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Biểu thức 1
$A=3\dfrac12\cdot\dfrac4{49}\cdot\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{5}\right)$
$=\dfrac72\cdot\dfrac4{49}\cdot\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\dfrac5{-42}$
$=\dfrac72\cdot\dfrac4{49}\cdot6\cdot\dfrac5{-42}$
$=\dfrac{12}{7}\cdot\dfrac5{-42}$
$=\dfrac{60}{-294}$
$=-\dfrac{10}{49}.$
Biểu thức 2
$B=\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot1\dfrac13\right):\dfrac43$
$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac43\right):\dfrac43$
$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac{8}{15}\cdot\dfrac34$
$=\dfrac{10}{81}\cdot\dfrac{99}{250}-\dfrac25$
$=\dfrac{11}{225}-\dfrac{90}{225}$
$=-\dfrac{79}{225}.$
a) \(10,\left(3\right)+0,\left(4\right)-8,\left(6\right)\)
\(=\frac{31}{3}+\frac{4}{9}-\frac{26}{3}\)
\(=\left(\frac{31}{3}-\frac{26}{3}\right)+\frac{4}{9}=\frac{5}{3}+\frac{4}{9}=\frac{15}{9}+\frac{4}{9}=\frac{19}{9}\)
b) \(\left[12,\left(1\right)-2,3\left(6\right)\right]:4,\left(21\right)\)
\(=\left[\frac{109}{9}-\frac{71}{30}\right]:\frac{139}{33}\)
\(=-\frac{52}{45}:\frac{139}{33}=-\frac{52}{45}\cdot\frac{33}{139}=-\frac{572}{2085}\)(số xấu quá)
c) \(3\frac{1}{2}\cdot\frac{4}{49}-\left[2,\left(4\right)\cdot2\frac{5}{11}\right]:\frac{-42}{53}\)
\(=\frac{7}{2}\cdot\frac{4}{49}-\left[\frac{22}{9}\cdot\frac{27}{11}\right]\cdot\frac{-53}{42}\)
\(=\frac{2}{7}-6\cdot\left(-\frac{53}{42}\right)=\frac{2}{7}-\left(-\frac{53}{7}\right)=\frac{2}{7}+\frac{53}{7}=\frac{55}{7}\)
$\textbf{a)}$
$\left(-\dfrac34+\dfrac27\right):\dfrac27+\left(-\dfrac14+\dfrac57\right):\dfrac23$
$=\left(-\dfrac{13}{28}\right)\cdot\dfrac72+\dfrac{13}{28}\cdot\dfrac32$
$=-\dfrac{13}{8}+\dfrac{39}{56}$
$=-\dfrac{13}{14}.$
$\textbf{b)}$
$\left(-\dfrac13\right)^2\cdot\dfrac4{11}+\dfrac7{11}\cdot\left(-\dfrac13\right)^2$
$=\dfrac19\left(\dfrac4{11}+\dfrac7{11}\right)$
$=\dfrac19.$
$\textbf{A}$
$A=\dfrac{2^{12}\cdot3^5-4^6\cdot9^2}{(2^2\cdot3)^6+8^4\cdot3^5}-\dfrac{5^{10}\cdot7^3-25^5\cdot49^2}{(125\cdot7)^3+5^9\cdot14^3}$
$=\dfrac{2^{12}\cdot3^5-2^{12}\cdot3^4}{2^{12}\cdot3^6+2^{12}\cdot3^5}-\dfrac{5^{10}\cdot7^3-5^{10}\cdot7^4}{5^9\cdot7^3+2^3\cdot5^9\cdot7^3}$
$=\dfrac{2^{12}\cdot3^4(3-1)}{2^{12}\cdot3^5(3+1)}-\dfrac{5^{10}\cdot7^3(1-7)}{5^9\cdot7^3(1+8)}$
$=\dfrac{2}{12}-\dfrac{-30}{9}$
$=\dfrac16+\dfrac{10}{3}$
$=\boxed{\dfrac72}.$
$\textbf{B}$
$B=\dfrac{\left(-\dfrac12\right)^3-\left(\dfrac34\right)^3\cdot(-2)^2}{2\cdot(-1)^5+\left(\dfrac34\right)^2-\dfrac38}$
$=\dfrac{-\dfrac18-\dfrac{27}{64}\cdot4}{-2+\dfrac9{16}-\dfrac38}$
$=\dfrac{-\dfrac18-\dfrac{27}{16}}{-2+\dfrac3{16}}$
$=\dfrac{-\dfrac{29}{16}}{-\dfrac{29}{16}}$
$=\boxed{1}.$
$\textbf{a)}$
$4\cdot\left(\dfrac14\right)^2+25\cdot\left[\left(\dfrac34\right)^3:\left(\dfrac54\right)^3\right]:\left(\dfrac32\right)^3$
$=\dfrac14+25\cdot\left(\dfrac35\right)^3:\left(\dfrac32\right)^3$
$=\dfrac14+25\cdot\dfrac{27}{125}\cdot\dfrac8{27}$
$=\dfrac14+\dfrac85$
$=\dfrac{5+32}{20}$
$=\boxed{\dfrac{37}{20}}.$
$\textbf{b)}$
$2^3+3\cdot\left(\dfrac12\right)^0+(-1)+\left[(-2)^2:\dfrac12\right]-8$
$=8+3\cdot1-1+\dfrac4{1/2}-8$
$=8+3-1+8-8$
$=\boxed{10}.$
Cũng khuya rồi , mình làm câu 1 thôi nhé !
\(\frac{2.5^{22}-9.5^{21}}{25^{10}}=\frac{2.5^{22}-9.5^{21}}{\left(5^2\right)^{10}}\)
\(\frac{5^{21}.\left(2.5-9\right)}{5^{20}}=5.\left(10-9\right)=5\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
Biểu thức 1
$3\dfrac12\cdot\dfrac4{49}-\left(2,(4)\cdot2\dfrac5{11}\right):\left(-\dfrac{42}{8}\right)$
$=\dfrac72\cdot\dfrac4{49}-\left(\dfrac{22}{9}\cdot\dfrac{27}{11}\right)\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27-6\cdot\left(-\dfrac4{21}\right)$
$=\dfrac27+\dfrac87$
$=\dfrac{10}{7}.$
Biểu thức 2
$\left[0,(5)\cdot0,(2)\right]:\left(3\dfrac13:\dfrac{33}{25}\right)-\left(\dfrac25\cdot3\dfrac13\right):\dfrac43$
$=\left(\dfrac59\cdot\dfrac29\right):\left(\dfrac{10}{3}:\dfrac{33}{25}\right)-\left(\dfrac25\cdot\dfrac{10}{3}\right):\dfrac43$
$=\dfrac{10}{81}:\dfrac{250}{99}-\dfrac43\cdot\dfrac34$
$=\dfrac{10}{81}\cdot\dfrac{99}{250}-1$
$=\dfrac{11}{225}-1$
$=-\dfrac{214}{225}.$