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Bài 4:
a; \(\dfrac{1}{4}\) - \(\dfrac{1}{5}\) = \(\dfrac{5}{20}\) - \(\dfrac{4}{20}\) = \(\dfrac{1}{20}\)
b; \(\dfrac{3}{5}\) - \(\dfrac{-1}{2}\) = \(\dfrac{6}{10}\) + \(\dfrac{5}{10}\) = \(\dfrac{11}{10}\)
c; \(\dfrac{3}{5}\) - \(\dfrac{-1}{3}\) = \(\dfrac{9}{15}\) + \(\dfrac{5}{15}\) = \(\dfrac{14}{15}\)
d; \(\dfrac{-5}{7}\) - \(\dfrac{1}{3}\)= \(\dfrac{-15}{21}\) - \(\dfrac{7}{21}\)= \(\dfrac{-22}{21}\)
Bài 5
a; 1 + \(\dfrac{3}{4}\) = \(\dfrac{4}{4}\) + \(\dfrac{3}{4}\) = \(\dfrac{7}{4}\) b; 1 - \(\dfrac{1}{2}\) = \(\dfrac{2}{2}\) - \(\dfrac{1}{2}\) = \(\dfrac{1}{2}\)
c; \(\dfrac{1}{5}\) - 2 = \(\dfrac{1}{5}\) - \(\dfrac{10}{5}\) = \(\dfrac{-9}{5}\) d; -5 - \(\dfrac{1}{6}\) = \(\dfrac{-30}{6}\) - \(\dfrac{1}{6}\) = \(\dfrac{-31}{6}\)
e; - 3 - \(\dfrac{2}{7}\)= \(\dfrac{-21}{7}\) - \(\dfrac{2}{7}\)= \(\dfrac{-23}{7}\) f; - 3 + \(\dfrac{2}{5}\) = \(\dfrac{-15}{5}\) + \(\dfrac{2}{5}\)= - \(\dfrac{13}{5}\)
g; - 3 - \(\dfrac{2}{3}\) = \(\dfrac{-9}{3}\) - \(\dfrac{2}{3}\) = \(\dfrac{-11}{3}\) h; - 4 - \(\dfrac{-5}{7}\) = \(\dfrac{-28}{7}\)+ \(\dfrac{5}{7}\) = - \(\dfrac{23}{7}\)
Có quá nhiều bài, thứ nhất em đăng tách ra, thứ hai chụp gần cận cho rõ, thứ ba em chỉ đăng bài cần giúp
Bài 3:
a; \(\frac56-\frac89\) = \(\frac{15}{18}-\) \(\frac{16}{18}\) = - \(\frac{1}{18}\)
d; \(\frac{5}{16}-\frac{5}{24}\)
= \(\frac{15}{48}\) - \(\frac{10}{48}\)
= \(\frac{5}{48}\)
e; - \(\frac{7}{30}\) + \(\frac{8}{45}\)
= \(-\frac{21}{90}\) + \(\frac{16}{90}\)
= - \(\frac{5}{90}\)
= - \(\frac{1}{18}\)
f; \(\frac{7}{12}-\frac{-9}{20}\)
= \(\frac{35}{60}\) + \(\frac{27}{60}\)
= \(\frac{62}{60}\)
= 31/30
h; - \(\frac48\) + \(-\frac{3}{10}\)
= -\(\frac{20}{40}-\frac{12}{40}\)
= - \(\frac{32}{40}\)
= - \(\frac45\)
\(a,MSC:180\\ Có:-5=\dfrac{-5.180}{180}=\dfrac{-900}{180};\dfrac{17}{-20}=\dfrac{17.\left(-9\right)}{\left(-9\right).\left(-20\right)}=\dfrac{-153}{180};\dfrac{-16}{9}=\dfrac{-16.20}{9.20}=\dfrac{-320}{180}\\ ---\\ b.MSC:75\\ Có:\dfrac{13}{-15}=\dfrac{13.\left(-5\right)}{\left(-15\right).\left(-5\right)}=\dfrac{-65}{75};\dfrac{-18}{25}=\dfrac{-18.3}{25.3}=\dfrac{-54}{75};-3=\dfrac{-3.75}{75}=\dfrac{-225}{75}\)
| Phân số | Đọc | Tử Số | Mẫu số |
| \(\dfrac{5}{7}\) | Năm phần bẩy | 5 | 7 |
| \(\dfrac{-6}{11}\) | âm sáu phần mười một | -6 | 11 |
| \(\dfrac{-2}{13}\) | âm hai phần ba | -2 | 13 |
| \(\dfrac{9}{-11}\) | chín phần âm mười một | 9 | -11 |
a) 3h 20ph = 3 và 1/3 = 10/3
b) 1h 45 ph = 1 và 3/4 = 7/4
c) 2h 40 ph = 2 và 2/3 = 8/3
