\(1,2x+3x-4x=\left(-2\right)^3\)

<=>\(x=-8\)

\(2,x-2x=4^2+4^0\)

<=>\(-x=16+1\)

<=>\(-x=17\)

<=>\(x=-17\)

\(3,2^3x-3^2x=|12-21|\)

<=>\(-x=9\)

<=>\(x=-9\)

\(4,x-45=2x+54\)

<=>\(x-2x=54+45\)

<=>\(-x=99\)

<=>\(x=-99\)

\(5,5x-12+23=6^7:6^5\)

<=>\(5x+11=6^2\)

<=>\(5x+11=36\)

<=>\(5x=25\)

<=>\(x=5\)

\(5x+2x=6^2-5^0\Leftrightarrow5x+2x=6^2-1\)

\(\Leftrightarrow5x-2x=36-1\Leftrightarrow5x-2x=35\Leftrightarrow x\left(5+2\right)=35\)

\(\Leftrightarrow7x=35\Leftrightarrow x=35:7\Leftrightarrow x=5\)

\(5x+x=150:2+3\Leftrightarrow5x+x=75+3\)

\(\Leftrightarrow5x+x=78\Leftrightarrow x\left(5+1\right)=78\Leftrightarrow x6=78\)

\(\Leftrightarrow x=78:6\Leftrightarrow x=13\)

a) 5x + 2x = 6² - 5⁰

7x = 35 => x = 5

b) 5x + x = 150 : 2 + 3

6x = 78 => x = 13

c) 6x + x = 5¹¹ : 5⁹ + 3¹

7x = 28 => x = 4

d) 5x + 3x = 3⁶ : 3³ x 4 + 12

8x = 120 => x = 15

e) 4x + 2x = 68 - 2¹⁹ : 2¹⁶

6x = 60 => x = 10

f) 5x + x = 39 - 3¹¹ : 3⁹

6x = 30 => x = 5

g) 7x - x = 5²¹ : 5¹⁹ + 3 x 2² - 7⁰ 

6x = 36 => x = 6

h) 7x - 2x = 6¹⁷ : 6¹⁵ + 44 : 11

5x = 40 => x = 8

a; -2\(x\) - 3.(\(x-17\)) = 34 - 2.( - \(x\) + 25)

    - 2\(x\) - 3\(x\) + 51 = 34 + 2\(x\) - 50

       2\(x\) + 2\(x\) + 3\(x\) = - 34 + 50 + 51

            7\(x\)            = 67

               \(x\)           =  67 : 7

                \(x\)         =  \(\dfrac{67}{7}\)

Vậy \(x\) = \(\dfrac{67}{7}\) 

b; 17\(x\) + 3.(- 16\(x\) - 37) = 2\(x\) + 43 - 4\(x\)

    17\(x\) - 48\(x\)  - 111 =  2\(x\) - 4\(x\) + 43

    - 31\(x\) - 2\(x\) + 4\(x\) = 111 + 43

        - \(x\) x (31 + 2 - 4) = 154

        - \(x\) x (33 - 4) =  154

         - \(x\) x 29 = 154

         - \(x\)         = 154 : (-29)

           \(x\)        = - \(\dfrac{154}{29}\)

          Vậy \(x=-\dfrac{154}{29}\) 

a; A = 7^2007-5.7^2005+4.7^2004 chia hết cho 13

A = 7^2004.(7^3 - 5.7 + 4)

A = 7^2004.(343 - 35 + 4)

A = 7^2004.(298 + 4)

A = 7^2004.312

A = 7^2004.13.24

Vì 13 chia hết cho 13 nên A chia hết cho 13 đpcm

Câu 2:Tìm số nguyên x,biết:

a/x-3 chia hết cho 3x-2

Giải

(x - 3) ⋮ (3x - 2)

(3x - 9) ⋮ (3x - 2)

(3x - 2 - 7) ⋮ (3x - 2)

7 ⋮ (3x - 2)

(3x - 2) ∈ Ư(7) = {-7; -1; 1; 7}

\(x\in\) {-5/3; 1/3; 1; 3}

Vì \(x\in\) Z nên \(x\) ∈ {1; 3}

Vậy \(x\) ∈ {1; 3}

Nếu bài dễ thì cố gắng tự làm bạn nhé.

