có ai ko

giúp mk vs

ko bt làm

dng hóng drama

2^x+2^x​⁺¹+2^x+2+2^x​⁺³-480=0

2^x+2^x​.2+2^x.2²+2^x​.2³=0+480

2^x.(1+2+2²+2³)=480

2^x.(1+2+4+8)=480

 2^x.15=480

2^x=480:15

2^x=32=2⁵

Vậy x =5

nếu sai thì thông cảm nha

các anh chị ơi giúp em với ạ

em đang cần gấp

\(S=1+2+2^2+...+2^9\)

\(\Rightarrow2S=2+2^2+2^3+...+2^{10}\)

\(\Rightarrow S=2^{10}-1\)

Lại có \(5.2^8=\left(2^2+1\right).2^8=2^{10}+2^8\)

Vậy \(S< 5.2^8\)

S=1+2+2^2+2^3+...+2^9​

2S=2+2^2+2^3+...+2^9+2^10

2S-S=(2+2^2+2^3+...+2^9+2^10)-(1+2+2^2+2^3+...+2^9)

S=2^10-1

5.2^8=(2^2+1).2^8=(2^2.2^8)+(1.2^8)=2^10+2^8

Vì 2^10-1<2^10+2^8=> S<5.2^8

Vậy S < 5. 2^8

\(S=1+2+2^2+2^3+...+2^{2020}+2^{2021}\)

\(=\left(1+2\right)+\left(2^2+2^3\right)+...+\left(2^{2020}+2^{2021}\right)\)

\(=3+2^2\left(1+2\right)+...+2^{2020}\left(1+2\right)\)

\(=3+2^2.3+...+2^{2020}.3⋮3\)

     VẬY \(S⋮3\)

Trả lời :...........................................

SCSH: (2021 - 1) : 1 = 2020

Tổng: (2021 + 1) : 2 = 1011

Hk tốt,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

k nhé

bạn viết sai đề rồi 2^210=2^2010

\(2A=2.\left(1+2+....+2^{2010}\right)\)

\(2A-A=\left(2+2^2+...+2^{2011}\right)-\left(1+2+...+2^{2010}\right)\)

\(A=2^{2011}-1\)

\(B=2^{2011}-1=>A=B\)

\(S=\frac{3}{2^0}+\frac{3}{2^1}+\frac{3}{2^2}+...+\frac{3}{2^9}\)

\(2S=6+\frac{3}{2^0}+\frac{3}{2^1}+...+\frac{3}{2^8}\)

2S-S=6-\(\frac{3}{2^9}\)

S=\(5\frac{509}{512}\)

CẢM ƠN BẠN

http://123link.pw/j6KCoe

   5⁹⁹ - 4² x 5⁹⁷ - 3² x 5⁹

= 5⁹⁷.(5² - 4²) - 3².5⁹

= 5⁹⁷.(25 - 16) - 3².5⁹

= 5⁹⁷.9 - 9.5⁹