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2^x +2^x+3 =144

» 2^x .1+2^x.  2^3 =144

»2^x.  (1+2^3) =144

»2^x. 9=144

» 2^x =16

» x=4

2^x + 2^{x + 3} = 144

2^x . 1 + 2^x . 2³ = 144

2^x . (1 + 8) = 144

2^x . 9 = 144

2^x = 16 = 2⁴

=> x = 4

Sửa lại 

<=>2^x+2^x.2³=144

<=>2^x(1+2³)=144

<=>2^x.9=144

<=>2^x=144:9=16=2⁴

=>x=4

<=>2^x+2^x.2³=144

<=>2^x(1+2³)=144

<=>2^x.9=144

<=>2^x=144:9=16=2⁴

=>x=4

\(2^x+2^{x+3}=144\)

\(\Leftrightarrow2^x+2^x.2^3=144\)

\(\Leftrightarrow2^x+2^x.8=144\)

\(\Leftrightarrow2^x.\left(1+8\right)=144\)

\(\Leftrightarrow2^x.9=144\)

\(\Leftrightarrow2^x=16\)\(\Leftrightarrow2^x=2^4\)

\(\Leftrightarrow x=4\)

Vậy \(x=4\)

2^x. 2^x-3= 144

=> 2^x . 2^x.\(\dfrac{1}{8}\)= 144

=> 2^x. \(\left(1+\dfrac{1}{8}\right)\)= 144

=> 2^x . \(\dfrac{9}{8}\) = 144

=> 2^x =128

=> x =7

uk cam on nhieu

Đặt \(\frac{x}{2}=\frac{y}{3}=k\)

=>x=2k; y=3k

\(xy^2=144\)

=>\(2k\cdot\left(3k\right)^2=144\)

=>\(2k\cdot9k^2=144\)

=>\(18k^3=144\)

=>\(k^3=8=2^3\)

=>k=2

=>\(\begin{cases}x=2\cdot2=4\\ y=3\cdot2=6\end{cases}\)

a) \(3^x+3^{x+2}=810\)

\(=>3^x+3^x\cdot9=810\)

\(=>3^x\left(1+9\right)=810\)

\(=>3^x\cdot10=810\)

\(=>3^x=810:10=81\)

\(=>3^x=3^4\)

\(=>x=4\)

a) \(3^x+3^{x+2}=810\)

\(\Leftrightarrow3^x\left(1+3^2\right)=810\)

\(\Leftrightarrow3^x\cdot10=810\)

\(\Leftrightarrow3^x=81\)

\(\Leftrightarrow x=4\)

b)\(2^x+2^{x+3}=144\)

\(\Leftrightarrow2^x\left(1+2^3\right)=144\)

\(\Leftrightarrow2^x\cdot9=144\)

\(\Leftrightarrow2^x=16\)

\(\Leftrightarrow x=4\)

2^x+2^x+3=144

2^x(1+2³)=144

2^x.9=144

2^x=16

2^x=2⁴

x=4

2^x+2^x+3=144

2^x.1+2^x.2³=144

2^x.(1+2³)=144

2^x.9=144

2^x=16

2^x=2⁴

=>x=4

a)  \(\left(x-\frac{3}{5}\right)^2=4\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x-\frac{3}{5}=2\\x-\frac{3}{5}=-2\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{13}{5}\\x=-\frac{7}{5}\end{cases}}\)

Vậy...

b)     \(2^x+2^{x+3}=144\)

\(\Leftrightarrow\)\(2^x.\left(1+2^3\right)=144\)

\(\Leftrightarrow\)\(2^x=16=2^4\)

\(\Leftrightarrow\)\(x=4\)

Vậy....

a) \(\left(x-\frac{3}{5}\right)^2=4\)

\(\Leftrightarrow\left(x-\frac{3}{5}\right)^2=\left(\pm2\right)^2\)

Xét : TH1 :x - 3/5 = 2

<=> x = 2 + 3/5

<=> x = 13/5

TH2 : x - 3/5 = -2

<=> x = - 2 + 3/5

<=> x = -7/5

Vậy ...

b ) 2^x + 2^x+3 = 144

<=> 2^x + 2^x . 2³ = 144

<=> 2^x ( 1 + 2³ ) = 144

<=> 2^x . 9 = 144

<=> 2^x = 16

<=> x = 4

Vậy ..