Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tìm x trong tỉ lệ thức
a) −0,52 : x = −9,36 : 16,38
\(\dfrac{-0.52}{x}=\dfrac{-9.36}{16.38}=-\dfrac{4}{7}\\ \Rightarrow x=\dfrac{7.\left(-0.52\right)}{-4}=\dfrac{91}{100}=0.91\)
a) \(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
=> x. 3,6 = 27. (-2)
=> x.3,6 = -54
x = (-54) : 3,6
x = -15
b) -0,52 : x = -9,36 : 16,38
- 0,52 : x = \(\dfrac{-4}{7}\)
x = \(\dfrac{-4}{7}\) . ( -0,52)
x = \(\dfrac{52}{175}\)
a)\(\dfrac{x}{27}=\dfrac{-2}{3,6}\)
=>x.3,6=27.(-2)
=>x . 3,6=-54
=>x=-54:3.6
=>x=-54:\(\dfrac{18}{5}\)
=>x=-54.\(\dfrac{5}{18}\)
=>x=-15
b)-0,52:x=-9,36:16,38
-\(\dfrac{13}{25}:x=-\dfrac{234}{25}:\dfrac{819}{50}\)
\(-\dfrac{13}{25}:x=-\dfrac{4}{7}\)
\(x=-\dfrac{4}{7}:\left(-\dfrac{13}{25}\right)\)
x=\(\dfrac{52}{175}\)
c)\(\dfrac{4\dfrac{1}{4}}{2\dfrac{7}{8}}=\dfrac{x}{1,61}\)
\(\dfrac{\dfrac{17}{4}}{\dfrac{23}{8}}=\dfrac{x}{1,61}\)
\(\dfrac{17}{4}:\dfrac{23}{8}=\dfrac{x}{1,61}\)
\(\dfrac{17}{4}.\dfrac{8}{23}=\dfrac{x}{1,61}\)
\(\dfrac{34}{23}=\dfrac{x}{1,61}\)
=>34.1,61=x.23
rồi bạn tự tính tự làm nốt nhé
a: =>||12x-1/2|-2|=-2/3x3/4=-6/12=-1/2(loại)
b: =>2/3-1/3x-1/2+2/3x=2x+2/3
=>-5/3x=1/2
=>x=-1/2:5/3=-1/2x3/5=-3/10
c: =>|3/2x+1/4|=2+3/4=11/4
=>3/2x+1/4=11/4 hoặc 3/2x+1/4=-11/4
=>3/2x=5/2 hoặc 3/2x=-3
=>x=3/5 hoặc x=-3:3/2=-2
a, \(\dfrac{1}{2}+\dfrac{2}{3}x=\dfrac{4}{5}\)
\(\Rightarrow\dfrac{2}{3}x=\dfrac{4}{5}-\dfrac{1}{2}\\ \Rightarrow\dfrac{2}{3}x=\dfrac{3}{10}\\ \Rightarrow x=\dfrac{3}{10}\cdot\dfrac{3}{2}\\ \Rightarrow x=\dfrac{9}{20}\)
b, \(x+\dfrac{1}{4}=\dfrac{4}{3}\)
\(\Rightarrow x=\dfrac{4}{3}-\dfrac{1}{4}\\ \Rightarrow x=\dfrac{13}{12}\)
c, \(\dfrac{3}{5}x-\dfrac{1}{2}=-\dfrac{1}{7}\)
\(\Rightarrow\dfrac{3}{5}x=-\dfrac{1}{7}-\dfrac{1}{2}\\ \Rightarrow\dfrac{3}{5}x=-\dfrac{9}{14}\\ \Rightarrow x=-\dfrac{9}{14}\cdot\dfrac{5}{3}\\ \Rightarrow x=\dfrac{15}{14}\)
d, \(\left|x-\dfrac{4}{5}\right|=\dfrac{3}{4}\)
\(\Rightarrow\left\{{}\begin{matrix}x-\dfrac{4}{5}=\dfrac{3}{4}\\x-\dfrac{4}{5}=-\dfrac{3}{4}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{3}{4}+\dfrac{4}{5}\\x=-\dfrac{3}{4}+\dfrac{4}{5}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=\dfrac{31}{20}\\x=\dfrac{1}{20}\end{matrix}\right.\)
e, \(lxl\) là j mk ko hiểu!
