Ta có 19/18=1+1/18

        2005/2004=1+1/2004

Vì 1/18>1/2004 nên 1+1/18 >1/2004 +1 hay 19/18>2005/2004

1. Ta có: \(\frac{19}{18}>\frac{18}{18}=1=\frac{2005}{2005}>\frac{2004}{2005}\)

hay: 19/18 > 1 > 2004/2005

Vậy 19/18 > 2004/2005

2. \(\frac{3}{6}=\frac{1}{2}=\frac{7}{14};\frac{2}{7}=\frac{4}{14};\frac{4}{7}=\frac{8}{14}\)

Vì 4/14 < 7/14 < 8/14

nên: 2/7 < 3/6 < 4/7.

3. \(\frac{12}{25};\frac{9}{5}=\frac{45}{25};\frac{3}{5}=\frac{15}{25};\frac{1}{25}\)

Vì 45/25 > 15/25 > 12/25 > 1/25

nên: 9/5 > 3/5 > 12/25 > 1/25

4. \(\frac{35}{42}+\frac{14}{42}=\frac{35+14}{42}=\frac{49}{42}\)

5. \(\frac{6}{16}+\frac{32}{16}=\frac{6+32}{16}=\frac{38}{16}=\frac{19}{8}\).

\(\frac{1}{4}+\frac{3}{5}=\frac{17}{20}\)

\(\frac{5}{2}+\frac{7}{9}=\frac{59}{18}\)

\(\frac{3}{2}+\frac{2}{3}=\frac{13}{6}\)

\(\frac{4}{5}+\frac{3}{2}=\frac{23}{10}\)

\(\frac{4}{5}+\frac{3}{15}=\frac{4}{5}+\frac{1}{5}=1\)

\(\frac{2}{3}+\frac{32}{24}=\frac{2}{3}+\frac{4}{3}=2\)

\(\frac{5}{6}+\frac{15}{18}=\frac{5}{6}+\frac{5}{6}=\frac{10}{6}=\frac{5}{3}\)

\(\frac{8}{15}+\frac{2}{3}=\frac{8}{15}+\frac{10}{15}=\frac{18}{15}=\frac{6}{5}\)

\(\frac{3}{7}+\frac{4}{8}=\frac{24}{56}+\frac{28}{56}=\frac{52}{56}=\frac{13}{14}\)

_HT_

Murad trả lời đúng rồi đó! 

= ps bn z bn

Trả lời :

Đề thiếu bạn ơi 

@ bạn gửi lại đề nhé @

# chúc bạn học tốt ạ #

c1

a,3/15 = 3:3/15:3  = 15 

33/44 = 33:11/44:11 = 34 

2/8 = 2:2/8:2 = 1/4 

b,9/12 =9:3/12:3  = 34 

24/36 =24:12/36:12 = 23 

3/8 = 3:1/8:1 = 3/8 

c2

a) =12x(4+6)/24

= 12x10/24

=120/24

=5

b,16x8-16x2/12x4

=16x(8-2)/48

=16x6/48

=2

c3

5/8=45/72

20/15=4/3=96/72

24/32=3/4=54/72

15/18=5/6=60/72

77/99=7/9=56/72

c4

2/3=2/3

12/15=4/5

24/18=4/3

16/48=1/3

75/100=3/4

30/45=2/3

12/36=1/3

20/15=4/3

các phân số lớn hơn 1 luôn có mẫu số bé hơn tử số 

vậy các số lớn hơn 1 là  24/18,20/15

k mk nha thank mọi ng'

a, \(\frac{3}{15}=\frac{1}{5}=\frac{4}{20}\);   \(\frac{33}{44}=\frac{3}{4}=\frac{15}{20}\);       \(\frac{2}{8}=\frac{1}{4}=\frac{5}{20}\)

b, \(\frac{9}{12}=\frac{3}{4}=\frac{18}{24}\);     \(\frac{24}{36}=\frac{2}{3}=\frac{16}{24}\);      \(\frac{3}{8}=\frac{9}{24}\)

Bài 2 :

a,\(\frac{12x4+12x6}{24}=\frac{12x\left(4+6\right)}{24}=\frac{1x10}{2}=\frac{10}{2}=\frac{5}{1}\)

b, \(\frac{16x8-16x2}{12}=\frac{16x\left(8-2\right)}{12}=\frac{8x6}{6}=\frac{8}{1}\)

chịu mình không thể giải được

Mấy con gà lắt nhắt này, dễ thế mà cũng ko tính đc.

             \(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\)

         = \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+....+\frac{1}{512}-\frac{1}{1024}\)

        =  \(1-\frac{1}{1024}\)

       = \(\frac{1023}{1024}\)

k mình nha các bạn

\(A=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}.\)

\(A+\frac{1}{64}=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{64}\)

\(A+\frac{1}{64}=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{32}\)

\(A+\frac{1}{64}=\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{16}=...=\frac{1}{2}\)

\(A=\frac{1}{2}-\frac{1}{64}=\frac{31}{64}.\)

\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)

\(=\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+\left(\frac{1}{8}-\frac{1}{16}\right)+\left(\frac{1}{16}-\frac{1}{32}\right)+\left(\frac{1}{32}-\frac{1}{64}\right)\)

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}\)

\(=\frac{1}{2}-\frac{1}{64}=\frac{31}{64}\)

a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)

\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)

b)\(5+\dfrac{3}{5}=\dfrac{25}{5}+\dfrac{3}{5}=\dfrac{28}{5};10-\dfrac{9}{16}=\dfrac{160}{16}-\dfrac{9}{16}=\dfrac{151}{16}\)

\(\dfrac{2}{3}-\left(\dfrac{1}{6}+\dfrac{1}{8}\right)=\dfrac{2}{3}-\left(\dfrac{8}{48}+\dfrac{6}{48}\right)=\dfrac{2}{3}-\dfrac{14}{48}=\dfrac{32}{48}-\dfrac{14}{48}=\dfrac{3}{8}\)