\(a,-\dfrac{9}{4}< 0;\dfrac{1}{3}>0.Nên:-\dfrac{9}{4}< \dfrac{1}{3}\\ b,-\dfrac{8}{3}< -2;\dfrac{4}{-7}>-1.Nên:-\dfrac{8}{3}< -2< -1< \dfrac{4}{-7}\\ Vậy:-\dfrac{8}{3}< \dfrac{4}{-7}\\ c,\dfrac{9}{-5}< -1;\dfrac{7}{-10}>-1.Nên:\dfrac{9}{-5}< -1< \dfrac{7}{-10}.Vậy:\dfrac{9}{-5}< \dfrac{7}{-10}\\ d,\dfrac{3}{14}>0;-\dfrac{6}{14}< 0.Nên:\dfrac{3}{14}>0>-\dfrac{6}{14}.Vậy:\dfrac{3}{14}>-\dfrac{6}{14}\\ e,\dfrac{7}{-12}=\dfrac{7.3}{-12.3}=\dfrac{21}{-36};\dfrac{11}{-18}=\dfrac{11.2}{-18.2}=\dfrac{22}{-36}\\ Vì:\dfrac{21}{-36}>\dfrac{22}{-36}.Nên:\dfrac{7}{-12}>\dfrac{11}{-18}\)
\(f,-\dfrac{4}{7}< -\dfrac{1}{2};-\dfrac{4}{10}>\dfrac{-1}{2}.Nên:-\dfrac{4}{7}< -\dfrac{1}{2}< -\dfrac{4}{10}.Vậy:-\dfrac{4}{7}< -\dfrac{4}{10}\\ g,-\dfrac{8}{15}< -\dfrac{1}{2};\dfrac{5}{-24}>-\dfrac{1}{2}.Nên:-\dfrac{8}{15}< -\dfrac{1}{2}< \dfrac{5}{-24}.Vậy:-\dfrac{8}{15}< \dfrac{5}{-24}\\ h,\dfrac{69}{-230}=\dfrac{69:23}{-230:23}=\dfrac{3}{-10};\dfrac{-39}{143}=\dfrac{-39:13}{143:13}=\dfrac{-3}{11}\\ Vì:\dfrac{-3}{10}< -\dfrac{3}{11}.Vậy:\dfrac{69}{-230}< \dfrac{-39}{143}\\ i,\dfrac{7}{41}=1-\dfrac{34}{41};\dfrac{13}{47}=1-\dfrac{34}{47}\\ Vì:\dfrac{34}{41}>\dfrac{34}{47}.Nên:1-\dfrac{34}{41}< 1-\dfrac{34}{47}.Vậy:\dfrac{7}{41}< \dfrac{13}{47}\)









Bài 1:
\(a)\left(\dfrac{1}{3}:x-1\right)=\dfrac{1}{3}+\dfrac{1}{7}-\dfrac{1}{21}\\ \dfrac{1}{3}:x-1=\dfrac{7}{21}+\dfrac{3}{21}-\dfrac{1}{21}=\dfrac{9}{21}\\ \dfrac{1}{3}:x-1=\dfrac{3}{7}\\ \dfrac{1}{3}:x=\dfrac{3}{7}+1=\dfrac{10}{7}\\ x=\dfrac{1}{3}:\dfrac{10}{7}\\ x=\dfrac{7}{30}\\ b)\dfrac{1}{5}\cdot x-\dfrac{2}{13}=\dfrac{1}{2\cdot3}+\dfrac{2}{3\cdot5}+\dfrac{3}{5\cdot8}+\dfrac{5}{8\cdot13}\\ \dfrac{1}{5}\cdot x-\dfrac{2}{13}=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{13}\\ \dfrac{1}{5}\cdot x-\dfrac{2}{13}=\dfrac{1}{2}-\dfrac{1}{13}=\dfrac{11}{26}\\\dfrac{1}{5}\cdot x=\dfrac{11}{26}+\dfrac{2}{13}=\dfrac{15}{26}\\ x=\dfrac{15}{26}:\dfrac{1}{5}=\dfrac{75}{26}\\c)\dfrac{13}{6} :\left(\dfrac{1}{2}+x\right)=\dfrac{1}{3}+\dfrac{3}{7}+\dfrac{1}{7\cdot2}+\dfrac{5}{2\cdot13}+\dfrac{3}{13\cdot4}\\ \dfrac{13}{6}:\left(\dfrac{1}{2}+x\right)=\dfrac{1}{3}+\left(\dfrac{3}{7}+\dfrac{1}{7\cdot2}\right)+\left(\dfrac{5}{2\cdot13}+\dfrac{3}{13\cdot4}\right)\\ \dfrac{13}{6}:\left(\dfrac{1}{2}+x\right)=\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{1}{4}\\ \dfrac{13}{6}:\left(\dfrac{1}{2}+x\right)=\dfrac{13}{12}\\ \dfrac{1}{2}+x=\dfrac{13}{6}:\dfrac{13}{12}=2\\ x=2-\dfrac{1}{2}\\ x=\dfrac{3}{2}\)
bằng 9/10 số hs còn lại nhé
lam bai giai di ban