1 phần 2 nhân 3 phần 4 cộng 1 phần 2 nhân 1 phần 4 ; 11 phần 3 nhân 26 phần 7 trừ 20 phần 7 nhân 8 phần 30

mày định giết tao à

\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)

\(b,\)Tương tự

$\textbf{a)}$

$\dfrac{2^5\cdot3^{12}\cdot7^8}{2^7\cdot3^{10}\cdot7^9}$

$=\dfrac{3^{12-10}}{2^{7-5}\cdot7^{9-8}}$

$=\dfrac{3^2}{2^2\cdot7}$

$=\dfrac{9}{28}.$

co ai giai dc ko cau 60 % .....

$\textbf{Ta có:}$

$A=\dfrac{-5^2-5\cdot3^2}{5^3+5^2\cdot3^2}$

$=\dfrac{-25-45}{125+225}$

$=\dfrac{-70}{350}$

$=-\dfrac15.$

Và

$B=\dfrac{2^{12}\cdot3^{10}+6^9\cdot120}{2^{12}\cdot3^{12}-2^{11}\cdot3^{11}}$

$=\dfrac{2^{12}3^{10}+2^{12}3^{10}\cdot5}{2^{11}3^{11}(2\cdot3-1)}$

$=\dfrac{2^{12}3^{10}(1+5)}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^{12}3^{10}\cdot6}{2^{11}3^{11}\cdot5}$

$=\dfrac{2^2}{5}$

$=\dfrac45.$

=> $M=B-A$$=\dfrac45-\left(-\dfrac15\right)$

$=\dfrac55$$=1.$

\(4^2\cdot120-4^3\cdot17+4^2\cdot34\)

\(=4^2\left(120-4\cdot17+34\right)\)

\(=16\left(120-68+34\right)\)

\(=16\cdot86=1088\)

\(7^3\cdot9+3^2\cdot7^4-45\cdot539\)

\(=7^3\cdot9+9\cdot7^4-45\cdot7^2\cdot11\)

\(=7^2\left(7\cdot9+9\cdot7^2-45\cdot11\right)\)

\(=49\left(63+9\cdot49-495\right)\)

\(=49\left(63+441-495\right)\)

\(=49\cdot9=441\)

65536

387420489

33554432

536870912

390625

6561

2⁴ . 2⁶ . 2 = 2¹¹

3⁵ . 27 . 81 . 3⁶ = 3⁵ . 3³ . 3⁴ . 3⁶ = 3¹⁸

4² . 4¹⁵ . 64 = 4² . 4¹⁵ . 4³ = 4²⁰

2⁹ . 16 . 4⁸ = 2⁹ . 2⁴ . (2²)⁸ = 2⁹ . 2⁴ . 2¹⁶ = 2²⁹

5¹² : 5⁴ = 5⁸

27⁴ : 3⁴ = (27:3)⁴ = 9⁴

a ) 4⁵ . 4 . 4⁷ = 4⁵ . 4¹ . 4⁷ = 4¹³

b ) 4 . 4³ . 4⁵ . 4⁶ = 4¹ . 4³ . 4⁵ . 4⁶ = 4¹⁵

c ) x . x³ . x⁴ = x¹ . x³ . x⁴ = x⁸

d ) x⁵ . x⁴ . x⁷ . x⁶ = x²²

= 2031250 x 62145792 x 0

= 0

$(5^7+5^9)(6^8+6^{10})(2^4-4^2)$

$=5^7(1+5^2)\cdot6^8(1+6^2)\cdot(16-16)$

$=5^7\cdot26\cdot6^8\cdot37\cdot0$

$=0.$

mấy mũ 6 đấy bạn?