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NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 1
\(\frac{x}{5}=\frac23\)
\(x\) = \(\frac23\times5\)
\(x=\frac{10}{3}\)
Vậy \(x=\frac{10}{3}\)
\(\frac{x}{3}-\frac12=\frac15\)
\(\frac{x}{3}\) = \(\frac15\) + \(\frac12\)
\(\frac{x}{3}\) = \(\frac{2}{10}+\frac{5}{10}\)
\(\frac{x}{3}=\frac{7}{10}\)
\(x=\frac{7}{10}\times3\)
\(x=\frac{21}{10}\)
Vậy \(x=\frac{21}{10}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
7 tháng 1
\(\frac{x}{5}+\frac12=\frac{6}{10}\)
\(\frac{x}{5}=\frac{6}{10}-\frac12\)
\(\frac{x}{5}=\frac{6}{10}-\frac{5}{10}\)
\(\frac{x}{5}=\frac{1}{10}\)
\(x=\frac{1}{10}\times5\)
\(x=\frac12\)
Vậy \(x=\frac12\)
\(\frac{x+3}{15}\) = \(\frac13\)
\(x+3=\frac13\times15\)
\(x+3=5\)
\(x=5-3\)
\(x=2\)
Vậy \(x=2\)
5 tháng 7 2019
a, \(\frac{-5}{21}+\frac{2}{9}=\frac{-15}{63}+\frac{14}{63}=\frac{-1}{63}\)
b, \(\frac{-4}{21}-\frac{5}{12}=\frac{-16}{84}-\frac{35}{84}=\frac{-51}{84}=\frac{-17}{28}\)
c, \(\frac{6}{-4}+\frac{1}{8}=\frac{-3}{2}+\frac{1}{8}=\frac{-12}{8}+\frac{1}{8}=\frac{-11}{8}\)
d, \(\frac{-56}{77}-\frac{30}{66}=\frac{-8}{11}-\frac{5}{11}=\frac{-13}{11}\)
e, \(\frac{-3}{9}+\frac{5}{-3}=\frac{-1}{3}+\frac{-5}{3}=\frac{-6}{3}=-2\)
NH
27 tháng 3 2019
\(a.\frac{108}{119}.\frac{107}{211}+\frac{108}{119}.\frac{104}{211}=\frac{108}{119}.\left(\frac{107}{211}+\frac{104}{211}\right)=\frac{108}{119}.1=108\)
25 tháng 6 2019
\(-5.\left(x+\frac{1}{5}\right)-\frac{1}{2}.\left(x-\frac{2}{3}\right)=\frac{3}{2}x-\frac{5}{6}\)
\(\Rightarrow-5x-1-\frac{1}{2}x+\frac{1}{3}=\frac{3}{2}x-\frac{5}{6}\)
\(\Rightarrow-5x-\frac{1}{2}x-\frac{3}{2}x=\frac{-5}{6}-\frac{1}{3}+1\)
\(\Rightarrow-7x=\frac{-1}{6}\)
\(\Rightarrow x=\frac{1}{42}\)
Vậy ...
\(\)
25 tháng 6 2019
\(3.\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
\(\Rightarrow3.\left(3x-\frac{1}{2}\right)^3=\frac{-1}{9}\)
\(\Rightarrow\left(3x-\frac{1}{2}\right)^3=\frac{-1}{27}\)
\(\Rightarrow\left(3x-\frac{1}{2}\right)^3=\left(\frac{-1}{3}\right)^3\)
\(\Rightarrow3x-\frac{1}{2}=\frac{-1}{3}\)
\(\Rightarrow3x=\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{18}\)
Vậy...
NH
3 tháng 2 2019
\(D=\frac{1}{6}+\frac{1}{66}+\frac{1}{176}+\frac{1}{336}+\frac{1}{546}\)
\(D=\frac{1}{1.6}+\frac{1}{6.11}+\frac{1}{11.16}+\frac{1}{16.21}+\frac{1}{21.26}\)
\(D=\frac{1}{5}\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}\right)\)
\(D=\frac{1}{5}\left(\frac{1}{1}-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+...+\frac{1}{21}-\frac{1}{26}\right)\)
\(D=\frac{1}{5}\left(\frac{1}{1}-\frac{1}{26}\right)\)
\(D=\frac{1}{5}.\frac{25}{26}=\frac{5}{26}\)
\(\frac{1}{2}.\frac{2}{3}=\frac{1}{3}\)
\(\frac{66}{5}:\frac{3}{5}=\frac{66}{5}.\frac{5}{3}=22\)
\(\frac{1}{2}\cdot\frac{2}{3}=\frac{1.2}{2.3}=\frac{1.1}{1.3}=\frac{1}{3}\)
\(\frac{66}{5}:\frac{3}{5}=\frac{66}{5}\cdot\frac{5}{3}=\frac{66.5}{5.3}=\frac{22.1}{1.1}=22\)
\(\frac{1}{2}\)\(\times\)\(\frac{2}{3}\)\(=\)\(\frac{1\times2}{2\times3}\)\(=\)\(\frac{1}{3}\)
\(\frac{66}{5}\)\(\times\)\(\frac{3}{5}\)\(=\)\(\frac{66\times3}{5\times5}\)\(=\)\(\frac{198}{25}\)
\(\frac{1}{2}\times\frac{2}{3}=\frac{1\times2}{2\times3}=\) \(\frac{2}{6}=\frac{1}{3}\)
\(\frac{66}{5}\div\frac{3}{5}=\frac{5}{66}\times\frac{3}{5}=\frac{3}{66}\) \(=\frac{1}{22}\)
1/2 × 2/3 = 1 × 2/2 × 3 = 2/6 = 1/3
66/5 ÷ 3/5 = 66/5 × 5/3 = 66 × 5/5 ×3 = 22
\(\frac{1}{2}\cdot\frac{2}{3}=\frac{2}{6}=\frac{1}{3}^{ }^{^{ }}^{ }\\ \frac{66}{5}:\frac{3}{5}=\frac{66}{5}\cdot\frac{5}{3}=22\)