a. \(\dfrac{-39}{7}:x=26\)
x = \(\dfrac{-39}{7}:26\)
x = \(\dfrac{-3}{14}\)
b. \(x:\dfrac{13}{5}=\dfrac{7}{4}\)
x = \(\dfrac{7}{4}.\dfrac{13}{5}\)
x = \(\dfrac{91}{20}\)
c. x = \(\dfrac{-3}{5}-\dfrac{1}{2}\)
x = \(\dfrac{-11}{10}\)
d. \(x-\dfrac{3}{4}=\dfrac{9}{4}\)
x = \(\dfrac{9}{4}+\dfrac{3}{4}\)
x = 3
e. \(\dfrac{7}{8}:x=\dfrac{14}{3}\)
x = \(\dfrac{7}{8}:\dfrac{14}{3}\)
x = \(\dfrac{3}{16}\)
f. \(x:\dfrac{8}{3}=\dfrac{13}{3}\)
x = \(\dfrac{13}{3}.\dfrac{8}{3}\)
x = \(\dfrac{104}{9}\)
g. x = \(\dfrac{4}{10}-\dfrac{2}{5}\)
x = 0
chúc bạn học tốt 
a) \(x+\dfrac{1}{3}=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{12}\) vậy \(x=\dfrac{5}{12}\)
b) \(x-\dfrac{2}{5}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{5}{7}+\dfrac{2}{5}\Leftrightarrow x=\dfrac{39}{35}\) vậy \(x=\dfrac{39}{35}\)
c) \(-x-\dfrac{2}{3}=\dfrac{-6}{7}\Leftrightarrow x=\dfrac{-2}{3}+\dfrac{6}{7}\Leftrightarrow x=\dfrac{4}{21}\) vậy \(x=\dfrac{4}{21}\)
d) \(\dfrac{4}{7}-x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{4}{7}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{21}\) vậy \(x=\dfrac{5}{21}\)
a) x + \(\dfrac{1}{3}\) = \(\dfrac{3}{4}\)
x = \(\dfrac{3}{4}\) - \(\dfrac{1}{3}\)
x = \(\dfrac{5}{12}\)
Vậy x = \(\dfrac{5}{12}\)
b) x - \(\dfrac{2}{5}\) = \(\dfrac{5}{7}\)
x = \(\dfrac{5}{7}\) + \(\dfrac{2}{5}\)
x = \(\dfrac{39}{35}\)
Vậy x = \(\dfrac{39}{35}\)
c) -x - \(\dfrac{2}{3}\) = \(-\dfrac{6}{7}\)
- x = \(-\dfrac{6}{7}\) + \(\dfrac{2}{3}\)
- x = \(-\dfrac{4}{21}\)
⇒ x = \(\dfrac{4}{21}\)
Vậy x = \(\dfrac{4}{21}\)
d) \(\dfrac{4}{7}\) - x = \(\dfrac{1}{3}\)
x = \(\dfrac{4}{7}\) - \(\dfrac{1}{3}\)
x = \(\dfrac{5}{21}\)
Vậy x = \(\dfrac{5}{21}\)
a: =>1/3x-1/3-3/4x=1
=>-5/12x=4/3
=>x=-4/3:5/12=-4/3*12/5=-48/15=-16/5
b: =>12x+36=5x-20
=>7x=-56
=>x=-8
c: =>x^2-9x+14=x^2-2x-15
=>-7x=-29
=>x=29/7
d: =>3x+2=3 hoặc 3x+2=-3
=>3x=1 hoặc 3x=-5
=>x=1/3 hoặc x=-5/3
e: \(\Leftrightarrow2^{x-3}=2^{40}\)
=>x-3=40
=>x=43
Các câu dễ tự làm :v
\(\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}=\dfrac{x+1}{13}+\dfrac{x+1}{14}\)
\(\Rightarrow\dfrac{x+1}{10}+\dfrac{x+1}{11}+\dfrac{x+1}{12}-\dfrac{x+1}{13}-\dfrac{x+1}{14}=0\)
\(\Rightarrow\left(x+1\right)\left(\dfrac{1}{10}+\dfrac{1}{11}+\dfrac{1}{12}-\dfrac{1}{13}-\dfrac{1}{14}\right)=0\)
\(\Rightarrow x+1=0\Rightarrow x=-1\)
\(\dfrac{x+4}{2000}+\dfrac{x+3}{2001}=\dfrac{x+2}{2002}+\dfrac{x+1}{2003}\)
\(\Rightarrow\dfrac{x+4}{2000}+1+\dfrac{x+3}{2001}+1=\dfrac{x+2}{2002}+1+\dfrac{x+1}{2003}+1\)
\(\Rightarrow\dfrac{x+2004}{2000}+\dfrac{x+2004}{2001}=\dfrac{x+2004}{2002}+\dfrac{x+2004}{2003}\)
\(\Rightarrow\dfrac{x+2004}{2000}+\dfrac{x+2004}{2001}-\dfrac{x+2004}{2002}-\dfrac{x+2004}{2003}=0\)
\(\Rightarrow\left(x+2004\right)\left(\dfrac{1}{2000}+\dfrac{1}{2001}-\dfrac{1}{2002}-\dfrac{1}{2003}\right)=0\)
\(\Rightarrow x+2004=0\Rightarrow x=-2004\)
\(a,\Leftrightarrow4\left(x-2\right)=3\left(x+3\right)\left(x\ne-3\right)\\ \Leftrightarrow4x-8=3x+9\\ \Leftrightarrow x=17\left(tm\right)\\ b,\Leftrightarrow\dfrac{-1,04}{x}=\dfrac{18,72}{16,38}\\ \Leftrightarrow x=\dfrac{-1,04\cdot16,38}{18,72}=-0,91\)
a) ĐKXĐ: \(x\ne-3\)
\(\Leftrightarrow4x-8=3x+9\\ \Leftrightarrow x=17\)
b) \(\Leftrightarrow-1,04:x=\dfrac{8}{7}\\ \Leftrightarrow x=-\dfrac{91}{100}\)