a) MC :24

\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}=\frac{1\times8+3\times3-7\times2}{24}=\frac{3}{24}=\frac{1}{8}\)

b)MC : 56

\(\frac{3}{14}+\frac{5}{8}-\frac{1}{2}=\frac{3\times4+5\times7-1\times28}{56}=\frac{19}{56}\)

c) MC: 36

\(\frac{1}{4}-\frac{2}{3}-\frac{11}{18}=\frac{1\times9-2\times12-11\times2}{36}=\frac{-37}{36}\)

d) MC: 312

\(\frac{1}{4}+\frac{5}{12}-\frac{1}{13}-\frac{7}{8}=\frac{1\times78+5\times26-1\times24-7\times39}{312}=\frac{-89}{312}\)

\(\frac{23}{12}\)

\(\frac{314}{105}\)

\(\frac{59}{60}\)

\(\frac{199}{90}\)

\(\frac{1}{18}\)

\(\frac{13}{36}\)

\(\frac{4}{221}\)

\(\frac{4}{85}\)

phải giải thích đày đủ

Bn lớp 5 suy nghĩ đi chứ

Lớp 4 học rồi 

dễ thế mà

a. \(\frac{-3}{2}-2x+\frac{3}{4}=-22\)2

=> \(-2x=-22+\frac{3}{2}-\frac{3}{4}\)

=> \(-2x=\frac{-85}{4}\)

=> \(x=\frac{-85}{4}:\left(-2\right)\)

=> \(x=\frac{85}{8}\)

b. \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\left(\frac{3}{-2}-\frac{10}{3}\right)=\frac{2}{5}\)

=> \(\left(\frac{-2}{3}x-\frac{3}{5}\right).\frac{-29}{6}=\frac{2}{5}\)

=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{2}{5}:\left(\frac{-29}{6}\right)\)

=> \(\frac{-2}{3}x-\frac{3}{5}=\frac{-12}{145}\)

=> \(\frac{-2}{3}x=\frac{-12}{145}+\frac{3}{5}\)

=> \(\frac{-2}{3}x=\frac{15}{29}\)

=> x = \(\frac{15}{29}:\frac{-2}{3}\)

=> x = \(\frac{-45}{58}\)

Ai nhanh được k nha :))

Trả lời 

\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{1}{14+15}\)

Hay 

\(A=\frac{11}{12+13}+\frac{12}{13+14}+\frac{13}{14+15}\)

mong xem lại hộ cái 

\(a,4\frac{1}{2}< 4\frac{3}{4}\)

\(b,2\frac{4}{5}< 3\frac{1}{4}\)

\(c,7\frac{2}{9}>5\frac{2}{9}\)

\(d,13\frac{5}{6}< 13\frac{6}{7}\)

Nao Tomori

\(a,4\frac{1}{2}....4\frac{3}{4}\Rightarrow4\frac{1}{2}=\frac{13}{2};4\frac{3}{4}=\frac{19}{4}\)

\(=4\frac{1}{2}< 4\frac{3}{4}\)

\(b,2\frac{4}{5}....3\frac{1}{4}\Rightarrow2\frac{4}{5}=\frac{14}{5};3\frac{1}{4}=\frac{13}{12}\)

\(=2\frac{4}{5}>3\frac{1}{4}\)

\(c,7\frac{2}{9}....5\frac{2}{9}\Rightarrow7\frac{2}{9}=\frac{65}{9};5\frac{2}{9}=\frac{42}{9}\)

\(=7\frac{2}{9}>5\frac{2}{9}\)

\(d,13\frac{5}{6}....13\frac{6}{7}\Rightarrow13\frac{5}{6}=\frac{83}{6};13\frac{6}{7}=\frac{97}{7}\)

\(=13\frac{5}{6}< 13\frac{6}{7}\)

P/s: Quy đồng là bước trung gian nên mk ko ghi bước quy đồng nha

a)\(\frac{77}{24}\)=\(3\frac{5}{24}\)

b)=10

c)\(\frac{24}{35}\)

a)\(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{1}{3}\right)+3\)

\(=1+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3\)

\(=1+3+\frac{7}{9}\)

\(=4\frac{7}{9}\)

\(=\frac{43}{9}\)

b)\(\frac{8}{5}\cdot\frac{4}{7}+\frac{4}{7}\cdot\frac{2}{5}-1\)

\(=\frac{4}{7}\cdot\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}\cdot2-1\)

\(=\frac{8}{7}-1\)

\(=\frac{1}{7}\)

a) \(\frac{8}{13}+\frac{4}{9}+\frac{1}{3}+\frac{5}{13}+3\)

\(=\left(\frac{8}{13}+\frac{5}{13}\right)+\left(\frac{4}{9}+\frac{3}{9}\right)+3\)

\(=1+\frac{7}{9}+3=4\frac{7}{9}\)

b)\(\frac{8}{5}.\frac{4}{7}+\frac{4}{7}.\frac{2}{5}-1\)

\(=\frac{4}{7}.\left(\frac{8}{5}+\frac{2}{5}\right)-1\)

\(=\frac{4}{7}.2-1\)

\(=\frac{8}{7}-\frac{7}{7}=\frac{1}{7}\)