$\textbf{A}$

$A=\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{(2^2\cdot3)^6+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{(125\cdot7)^3+5^9\cdot14^3}$

$=\dfrac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{12}\cdot3^6+2^{12}\cdot3^5}-\dfrac{5^{10}\cdot7^3-5^{10}\cdot7^4}{5^9\cdot7^3+2^3\cdot5^9\cdot7^3}$

$=\dfrac{2^{12}\cdot3^4(3-1)}{2^{12}\cdot3^5(3+1)}-\dfrac{5^{10}\cdot7^3(1-7)}{5^9\cdot7^3(1+8)}$

$=\dfrac{2}{12}-\dfrac{-30}{9}$

$=\dfrac16+\dfrac{10}{3}$

$=\boxed{\dfrac72}.$

$\textbf{B}$

$B=\dfrac{\left(-\dfrac12\right)^3-\left(\dfrac34\right)^3\cdot(-2)^2}{2\cdot(-1)^5+\left(\dfrac34\right)^2-\dfrac38}$

$=\dfrac{-\dfrac18-\dfrac{27}{64}\cdot4}{-2+\dfrac9{16}-\dfrac38}$

$=\dfrac{-\dfrac18-\dfrac{27}{16}}{-2+\dfrac3{16}}$

$=\dfrac{-\dfrac{29}{16}}{-\dfrac{29}{16}}$

$=\boxed{1}.$

Hãy tích cho tui đi

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THANKS

mình ghi nhầm a = \(\frac{20}{3}\)

a = 20\(\frac{20}{3}\)

b = \(\frac{45}{4}\)

a) \(\frac{1}{7}+\frac{6}{7}:\frac{3}{7}\)

\(=\frac{1}{7}+\frac{6}{7}.\frac{7}{3}\) (nhân nghịch đảo)

\(=\frac{1}{7}+2\)

\(=\frac{15}{7}\)

b) \(\frac{4}{5}-\frac{1}{5}.\left(-3\right)\)

\(=\frac{4}{5}-\left(-\frac{3}{5}\right)\)

\(=\frac{7}{5}\)

c) \(\frac{3}{7}+\left(\frac{-5}{2}\right)-\left(-\frac{3}{5}\right)\)

\(=\frac{3}{7}-\left(-\frac{5}{2}\right)+\frac{3}{5}\)

\(=\frac{30}{70}+\frac{175}{70}+\frac{42}{70}\)

\(=\frac{30+175+42}{70}\)

\(=\frac{247}{70}\)

d) viết lại đề hộ mình nhé

mik ko bít

I don't now

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(12/25)^x=(5/3)^-2-(-3/5)⁴

(12/25)^x=144/625

=> (12/25)^x=(12/25)²

=> x=2

Vậy x=2