\(3\left(x-\frac{1}{2}\right)-3\left(x-\frac{1}{3}\right)=x\)

=> \(3x-\frac{3}{2}-3x+1=x\)

=> \(x=-\frac{1}{2}\)

2) \(\frac{1}{3}x+5-x=\frac{1}{2}-2x\)

=> \(\frac{1}{3}x-x+2x=-5+\frac{1}{2}\)

=> \(\frac{4}{3}x=-\frac{9}{2}\)

=> x = \(-\frac{27}{8}\)

Từ x:3=y:5 suy ra 4x:12=y:5 và 4x-y=14

Áp dụng tính chất của dãy tỉ số bằng nhau

x:3=y:5=4x-y:12-5=14:7=2

+)x:3=2 suy ra x=6

+)y:7=2 suy ra y=14

Vậy x=6;y=7

1. \(\Rightarrow x-\frac{1}{2}=0\Rightarrow x=\frac{1}{2}\)

2. \(\Rightarrow x-2=1\Rightarrow x=3\)

hoặc \(x-2=-1\Rightarrow x=1\)

3. \(\Rightarrow2x-1=-8\Rightarrow x=\frac{-9}{2}\)

4. \(\Rightarrow x+\frac{1}{2}=\frac{1}{4}\Rightarrow x=\frac{1}{4}\)

hoặc \(x+\frac{1}{2}=\frac{-1}{4}\Rightarrow x=\frac{-3}{4}\)

2)  Ta có: \(\hept{\begin{cases}3x=2y;7y=5z\\x-y+z=32\end{cases}\Rightarrow\frac{x}{2}=\frac{y}{3};\frac{y}{5}=\frac{z}{7}\Rightarrow\frac{x}{10}=\frac{y}{15}=\frac{z}{21}.}\)

                                                                                           \(\Rightarrow\frac{x-y+z}{10-15+21}=\frac{32}{16}=2\)

Vậy \(\hept{\begin{cases}x=2.10=20\\y=2.15=30\\z=2.21=42\end{cases}}\)

Ủng hộ nha m.n

a) Thiếu đề (hoặc sai)

b) x đâu?

c)\(3x-1=x+2\)

\(\Rightarrow3x-x=2+1\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\frac{3}{2}\)

c) \(\frac{x+2}{5}=\frac{2-3x}{3}\)

\(\Rightarrow3.\left(x+2\right)=5.\left(2-3x\right)\)

\(\Rightarrow3x+6=10-15x\)

\(\Rightarrow3x+15x=10-6\)

\(\Rightarrow18x=4\)

\(\Rightarrow x=\frac{4}{18}=\frac{2}{9}\)

câu 1 là \(x\times\left(4.6+\frac{3}{5}\right)=7.2-8.15\)

câu 2 là \(42+\frac{3}{7}.\left[3\times x-1=12\right]\)

\(4^{x+1}.2=32\)

\(4^{x+1}=32:2\)

\(4^{x+1}=16\)

\(4^{x+1}=4^2\)

\(\Rightarrow x+1=2\)

\(\Rightarrow x=1\)

vậy \(x=1\)

\(\left(x-\frac{2}{3}\right)^2=\frac{25}{81}\)

\(\left(x-\frac{2}{3}\right)^2=\left(\frac{5}{9}\right)^2\)

\(\Rightarrow x-\frac{2}{3}=\frac{5}{9}\)

\(\Rightarrow x=\frac{11}{9}\)

vậy \(x=\frac{11}{9}\)

\(500^{300}=\left(500^3\right)^{100}=125000000^{100}\)

\(300^{500}=\left(300^5\right)^{100}\)

vì \(\left(500^3\right)^{100}< \left(300^3\right)^{100}\)nên\(500^{300}< 300^{500}\)

\(4^{45}=\left(4^9\right)^5=262144^5\)

\(3^{60}=\left(3^{12}\right)^5=531441^5\)

vì  \(262144^5< 531441^5\) nên \(4^{45}< 3^{60}\)

Áp dụng tính chất của tỉ lệ thức