\(A=\frac{\left(4^2\right)^{17}.64^{36}}{8^{35}.32^{34}}\)

\(A=\frac{\left(2^4\right)^{17}.\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)

\(A=\frac{2^{68}.2^{216}}{2^{105}.2^{170}}=\frac{2^{284}}{2^{275}}=2^9=512\)

\(a,27^4\cdot81^{10}=\left(3^3\right)^4\cdot\left(3^4\right)^{10}=3^{12}\cdot3^{40}=3^{52}\\ b,=8^{31}\cdot32^5:64^4=\left(2^3\right)^{31}\cdot\left(2^5\right)^5:\left(2^6\right)^4=2^{93}\cdot2^{25}:2^{24}=2^{93+25-24}=2^{94}\)

A=5^10 .9+5^10.7 / 5^9.2^4

A=5^10.(9+7) / 5^9.16

A=5^10.16 /5^9.16

A=5^9.5.16/5^9.16

=>A=5/1

=>A=1

B=2^10.55+2^10. 26 / 2^8 . 27

B=2^10.(55+26) / 2^8 .27

B=2^10.81 / 2^8 .27

B=2^8.2^2.81 / 2^8.27

=>B=2^2.81 / 27

=>B=4.81 / 27

=>B=4.3^3.3 / 3^3

=>B=4.3

=>B=12

Cn phần C thì....mik chưa rõ lém nhưng mak nếu ai cko mik là dzui lém òy......ủng hộ nhoa mina

6 nhaan3 băng2

a) \(2^x=32\)=>\(2^x=2^5\)=>\(x=5\)

b) \(64\times4^x=4^5\)

\(4^3.4^x=4^5\)

\(4^{3+x}=4^5\)

=>\(3+x=5\)

=> x=2

c)\(2^x-15=17\)

\(2^x=17+15\)

\(2^x=32\)

=>\(2^x=2^5\)

=>\(x=5\)

a, 2 mũ x = 32

    2 mũ x = 2 mũ 5

    x = 5

b, 64 x 4 mũ x = 4 mũ 5

    64 x 4 mũ x = 1024

     4 mũ x = 1024 : 64

      4 mũ x = 16

       4 mũ x = 4 mũ 2

       x = 2

   c, 2 mũ x - 15 = 17 

       2 mũ x = 17 + 15

       2 mũ x = 32

       2 mũ x = 2 mũ 5

       x = 5

\(5.3^2-32:4^2\)

\(=5.9-32:16\)

\(=45-2\)

\(=43\)

43

\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)

\(b,\)Tương tự

clgt???

Đặt B =\(32^{17}.8^{19}\)

So sánh :\(A=64^{11}.16^{11}\)và  \(B=32^{17}.8^{19}\)

TA có :\(A=64^{11}.16^{11}=\left(64.16\right)^{11}=1024^{11}=\left(2^{10}\right)^{11}\)\(=2^{110}\)

            \(B=32^{17}.8^{19}=\left(2^5\right)^{17}.\left(2^3\right)^{19}=2^{85}.2^{57}\)\(=2^{142}\)

 VÌ  A < B ( 2¹¹⁰< 2¹⁴²)

 Nên A < 32¹⁷.8¹⁹

2^x = 4³ : 2⁵

2^x = (2²)³ : 2⁵

2^x = 2⁶ : 2⁵

2^x = 2

=> x = 1

viết kiểu gì ko hiểu

$a,$

$2^{20}.15+2^{10}.85$

$=2^{20}.2^{10}.85+15$

$=2^{30}.100$

$=2^{30}{.10}^2$    

$b,$

${27}^{16}:9^{10}$

$=(3^3{)}^{16}:(3^2{)}^{1}0$

$=3^{48}:3^{20}$

$=3^{}$