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b)
( Tu ve hinh nha! )
Xet AB < AC
Ta co : \(\Delta KBM\sim\Delta ICM\left(g-g\right)\)
\(\Rightarrow\dfrac{BK}{IC}=\dfrac{MK}{IM}\) \(\Rightarrow\dfrac{IC}{MI}=\dfrac{BK}{MK}\)
Co : goc BCM = goc BAM ( cung chan cung BM )
\(\Rightarrow\Delta AKM\sim\Delta CHM\)
\(\Rightarrow\dfrac{AK}{CH}=\dfrac{MK}{HM}\) \(\Rightarrow\dfrac{AK}{MK}=\dfrac{CH}{HM}\left(1\right)\)
Co : goc MBC = goc MAC ( cung chan cung MC )
=> \(\Delta AIM\sim\Delta BHM\left(g-g\right)\)
\(\Rightarrow\dfrac{AI}{BH}=\dfrac{IM}{HM}\) \(\Rightarrow\dfrac{AI}{IM}=\dfrac{BH}{HM}\left(2\right)\)
tu (1) va (2) => \(\dfrac{AK}{MK}+\dfrac{AI}{IM}=\dfrac{BH}{HM}+\dfrac{CH}{HM}\left(=\dfrac{BC}{HM}\right)\)
Lai co :
\(\dfrac{AB}{MK}+\dfrac{AC}{MI}=\dfrac{AK}{MK}-\dfrac{BK}{MK}+\dfrac{AI}{MI}+\dfrac{IC}{MI}=\dfrac{AK}{MK}+\dfrac{AI}{MI}\)( vi \(\dfrac{IC}{MI}=\dfrac{BK}{MK}\)) .
=> DPCM.