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ko biết *@_$%
đầu hàng luôn !!!!!!!!
5x.5x+1.5x+2 \(\le\)1018 : 218
5x + x + 1 + x + 2 \(\le\) 518
53x + 3 \(\le\)518
3x + 3 \(\le\)18
3x \(\le\)15
x \(\le\)5
Bg
c) 9 < 3x : 3 < 81
=> 32 < 3x - 1 < 34
=> x - 1 = {2; 3; 4}
=> x = {3; 4; 5}
d) 5x . 5x + 1 . 5 x + 2 < 218 . 518 : 218
=> 5x + x + 1 + x + 2 < 218 : 218 . 518
=> 53x + 3 < 1.518
=> 53.(x + 1) < 518
=> 3.(x + 1) < 18
=> x + 1 < 18 : 3
=> x + 1 < 6
=> x < 6 - 1
=> x < 5
c. \(9\le3^x:3\le81\)
\(\Rightarrow3^2\le3^{x-1}\le3^4\)
\(\Rightarrow3^{x-1}\in\left\{3^2;3^3;3^4\right\}\)
\(\Rightarrow x-1\in\left\{2;3;4\right\}\)
\(\Rightarrow x\in\left\{3;4;5\right\}\)
d. Thêm đk : x thuộc N
\(5^x.5^{x+1}.5^{x+2}\le2^{18}.5^{18}:2^{18}\)
\(\Rightarrow5^{x+x+1+x+2}\le5^{18}\)
\(\Rightarrow x+x+x+1+2\le18\)
\(\Rightarrow3x+3\le18\)
\(\Rightarrow3\left(x+1\right)\le18\)
\(\Rightarrow x+1\le6\)
\(\Rightarrow x\le5\)
\(\Rightarrow x\in\left\{1;2;3;4;5\right\}\)
a, <=>(-5)x=(-5)3
<=> x=3
b, <=> 52x=522
<=> x=11
c, 32x=317.315
<=> 32x=332
<=> x=16
d,2x+1=225
<=> x+1=25
<=> x=24
Chúc hok tốt!!!
\(5^x.5^{x+1}.5^{x+2}\le10^{18}:2^{18}\)
\(5^x.5^x.5.5^x.5^2\le5^{18}.2^{18}:2^{18}\)
\(5^{3x}.5^3\le5^{18}\)
\(5^3.5^x.5^3\le5^{18}\)
\(5^x\le5^{18}:5^6\)
\(5^x\le5^{12}\)
\(\Rightarrow x\le12\)
\(\Rightarrow x\in\left\{0,1,2,3,4,5,6,7,8,9,10,11,12\right\}\)
\(x:\left(\frac{-1}{2}-\frac{5}{18}-\frac{1}{3}\right)=x-\left(3-\frac{2}{5}\right)\)
\(=>x:\left(\frac{-9}{18}-\frac{5}{18}-\frac{6}{18}\right)=x-\left(\frac{15}{5}-\frac{2}{5}\right)\)
\(=>x:\left(\frac{-10}{9}\right)=x-\frac{13}{5}\)
\(=>x\cdot\frac{-9}{10}=x-\frac{13}{5}\)
\(=>x\cdot\frac{-9}{10}-x=\frac{-13}{5}\)
\(=>x\cdot\frac{-19}{10}=-\frac{13}{5}\)
\(=>x=\frac{-13}{5}:\frac{-19}{10}\)
\(=>x=\frac{-13}{5}\cdot\frac{10}{-19}\)
\(=>x=\frac{26}{19}\)
\(x:\left(\frac{-1}{2}-\frac{5}{18}-\frac{1}{3}\right)=x-\left(3-\frac{2}{5}\right)\)
\(=>x:\frac{-10}{9}=x-\frac{13}{5}\)
\(=>x\cdot\frac{-9}{10}-x=\frac{-13}{5}\)
\(=>x\cdot\frac{-19}{10}=\frac{-13}{5}\)
\(=>x=\frac{-13}{5}:\frac{-19}{10}\)
\(=>x=\frac{-13}{5}\cdot\frac{10}{-19}\)
\(=>x=\frac{26}{19}\)
\(\Leftrightarrow x:\left(\frac{-9-5-6}{18}\right)=x-\left(\frac{15-2}{5}\right)\)
\(\Leftrightarrow x:\frac{-10}{9}=x-\frac{13}{5}\)
\(\Leftrightarrow\frac{-9x}{10}=\frac{5x-13}{5}\)
\(\Leftrightarrow\frac{-9x}{10}=\frac{10x-26}{10}\)
\(\Leftrightarrow-9x=10x-26\)
\(\Leftrightarrow19x=26\)
\(\Leftrightarrow x=\frac{26}{19}\)
5x.5x+1.5x+2 = 518
⇔53x+3 = 518
⇔3x+3 = 18
⇔3x = 18-3
⇔3x = 15
⇔x = 5
5^x.5^x+1.5^x+2=5^18
=> 5^3x+1+2=5^18
=> 5^3x+3=5^18
=>3x+3=18
=> x=5
vậy....