightarrow x\left(\frac{2}{3}-\frac{3}{2}\right)=\frac{5}{12}\Leftrightarrow-\frac{5}{6}x=\frac{5}{12}\Leftrightarrow x=-\frac{1}{2}\)