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\(\Leftrightarrow\frac{7}{8}x-5x-\frac{20}{6}x+5-\frac{1,5}{6}=0\)
\(\Leftrightarrow\frac{7}{8}x-5x-\frac{10}{3}x+5-\frac{1}{4}=0\).Giải x
\(\frac{7}{8}x-5.\left(x-9\right)=20x+1\frac{5}{6}\)
\(\frac{7}{8}x-5x+45=20x+\frac{11}{6}\)
\(\frac{7}{8}x-5x-20x=\frac{11}{6}-45\)
\(\frac{-193}{8}x=\frac{-295}{6}\)
\(\Rightarrow x=\frac{1036}{579}\)
cái này ez mà
a,
\(\dfrac{1}{2}x\)\(-3>0\)
\(\Leftrightarrow\dfrac{1}{2}x>3\)
\(\Leftrightarrow x>6\)
b,\(-\dfrac{5}{2}-3\ge0\)
\(-\dfrac{5}{2}\ge3\)
\(x\ge-\dfrac{6}{5}\)
\(\dfrac{7}{8x}-5\left(x-9\right)=20x+\dfrac{1,5}{6}\)
\(\Leftrightarrow7-8x.5\left(x-9\right)=120x+1,5\)
\(\Leftrightarrow7-40x^2+360x=120x+1,5\)
\(\Leftrightarrow-40x^2+360x-120x=7+1,5\)
\(\Leftrightarrow-40x^2+240x=8,5\)
\(\Leftrightarrow40x\left(-x-6\right)=8,5\)
\(\Leftrightarrow\left[{}\begin{matrix}40x=8,5\\-x-6=8,5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{80}\\x=-\dfrac{29}{2}\end{matrix}\right.\)
S\(=\left\{\dfrac{17}{80},\dfrac{-29}{2}\right\}\)
ko hỉu,viết rõ ra ik
\(\Leftrightarrow\frac{7}{8}-5x+45=60x+4,5\Leftrightarrow\frac{7}{8}x-5x-60x=4,5-45\)
\(\Leftrightarrow\frac{-513}{8}x=\frac{81}{2}\Leftrightarrow x=\frac{12}{19}\)
\(\Leftrightarrow\frac{7}{8}x-5x+45=\frac{20}{3}x+0.5\)
\(\Leftrightarrow-\frac{259}{24}x=-44.5\)
\(x=\frac{1068}{259}\)
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