Cân bằng CxHyOz + O2 ------> CO2 + H2O - Thuy Kim

$C_x{H}_y{O}_z$+$\left(x+\frac{y}{4}-\frac{z}{2}\right)O_2$---->$xC{O}_2+\frac{y}{2}{H}_{2}O$

3)

2Al + 6H2SO4 → Al2(SO4)3 + 3SO2 + 6H2O

Cái này cân bằng theo phương pháp thăng bằng electron nhé:

\(2Fe+6H_2SO_{4\left(đn\right)}\rightarrow Fe_2\left(SO_4\right)_3+3SO_2\uparrow+6H_2O\)

\(8Al+15H_2SO_4\rightarrow4Al_2\left(SO_4\right)_3+3H_2S+12H_2O\)

\(3Fe+8HNO_{3\left(đn\right)}\rightarrow3Fe\left(NO_3\right)_2+2NO+4H_2O\)

2Al +6 $H_{2}S{O}_4$ -->

2Al + 6H₂SO₄ --> Al₂(SO₄)₃ + 3SO₂ + 6H₂O

1) $2n+O_2\to 2nO$

2) $\mathrm{2F}e+\mathrm{3C}{l}_2\to \mathrm{2F}eC{l}_3$

3) $Mg+\mathrm{2H}Cl\to MgC{l}_2+H_2$

4) $\mathrm{2A}l+\mathrm{6H}Cl\to \mathrm{2A}lC{l}_3+{\mathrm{3H}}_2$

5) $\mathrm{2A}l+{\mathrm{3H}}_{2}S{O}_4\to A{l}_2{\left(S{O}_4\right)}_{{}_3}+{\mathrm{3H}}_2$

1:2n+O2 to→2nO

2: 2Fe+3Cl2 to→2FeCl3

3: Mg+2HCl to→MgCl2+H2

4: 2Al+6HCl →2AlCl3+3H2

5: 2Al+3H2SO4 →Al2(SO4)3+3H2

1.6KOH + 3 + 2

2.2KMnO KMnO + MnO + O

3.FeO + 4CO 3Fe + 4CO

4. 2KClO 2KCl + 3O

5. 2Al(OH) + 3HSO Al(SO) + 3HO

Diệp Tử Vân đề yêu cầu cân bằng hả bạn :))

2Al + 6H₂SO₄ → Al₂(SO₄)₃ + 3SO₂ + 6H₂O

CaCO₃ \(\underrightarrow{to}\) CaO + CO₂

2Al(OH)₃ \(\underrightarrow{to}\) Al₂O₃ + 3H₂O

3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O

4P + 5O₂ \(\underrightarrow{to}\) 2P₂O₅

2Al(OH)₃ + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

2AlCl₃ + 3Ba(OH)₂ → 3BaCl₂ + 2Al(OH)₃

2Na₃PO₄ + 3CaCl₂ → 6NaCl + Ca₃(PO₄)₂

Bạn viết sai một số công thức, lần sau chú ý hơn nhé!

`Fe + 2HCl -> FeCl_2 + H_2`

`2Na + 2HCl -> 2NaCl + H_2`

`2Al + 6HCl -> 2AlCl_3 + 3H_2`

`2Al(OH)_3 + 3H_2SO_4 -> Al_2(SO_4)_3 + 6H_2O`

Fe + 2HCl → FeCl₂ + H₂
2Na + 2HCl → 2NaCl + H₂
2Al + 6HCl → 2AlCl₃ + 3H₂
2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 6H₂O

a/ Xét CTHH: Na_xCO_y

Theo quy tắc hóa trị: I.x=II.y

Chuyển thành tỷ lệ: \(\dfrac{x}{y}=\dfrac{2}{1}\Rightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)

PT: 4NaOH + 3CO₂ -> 2NaHCO₃ + Na₂CO₃ + H₂O

b/ Al₂(SO₄)₃ + 6NaOH -> 2Al(OH)₃ + 3Na₂SO₄

a. 6NH3 + 5O3 --> 6NO + 9H2O

b. 2S + HNO3 -to-> 2NO + H2SO4

c. 4NO2 + O2 + 2H2O --> 4HNO3

d. FeCl3 + 3AgNO3 --> Fe(NO3)3 + 3AgCl

e. 3NO2 + H2O -to-> 2HNO3 + NO

f. 3Ba(NO3)2 + Al2(SO4)3 --> 3BaSO4 + 2Al(NO3)3

a. 6NH₃ + 5O₃ \(\rightarrow\) 6NO + 9H₂O

b. 2S + HNO₃ \(\underrightarrow{to}\) 2NO + H₂SO₄

c. 4NO₂ + O₂ + 2H₂O \(\rightarrow\) 4HNO₃

d. FeCl₃ + 3AgNO₃ \(\rightarrow\) Fe(NO₃)₃ + 3AgCl

e. 3NO₂ + H₂O \(\underrightarrow{to}\) 2HNO₃ + NO

f. 3Ba(NO₃)₂ + Al₂(SO₄)₃ \(\rightarrow\) 3BaSO₄ + 2Al(NO₃)₃

a) \(K_2O+H_2O->2KOH\)

b) \(2Fe+3Cl_2->2FeCl_3\)

c) \(2Al\left(OH\right)_3+3H_2SO_4->Al_2\left(SO_4\right)_3+6H_2O\)

d) \(4FeS_2+11O_2->2Fe_2O_3+8SO_2\)

e)\(2Al+6HCl->2AlCl_3+3H_2\)

f) \(2KClO_3->KCl+3O_2\)

g) \(4P+5O_2->2P_2O_5\)

h) \(3Fe+2O_2->Fe_3O_4\)

i) \(2Al+3CuSO_4->Al_2\left(SO_4\right)_3+3Cu\)

j) \(2K+2H_2O->2KOH+H_2\)