Khó nhìn qá bn à

a) (2x-1)⁴ = 16

=> (2x-1)⁴ = 2⁴ hoặc (-2)⁴

=>\(\left[{}\begin{matrix}2x-1=2\\2x-1=-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=2+1\\2x=-2+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{-1}{2}\end{matrix}\right.\)

b) (2x+1)⁴ = (2x+1)⁶

=> (2x+1)⁴ = (2x+1)⁴⁺²

=> (2x+1)⁴ = (2x+1)⁴ . (2x+1)²

=> (2x+1)⁴ - (2x+1)⁴ . (2x+1)² = 0

=> (2x+1)^{4 .} [1 - (2x+1)²] = 0

\(\left[{}\begin{matrix}\left(2x+1\right)^4=0\\1-\left(2x+1\right)^2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x+1=0\\2x+1=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{-1}{2}\\x=0\end{matrix}\right.\)

2(x - 1) - 3(2x + 2) - 4(2x + 3) = 16

2x - 2 - 6x + 6 - 8x + 12 = 16

(2x - 6x - 8x) - (2 + 6 + 12) = 16

(-12) . x - 20 =16 

(-12) . x = 16 + 20 = 36

x = 36 : (-12) = -3

 2 (x+1) -3 (2x+2) -4(2x+3)=16

2x+2-6x-6-8x-12=16

2x-6x-8x=16-2+6+12

-12x=32

x=32/-12

x=-2

<=> 2x+2-6x-6-8x-12=16

<=> -12x =32

<=> x=32;(-12)=-8/3

Vậy x=-8,3

a) \(2x\left(3x+1\right)+3x\left(4-2x\right)=7\)

\(\Rightarrow6x^2+2x+12x-6x^2=7\)

\(\Rightarrow14x=7\Rightarrow x=\frac{1}{2}\)

b) \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)

\(72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow-20x-36x-30x+6x=-240-84-72-84\)

\(-80x=-480\)

x = 6

c) \(\left(3x+2\right).\left(2x+9\right)-\left(x+2\right).\left(6x+1\right)=\left(x+1\right)-\left(x-6\right)\)

\(\Rightarrow6x^2+4x+27x+18-6x^2-12x-x-2=x+1-x+6\) ( chỗ này bn tự phân tích ik nha, mk chỉ đưa ra kp sau khi phân tích thôi, ko thì viết ra dài lắm)

\(\Rightarrow18x+16=7\)

18x = -9

x = -2

18x = 

a: \(\Leftrightarrow6x^2+2x+12x-6x^2=7\)

=>14x=7

hay x=1/2

b: \(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)

=>-56x+156=24x-324

=>-80x=-480

hay x=6

c: \(\Leftrightarrow6x^2+27x+4x+18-6x^2-x-12x-2=x+1-x+6=7\)

=>18x+16=7

=>18x=-9

hay x=-1/2