a) \(\frac{-8}{x}=\frac{-x}{18}\)

=> x.(-x) = (-8).18

=> -x² = -144

=> x² = 144 => x = \(\pm12\)

b) \(\frac{2x+3}{6}=\frac{x-2}{5}\)

=> 5(2x + 3) = 6(x - 2)

=> 10x + 15 - 6x + 12 = 0

=> 4x + 27 = 0

=> 4x = -27

=> x = -27/4

c) \(\frac{x+1}{22}=\frac{6}{x}\)

=> x(x + 1) = 22.6 = 132

=> x(x + 1) = 11.12

=> x = 11

\(\frac{-8}{x}=\frac{-x}{18}\)

\(\Leftrightarrow-8\cdot18=x\cdot\left(-x\right)\)

\(\Leftrightarrow-144=-x^2\)

\(\Leftrightarrow144=x^2\)

\(\Leftrightarrow\left(\pm12\right)^2=x^2\)

\(\Leftrightarrow\pm12=x\)

\(\frac{2x+3}{6}=\frac{x-2}{5}\)

\(\Leftrightarrow\left(2x+3\right)\cdot5=6\left(x-2\right)\)

\(\Leftrightarrow10x+15=6x-12\)

\(\Leftrightarrow10x-6x=-12-15\)

\(\Leftrightarrow4x=-27\)

\(\Leftrightarrow x=-\frac{27}{4}\)

\(\frac{x+1}{22}=\frac{6}{x}\)

\(\Leftrightarrow\left(x+1\right)x=22\cdot6\)

\(\Leftrightarrow\left(x+1\right)x=132\)

\(\Leftrightarrow\left(x+1\right)x=12\cdot11\)

\(\Leftrightarrow x=11\)

e, \(18x-19=21+8x\)

\(\Rightarrow18x-8x=21+19\)

\(\Rightarrow10x=30\)

\(\Rightarrow x=3\)

Vậy \(x=3\)

g, \(18-4x=-20-6x\)

\(\Rightarrow-4x+6x=-20-18\)

\(\Rightarrow-2x=-38\)

\(\Rightarrow x=19\)

Vậy \(x=19\)

h, \(-15x-24=-7x-32\)

\(\Rightarrow-15x+7x=-32+24\)

\(\Rightarrow-8x=-8\)

\(\Rightarrow x=1\)

Vậy \(x=1\)

i, \(15x-3\left(4x-6\right)=-12+36\)

\(\Rightarrow15x-12x+18=-12+36\)

\(\Rightarrow7x=-12+36-18\)

\(\Rightarrow7x=6\)

\(\Rightarrow x=\frac{6}{7}\)

Vậy \(x=\frac{6}{7}\)

k, \(-10x-27=-7x+33\)

\(\Rightarrow-10x+7x=33+27\)

\(\Rightarrow-3x=60\)

\(\Rightarrow x=-20\)

m, \(-17x-24=-9x-40\)

\(\Rightarrow-17x+9x=-40+24\)

\(\Rightarrow-8x=-16\)

\(\Rightarrow x=2\)

Vậy \(x=2\)

n, \(-23x-25=-18x+75\)

\(\Rightarrow-23x+18x=75+25\)

\(\Rightarrow-5x=100\)

\(\Rightarrow x=-20\)

Vậy \(x=-20\)

p, \(-5x+7\left(2x-3\right)=4\left(x-4\right)\)

\(\Rightarrow-5x+14x-21=4x-16\)

\(\Rightarrow-5x+14x-4x=-16+21\)

\(\Rightarrow5x=5\)

\(\Rightarrow x=1\)

Vậy \(x=1\)

q, \(24-6\left(3x+1\right)=-5\left(4x-4\right)-8\)

\(\Rightarrow24-18x-6=-20x+20-8\)

\(\Rightarrow-18x+20x=20-8-24+6\)

\(\Rightarrow2x=-6\)

\(\Rightarrow x=-3\)

Vậy \(x=-3\)

r, \(18-4\left(6-2x\right)=-3\left(4x+5\right)-11\)

\(\Rightarrow18-24+8x=-12x-15-11\)

\(\Rightarrow8x+12x=-15-11-18+24\)

\(\Rightarrow20x=-20\)

\(\Rightarrow x=-1\)

Vậy \(x=-1\)

s, \(-5\left(4x-5\right)-14=6\left(2-3x\right)-10x-9\)

\(\Rightarrow-20x+25-14=12-18x-10x-9\)

\(\Rightarrow-20x+18x+10x=12-9+14-25\)

\(\Rightarrow8x=-8\)

\(\Rightarrow x=-1\)

Vậy \(x=-1\)

Chúc bạn hok tốt!!! tỷ tỷ

a) \(-\frac{2x}{5}=\frac{-6}{3}\)

\(\Rightarrow-2x.3=-6.5\)

\(\Rightarrow-2x=\frac{-6.5}{3}\)

\(\Rightarrow-2x=-10\)

\(\Rightarrow x=\frac{-10}{-2}\)

\(\Rightarrow x=5\)

b) \(\frac{x-2}{18}=\frac{-1}{6}\)

\(\Rightarrow\left(x-2\right).6=-1.18\)

\(\Rightarrow x-2=\frac{-1.18}{6}\)

\(\Rightarrow x-2=-3\)

\(\Rightarrow x=-3+2\)

\(\Rightarrow x=-1\)

c) \(\frac{x}{14}=\frac{6}{y}=\frac{-15}{35}\)

\(\Rightarrow\left[\begin{matrix}\frac{x}{14}=\frac{-15}{35}\\\frac{6}{y}=\frac{-15}{35}\end{matrix}\right.\Rightarrow\left[\begin{matrix}x.35=-15.14\\6.35=-15.y\end{matrix}\right.\)

\(\Rightarrow\left[\begin{matrix}x=\frac{-15.14}{35}\\y=\frac{6.35}{-15}\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=-6\\y=-14\end{matrix}\right.\)

Vậy \(x=-6;y=-14\)

a) \(\frac{-2x}{5}=-\frac{6}{3}\)

\(\Leftrightarrow-6x=-30\)

\(\Leftrightarrow x=5\)

b) \(\frac{x-2}{18}=-\frac{1}{6}\)

\(\Leftrightarrow-6\left(x-2\right)=-18\)

\(\Leftrightarrow x-2=3\)

\(\Leftrightarrow x=5\)

c) \(\frac{x}{14}=\frac{6}{y}=-\frac{15}{35}\)

\(\Leftrightarrow\frac{x}{14}=\frac{6}{y}=-\frac{3}{7}\)

\(\Leftrightarrow\left\{\begin{matrix}x=-6\\y=-14\end{matrix}\right.\)

a) \(-\frac{42}{18}=-\frac{2x}{-27}\)

\(\Leftrightarrow-\frac{7}{3}=\frac{2x}{27}\)

\(\Leftrightarrow6x=-189\)

\(\Leftrightarrow x=-\frac{63}{2}\left(loại\right)\)

b) \(\dfrac{x}{27}=\dfrac{3}{x}\)

\(\Rightarrow x.x=27.3\)

\(\Rightarrow x^2=81\)

\(\Rightarrow x^2=9^2\)

\(\Rightarrow x=9\)

Vậy x=9