g(1)=1⁶ - 6 x 1⁵ + 6 x 1⁴ - 6 x 1³+ 6 x 1² - 6 x 1 +11

= 1 - 6 + 6 - 6 + 6 - 6 + 11

= 6

bằng 7

Nhớ tick nha !

vòng 11 nha Hoàng Phúc 

bằng 7. Vòng 11 olympic 7 đúng không? Mình làm rồi 7 là đúng đó!

Nhớ tick nha !

( fx) + g(x) + (f(x) - g(x) = 6x^4 - 3x^2 - 5 + 4x^4 - 6x^3 + 7x^2 + 8x - 9 

                                   = 10x^4 +   4x^2  + 8x - 14 

=> 2fx = 2 (  5x^4  + 2 x^2 + 4x - 7)

=> f(x) = 5x^4 + 2x^2 + 4x - 7 

Tính tiếp g(x) nha 

* Trả lời:

\(\left(1\right)\) \(-3\left(1-2x\right)-4\left(1+3x\right)=-5x+5\)

\(\Leftrightarrow-3+6x-4-12x=-5x+5\)

\(\Leftrightarrow6x-12x+5x=3+4+5\)

\(\Leftrightarrow x=12\)

\(\left(2\right)\) \(3\left(2x-5\right)-6\left(1-4x\right)=-3x+7\)

\(\Leftrightarrow6x-15-6+24x=-3x+7\)

\(\Leftrightarrow6x+24x+3x=15+6+7\)

\(\Leftrightarrow33x=28\)

\(\Leftrightarrow x=\dfrac{28}{33}\)

\(\left(3\right)\) \(\left(1-3x\right)-2\left(3x-6\right)=-4x-5\)

\(\Leftrightarrow1-3x-6x+12=-4x-5\)

\(\Leftrightarrow-3x-6x+4x=-1-12-5\)

\(\Leftrightarrow-5x=-18\)

\(\Leftrightarrow x=\dfrac{18}{5}\)

\(\left(4\right)\) \(x\left(4x-3\right)-2x\left(2x-1\right)=5x-7\)

\(\Leftrightarrow4x^2-3x-4x^2+2x=5x-7\)

\(\Leftrightarrow-x-5x=-7\)

\(\Leftrightarrow-6x=-7\)

\(\Leftrightarrow x=\dfrac{7}{6}\)

\(\left(5\right)\) \(3x\left(2x-1\right)-6x\left(x+2\right)=-3x+4\)

\(\Leftrightarrow6x^2-3x-6x^2-12x=-3x+4\)

\(\Leftrightarrow-15x+3x=4\)

\(\Leftrightarrow-12x=4\)

\(\Leftrightarrow x=-\dfrac{1}{3}\)

P(x)-Q(x)

=6x^3+8x^2+5x-2+9x^3-6x^2-2x-3

=15x^3+2x^2+2x-5

\(P\left(x\right)-Q\left(x\right)=\left(6x^3+8x^2+5x-2\right)-\left(-9x^3+6x^2+3+2x\right)\)

                       \(=6x^3+8x^2+5x-2+9x^3-6x^2-3-2x\)

                       \(=6x^3+9x^3+8x^2-6x^2+5x-2x-2-3\)

                       \(=15x^3+2x^2+3x-5\)