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Supose all of the skewers contain \(6\)meatballs.
Then the number of mearballs used is:
\(6\times32=192\)(meatballs)
In order to have \(150\)meatballs total, the number of skewers have only \(4\)meatballs is:
\(\left(192-150\right)\div\left(6-4\right)=21\)(skewers)
tư vấn à ? tui khuyên bồ nên mở : " Trung tâm tư vấn tình yêu quả sung "
\(linh_1=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}\)
\(linh_1=\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}\right)\)
\(linh_1=\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{4.5}\right)\)
\(linh_1=\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{20}\right)=\dfrac{1}{2}.\dfrac{9}{20}=\dfrac{9}{40}\)
\(linh_2=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}+...+\dfrac{1}{8.9.10}\)
\(linh_2=\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}+...+\dfrac{1}{8.9}-\dfrac{1}{9.10}\right)\)\(linh_2=\dfrac{1}{2}\left(\dfrac{1}{1.2}-\dfrac{1}{9.10}\right)\)
\(linh_2=\dfrac{1}{2}\left(\dfrac{1}{2}-\dfrac{1}{90}\right)=\dfrac{1}{2}.\dfrac{22}{45}=\dfrac{11}{45}\)
a/ \(G=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+\dfrac{1}{3.4.5}\)
\(\Leftrightarrow2G=\dfrac{2}{1.2.3}+\dfrac{2}{2.3.4}+\dfrac{2}{3.4.5}\)
\(\Leftrightarrow2G=\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+\dfrac{1}{3.4}-\dfrac{1}{4.5}\)
\(\Leftrightarrow2G=\dfrac{1}{1.2}-\dfrac{1}{4.5}\)
\(\Leftrightarrow2G=\dfrac{1}{2}-\dfrac{1}{20}\)
\(\Leftrightarrow2G=\dfrac{9}{20}\)
\(\Leftrightarrow G=\dfrac{9}{40}\)
b/ \(H=\dfrac{1}{1.2.3}+\dfrac{1}{2.3.4}+.....+\dfrac{1}{8.9.10}\)
\(\Leftrightarrow2H=\dfrac{2}{1.2.3}+\dfrac{2}{3.4.5}+.....+\dfrac{2}{8.9.10}\)
\(\Leftrightarrow2H=\dfrac{1}{1.2}-\dfrac{1}{2.3}+\dfrac{1}{2.3}-\dfrac{1}{3.4}+.....+\dfrac{1}{8.9}-\dfrac{1}{9.10}\)
\(\Leftrightarrow2H=\dfrac{1}{1.2}-\dfrac{1}{9.10}\)
\(\Leftrightarrow2H=\dfrac{1}{2}-\dfrac{1}{90}\)
\(\Leftrightarrow2H=\dfrac{22}{45}\)
\(\Leftrightarrow H=\dfrac{22}{90}\)
a) 820 và 720
vì 8>7 nên 820>720
b) 420 và 1620
vì 4<16 nên 420<1620
c) 277= (33)7= 321
815=( 34)5=320
vì 21>20 nên 321>320 hay 277> 815
e) 521= 520 . 5
vì 520 . 5>520 . 4 nên 521> 4 . 520
Bài 1 :
a,820 > 720
b, 420 = 1610
c, 277 > 815
d , 554 > 381
e, 521 > 4 . 520
f, 220 > 7.217
a) 820 và 720
\(\Rightarrow\) 820 > 720
b) 420 và 1610
420
1610 = (42)10 = 420
\(\Rightarrow\) 420 = 1610
c) 277 và 815
277 = (33)7 = 321
815 = (34)5 = 320
\(\Rightarrow\) 277 > 815
Ta có :
\(B=3+3^2+3^3+.....+3^{2015}\)
\(\Leftrightarrow3B=3^2+3^3+.........+3^{2015}+3^{2016}\)
\(\Leftrightarrow3B-B=\left(3^2+3^3+.....+3^{2016}\right)-\left(3+3^2+......+3^{2015}\right)\)
\(\Leftrightarrow2B=3^{2016}-3\)
\(\Leftrightarrow2B+3=3^{2016}\)
Lại có : \(2B+3=3^x\)
\(\Leftrightarrow3^{2016}=3^x\Leftrightarrow x=2016\)
Vậy...
1.
a) 15 phút = 1/4 giờ.
b) 30 phút = 1/2 giờ.
c) 45 phút = 3/4 giờ.
d) 20 phút = 1/3 giờ.
e) 40 phút = 2/3 giờ.
g) 10 phút = 1/6 giờ.
h) 5 phút = 1/12 giờ.
2.
A) 3/5 = 15/25.
M) 8/13 = 24/39.
G) -9/12 = -27/36.
T) -7/8 = -28/32.
S) 7/15 = 21/45.
O) 5/7 = 20/28.
Y) -5/9 = -35/63
I) -2/11 = -22/121
C) 3/7 = 36/84.
E) 11/25 = 44/100.
K) 1/4 = 16/64.
N) 6/18 = 18/54.
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