Bài 1:

a) \(2x+3=5\)

\(\Leftrightarrow2x=5-3=2\)

\(\Leftrightarrow x=2:2=1\)

Vậy: x=1

b) \(\left(2x-3\right)^2=9\)\(=3^2=\left(-3\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\left(3+3\right):2=3\\x=\left(-3+3\right):2=0\end{matrix}\right.\)

Vậy: \(x\in\left\{3;0\right\}\)

c) \(3x+4=2x-7\)

\(\Leftrightarrow2x-3x=7+4\)

\(\Leftrightarrow-1x=11\)

\(\Leftrightarrow x=-11\)

Vậy: x=-11

d) \(\left(4x-1\right)^3=27\)\(=3^3\)

\(\Rightarrow4x-1=3\)

\(\Leftrightarrow4x=3+1=4\)

\(\Leftrightarrow x=4:4=1\)

Vậy: x=1

e) \(\left(x-7\right).2=3.\left(2x+4\right)\)

\(\Leftrightarrow2x-14=6x+12\)

\(\Leftrightarrow2x-6x=12+14\)

\(\Leftrightarrow-4x=26\)

\(\Leftrightarrow x=\frac{26}{-4}=\frac{13}{-2}\)

Vậy: \(x=\frac{13}{-2}\)

\(5x+2x=6^2-5^0\)

\(7x=36-1\)

\(7x=35\)

\(x=5\)

vậy \(x=5\)

\(5x+x=150:2+3\)

\(6x=75+3\)

\(x=78:6\)

\(x=13\)

vậy \(x=13\)

những câu sau tương tự

1) 5x + 2x = 6^2 - 5^0

=> 7x = 36 - 1 = 35

=> x = 35 : 5 = 5.

    Vậy x = 5  

2) 5x + x = 150 : 2 + 3

=> 6x = 75+3 = 78

=> x = 78 : 6 =13.

    Vậy x = 13

3) 6x + x = 5^11 : 5^9 - 3^1

=> 7x = 5^2 -3 = 25 - 3 = 22

=> x = 22 : 7 = 22 / 7.

    Vậy x = 22/7

4) 5x + 3x = 3^6 : 3^3 .4 + 12

=> 8x = 3^3 .4 + 12= 27.4 + 12 = 108 + 12 =120

=> x = 120 : 8 = 15.

     Vậy x = 15

5) 4x + 2x = 68 - 2^19 : 2^16

=> 6x = 68 - 2 ^3 = 68 - 8 =60

=> x = 60 : 6 =10.

     Vậy x = 10

6) 5x + x = 39 - 3^11 : 3^9 

=> 6x = 39 - 3^2 = 39 - 9 = 30

=> x = 30 : 6 =5.

     Vậy x =5

7) 7x - x = 5^21 : 5^19 + 3. 2^2 - 7^0

=> 6x = 5^2 + 3.4 - 1 = 25 + 12 - 1 = 36

=> x = 36 : 6 = 6.

     Vậy x = 6

8) 7x - 2x = 6^17 : 6^15 + 44 : 11

=> 5x = 6^2 + 4 = 36 + 4 = 40

=> x = 40 : 5 = 8 .

     Vậy x = 8

\(2x-8x^2=0\Rightarrow2x\left(1-4x\right)=0\Rightarrow\orbr{\begin{cases}2x=0\\1-4x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=\frac{1}{4}\end{cases}}}\)

\(x-x^2=0\Rightarrow x\left(1-x\right)=0\Rightarrow\orbr{\begin{cases}x=0\\1-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)

Cn lại lm tương tự nha e!

=.= hok tốt!!